TW201122503A - Failure locating method. - Google Patents
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201122503201122503
【發明所屬之技術領域】 本發明是有關於一種輸電線的摘測技術’特別是指一 種故障定位方法。 【先前技術】 電力佈局上,通常是以一輸電線來聯繫兩個變電器, 因此輸電線品質的維持是有效供電的先決條件。當供電不 穩定,系統大都要求在所傳電力信號的3〜5個週期内就找 • 出輸電線的故障位置,以儘快排除障礙。 習知一種故障定位法,是先測量該輸電線而得知所傳 電力信號的電壓與電流,再藉由離散傅利葉轉換(DFT, Discrete Fourier Transform)對電壓與電流分別進行濾波來取 出基頻相量(phasor),最後再就「電塵相1之於電流相量的 相對關係」與「輸電線的特徵阻抗」做比較’來分析出故 障位置。 然而,這種定位法主要建立在穩態相量的基礎上。但 φ 發生故障後,DFT算出的相量除了穩態成分’通常也挾帶 著暫態成分(如:衰減直流成分),使得故障定位的精確度大 受影響。為此,C. S. Yu在2006 transform based adaptive mimic phasor estimator for distance relaying applications,” IEEE Trans. Power Delivery, 以妨中提出改良式的DFT架構,企圖 移除其中的衰減直流成分,只是計算成本大幅地超出預期 201122503 【發明内容】BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to a technique for extracting power lines, and more particularly to a method of fault location. [Prior Art] In the power layout, two power transformers are usually used to contact two power transformers, so the maintenance of the quality of the power lines is a prerequisite for effective power supply. When the power supply is not stable, most of the systems require that the fault location of the power transmission line be found within 3 to 5 cycles of the transmitted power signal to remove the obstacle as soon as possible. A fault location method is known in which the power line is first measured to know the voltage and current of the transmitted power signal, and then the voltage and current are separately filtered by Discrete Fourier Transform (DFT) to extract the fundamental frequency phase. The amount of phasor is finally analyzed by comparing the relative relationship between the electric dust phase 1 and the current phasor and the characteristic impedance of the power line. However, this positioning method is mainly based on the steady state phasor. However, after φ fails, the phasor calculated by DFT, in addition to the steady-state component, usually carries transient components (such as attenuating DC components), which greatly affects the accuracy of fault location. To this end, CS Yu in 2006 transform based adaptive mimic phasor estimator for distance relaying applications," IEEE Trans. Power Delivery, in order to propose an improved DFT architecture, in an attempt to remove the attenuated DC components, but the computational cost is significantly exceeded Expected 201122503 [Summary of the Invention]
At因此,本發明之目的,即在提供一種故障定位方法, ::系統要求的時間内提供輸電線上發生故障的位置,不 仁疋位精確度高,也能有效控制計算成本。 於是,本發明故障定位方法,適用於為聯繫一第一變 電:和-第二變電器間的一輸電線,計算出一故障位置, 包含以下步驟:(A)分別量測於該第一變電器處的一第一參 考電壓與一第一參考電流和該第二變電器處的一第二參考 電壓與帛一參考電流;⑻設定一故障參數的初始值,該 故障參數是該故障位置與該第二變電器的距離之於該輸電 線總長的比例;(C)基於該輸電線的一總長、一特徵阻抗和 一傳播常數以及該故障參數,得到一第一組阻抗,該第一 組阻抗表示了位於該故障位置與該第一變電器之間的該輸 電線的等效電路模型;(D)利用該第一參考電壓和該第一參 考電"U·和該第一組阻抗得到一第一故障電壓;(E)基於該輸 電線的總長、該特徵阻抗和該傳播常數以及該故障參數, 得到一第二組阻抗,該第二組阻抗表示了位於該故障位置 與該第一變電器之間的輸電線的等效電路模型;(F)利用該 第二參考電壓、該第二參考電流和該第二組阻抗得到一第 一故障電壓,(G)計算該第一、第二故障電壓的差值,並利 用該差值來更新該故障參數,並基於更新後的故障參數重 複步驟(C)~(G) ’直到更新後的故障參數使該第一、第二故 障電壓趨於接近·’及(H)利用更新完成的該故障參數求出該 201122503 故障位置。 -而本發明故障定位方法,適用於為聯繫一第一變電器 和一第二變電器間的一輸電線,計算出一故障位置,包含 以下步驟:(A)分別量測於該第一變電器處的一第一參考電 麼與一第一參考電流和該第二變電器處的一第二參考電壓 與一第二參考電流;(Β)基於該輸電線的一總長、一特徵阻 抗矛 傳播*數,得到一組因子’該組因子表示了位於該 故障位置與該第一變電器之間的該輸電線的等效阻抗相對 籲 於一故障參數的比例,且該故障參數是該故障位置與該第 二變電器的距離之於該輸電線總長的比例;(c)基於該等參 考電Μ、該等參考電流以及該組因子,計算出滿足一第一 故障電壓等於一第二故障電壓的故障參數,其中該第一故 障電壓是指該故障位置處基於該第一參考電壓的電壓,該 第二故障電壓是指該故障位置處基於該第二參考電壓的電 壓;及(D)利用該故障參數求出該故障位置。 • 【實施方式】 有關本發明之前述及其他技術内容、特點與功效,在 以下配合參考圖式之二個較佳實施例的詳細說明中’將可 清楚的呈現。 在本發明被詳細描述之前,要注意的是,在以下的說 明内容中’類似的元件是以相同的編號來表示。 第一較佳實施例之原理介紹與推導 參閱圖1,其繪示了 一個二端點的三相電力系統100。 201122503 坆-端點疋指分處兩地的第-變電器1和第二變電器2,會 藉由:總長W的輸電線3來傳遞三個分別具有不同相位的 號。在進行輸電線3的故障定位時,為了同步地取 仔这些電力信號於料變電器卜2處的電壓與電流,較佳 地會配合一全球定位衛星(GPS)系統200來監測。 而根據 J. J. Grainger 和 W.D. Stevens〇n 於〜赠 System Analysis, New York .. McGraw-mu,】994 中的介绍, 可知.就其中-電力信號來說,假設故障位置F發生在與 變電器2距離dW處’那麼輸電線3於變電器【到此故障位 置F間會等效形成如圖2所示的第—組阻抗,其+故障參 數d代表「故障位置F與變電器2的距離」之於「該輸電 線總長j的比例,。 第一組阻抗包括一個第一阻抗21(旬及二個第二阻抗 Yl(d),且該等值會隨著故障參數d改變。第一阻抗ζι(句跨 接於變電器1與故障位置FPb1,而各第二阻抗γι⑷則是轉 接其中一跨接處與接地點。詳細參數定義如下:At the present end, the object of the present invention is to provide a fault location method, the location required to be faulty on the transmission line within the time required by the system, and the high accuracy of the non-defective position can also effectively control the calculation cost. Therefore, the fault location method of the present invention is adapted to calculate a fault location for contacting a power line between the first power transformer and the second power transformer, and includes the following steps: (A) separately measuring the first a first reference voltage at the transformer and a first reference current and a second reference voltage at the second power transformer and a first reference current; (8) setting an initial value of a fault parameter, the fault parameter is the fault location a ratio of the distance from the second power transformer to the total length of the power line; (C) obtaining a first set of impedances based on a total length of the power line, a characteristic impedance and a propagation constant, and the fault parameter, the first The group impedance represents an equivalent circuit model of the power line between the fault location and the first power transformer; (D) utilizing the first reference voltage and the first reference power "U· and the first group The impedance obtains a first fault voltage; (E) obtaining a second set of impedances based on the total length of the power line, the characteristic impedance and the propagation constant, and the fault parameter, the second set of impedances indicating that the fault location is located First An equivalent circuit model of the power line between the transformers; (F) using the second reference voltage, the second reference current, and the second set of impedances to obtain a first fault voltage, (G) calculating the first, The difference between the second fault voltage, and using the difference to update the fault parameter, and repeating steps (C)~(G)' based on the updated fault parameter until the updated fault parameter causes the first fault and the second fault The voltage tends to approach '' and (H) to find the 201122503 fault location using the fault parameter completed by the update. - The fault location method of the present invention is adapted to calculate a fault location for contacting a power line between a first power transformer and a second power transformer, comprising the steps of: (A) separately measuring the first change a first reference voltage at the electrical device and a first reference current and a second reference voltage at the second power transformer and a second reference current; (Β) based on a total length of the power line, a characteristic impedance spear Propagating * number, obtaining a set of factors 'The set of factors represents the ratio of the equivalent impedance of the power line between the fault location and the first power transformer relative to a fault parameter, and the fault parameter is the fault a ratio of a distance from the second power transformer to a total length of the power line; (c) calculating, based on the reference power, the reference current, and the set of factors, that satisfying a first fault voltage is equal to a second fault a fault parameter of the voltage, wherein the first fault voltage is a voltage based on the first reference voltage at the fault location, and the second fault voltage is a voltage based on the second reference voltage at the fault location; and D) obtains the parameters of the fault using a fault location. The above and other technical contents, features and effects of the present invention will be apparent from the following detailed description of the preferred embodiments of the accompanying drawings. Before the present invention is described in detail, it is to be noted that in the following description, similar elements are denoted by the same reference numerals. Principles and Derivations of the First Preferred Embodiment Referring to Figure 1, a two-terminal three-phase power system 100 is illustrated. 201122503 坆-Endpoint 第 refers to the first-variable transformer 1 and the second transformer 2 in two places, which will transmit three numbers with different phases by the transmission line 3 of the total length W. In order to locate the faulty location of the power line 3, in order to synchronously take the voltage and current of the power signal at the material transformer 2, it is preferably monitored in conjunction with a Global Positioning Satellite (GPS) system 200. According to the introduction of JJ Grainger and WD Stevens〇n in System Analysis, New York .. McGraw-mu, 994, it can be seen that for the power signal, the fault location F is assumed to be at the distance from the transformer 2. At dW, then the power line 3 is in the transformer [to the fault position F will form the first group impedance as shown in Figure 2, and the + fault parameter d represents the "distance of the fault location F and the transformer 2". The ratio of the total length of the transmission line, j. The first set of impedances includes a first impedance 21 (one and two second impedances Y1(d), and the value changes with the fault parameter d. The first impedance is ζι (The sentence is connected to the transformer 1 and the fault location FPb1, and each of the second impedances γι(4) is one of the bridges and the grounding point. The detailed parameters are defined as follows:
Zl(d ) = Zc- sinh(^(l -d)w)Zl(d) = Zc- sinh(^(l -d)w)
Zc { 2 ) (1) 其中,Zc為該輸,線f的特徵阻抗,y為該輸電線3的 傳播常數,且。 2 ex + e~x 請注意,除了相位差.異外,輸電線3傳送之三個電力 信號具有相同的電壓絕對值,以及相同的電流絕對值,因 此分析各電力信號後所對應到的等效電路會包括同樣的阻 抗元件值。所以,利用前述相關其中一電力信號的電路模 201122503 型來探討故障位置F,即已足夠。 進一步地,第一阻抗Zl(d)還可等效為一電阻Ri(d)串 接一電感Ll(d),第二阻抗Yl(d)也可等效為一電導Gl(d)並 聯一電容Cl(d),即: Z\{d) = R\{d)^ jQ\L\{d)Zc { 2 ) (1) where Zc is the characteristic impedance of the input, line f, and y is the propagation constant of the transmission line 3, and. 2 ex + e~x Please note that in addition to the phase difference, the three power signals transmitted by the transmission line 3 have the same absolute value of the voltage and the same absolute value of the current, so the corresponding power signals are analyzed. The circuit will include the same impedance component value. Therefore, it is sufficient to use the circuit model 201122503 of the aforementioned related one of the power signals to investigate the fault position F. Further, the first impedance Z1(d) can also be equivalent to a resistor Ri(d) connected in series with an inductor L1(d), and the second impedance Y1(d) can also be equivalent to a conductance Gl(d) connected in parallel. Capacitor Cl(d), ie: Z\{d) = R\{d)^ jQ\L\{d)
Yl(d)=Gl(d)+ jarCl(d) 其中,M⑷= Re4Zcsinh(Hl-i/)W)]Yl(d)=Gl(d)+ jarCl(d) where M(4)= Re4Zcsinh(Hl-i/)W)]
Ll(d)=(l/ω^-Im ag [Zc sinh (y (l - )V^)]Ll(d)=(l/ω^-Im ag [Zc sinh (y (l - )V^)]
而Reai[x]代表x的實部,Imag[x]代表x的虛部。 值得留意的是,由於一般系統的電力信號普遍落於 60Hz頻率,所以較佳地角頻率叫=2πχ60,取樣時間Δί為 1/(60Ν),且Ν是一正整數。 由於電容Cl(d)和電感Ll(d)對於電路的影響是非線性 的,所以本實施例特別引進51· 於Reai[x] represents the real part of x, and Imag[x] represents the imaginary part of x. It is worth noting that since the power signal of a general system generally falls at a frequency of 60 Hz, the angular frequency is preferably = 2π χ 60, the sampling time Δί is 1 / (60 Ν), and Ν is a positive integer. Since the influence of the capacitance Cl(d) and the inductance Ll(d) on the circuit is non-linear, this embodiment is specifically introduced in 51.
Numerical Methods for Engineers, 5th Edition, McGraw-Hill, A^w 1¾味2㈨5所提到的一用以描述動態相量的方式,主要 是在取樣時間為Δί的情況下,以取樣時間索引值k、k-Ι來 描述電力信號,並且會特別強調電感Ll(d)與電容Cl(d)的 暫態特性,即:流經Ll(d)的電流變化,和Cl(d)的跨壓變 201122503 假設量測變電器1處的電力信號會得到一第一參考電 歷Vl(k)及—第一參考電流ii(k),那麼「與變電器2距離 dW」處的第—故障電壓vFi(k,d)為: (M) = V;⑻-L U) _L1 ⑹ Izl(k,d)-Izl(k-l,d) 2 At (3) 這裡的第一故障電流Izl(k,d)代表:i1(k)扣除「流往 Yl(d)之電流」的結果,可進一步寫成: 2 At (4) 凊 >主意,對每一取樣時間索引值k來說,第一參考電 壓v1(k)與第一參考電流Ii(k)都會有些不同。而輸電線3的 每一處都可能發生故障,所以除了 k以外,第一故障電壓 VF1(k’d)與第一故障電流Izi(k d)還會隨d變化。 另一方面,本發明領域具有通常知識者可同理推論: 當故障參數為d,變電器2到此故障位置F間的一第二組阻 抗會如圖3所示,且所包括的第一阻抗Z2(d)具有相互串接 的一電阻R2(d)及一電感L2(d) ’所包括的二個第二阻抗 Y2(d)分別具有並聯的一電導G2(d)及一電容C2(d)。 Z2⑷=Zc ♦ sinh(jcW) = /?2⑷ + · L2⑷ F2(rf) = itanh ⑷ 其中,i?2⑷= Rea/[Zc,sinh(jcW)] * 1 u —tanh fjdW\ [Zc v 2 J_ L2(d) = {\.l ωλ)·\χΆ ag [Zc · sinh(^/W)] G2(d) = Re,al 201122503 (5) 假設量測變電器2處的電力信號會得到一第二參考電 壓V2(k)及—第二參考電流〗2(k),那麼「與變電器2距離 dW」處的第二故障電壓VF2(k,d)為: 心2 (M) = ⑷-Z2{d) (6)Numerical Methods for Engineers, 5th Edition, McGraw-Hill, A^w 13⁄4味2(9)5 A method for describing dynamic phasors, mainly in the case of sampling time Δί, with sampling time index value k, K-Ι describes the power signal, and will particularly emphasize the transient characteristics of the inductor Ll(d) and the capacitor Cl(d), namely: the current flowing through Ll(d), and the cross-pressure change of Cl(d) 201122503 Assuming that the power signal at the measuring transformer 1 will obtain a first reference electrical calendar Vl(k) and a first reference current ii(k), then the first fault voltage vFi at the distance dW from the transformer 2 ( k,d) is: (M) = V; (8)-LU) _L1 (6) Izl(k,d)-Izl(kl,d) 2 At (3) The first fault current Izl(k,d) here represents: The result of i1(k) deducting the "current flowing to Yl(d)" can be further written as: 2 At (4) 凊> idea, for each sampling time index value k, the first reference voltage v1 (k) ) is somewhat different from the first reference current Ii(k). The fault may occur at every place of the power line 3, so the first fault voltage VF1(k'd) and the first fault current Izi(kd) may vary with d except for k. On the other hand, in the field of the invention, the general knowledge can reasonably infer: when the fault parameter is d, a second set of impedance between the transformer 2 and the fault position F will be as shown in FIG. 3, and the first included The impedance Z2(d) has a resistor R2(d) connected in series with each other and an inductor L2(d)' includes two second impedances Y2(d) respectively having a conductance G2(d) and a capacitor C2 connected in parallel. (d). Z2(4)=Zc ♦ sinh(jcW) = /?2(4) + · L2(4) F2(rf) = itanh (4) where i?2(4)= Rea/[Zc,sinh(jcW)] * 1 u —tanh fjdW\ [Zc v 2 J_ L2(d) = {\.l ωλ)·\χΆ ag [Zc · sinh(^/W)] G2(d) = Re,al 201122503 (5) Assume that the power signal at the measuring transducer 2 will get one The second reference voltage V2(k) and the second reference current 〖2(k), then the second fault voltage VF2(k,d) at "distance dW from the transformer 2" is: heart 2 (M) = (4) -Z2{d) (6)
ZcZc
其中的第—故障電流Iz2(k,d)代表:l2(k)扣除「流往 Y2(d)之電流」的結果,可進一步寫成:The first fault current Iz2(k,d) represents: l2(k) deducting the result of "current flowing to Y2(d)", which can be further written as:
Iz2{k,d) = l2(k)~ Y2(d)V2^-V2^k~^· -C2(d 2 At ⑺ 最後,因為配合著GPS系統2〇〇,可以準確地測得電 力信號於變電器1、2的同步電壓與電流。所以,不管於哪 一暫態(如:取樣時間索引值k),從變電器】推演或是從變 電f 2推演故障位置F的電壓準位,都會得_同的值。 簡言之,只要找出符合Vn(W)_[2(w)=〇的d,就能推得 .在與變電器2距離dW處,輸電線3發生了故障。 第一較佳實施例之實現方式 參_ 4’在前述絲式的基礎下,本發㈣障定位器 之第一較佳實施例適用於麵接一内建於變電器i的第一量 測模組η,絲接-㈣於變電器2的第二量測模组2卜 蝴固模組11、21-會分別量測輸電線3上的電力信號,以 201122503 供故障定位器5做為計算故障位置的參考。 故障定位器5包含—設定單元5ι、 &… 組52、-第—電屡 運算模 定一带「 3 —第二電流運算模組55、 -第,運算模組56、 鼻模組55、 以及一阻枋舛笪- 模,.且57、—疋位模組58, 及阻抗3十算早兀59。且模組Ml 56耦接,而逼近模έ 模組55、 μ 、 則分別耦接模組53、56、58。妒 佳地,電流運算模组_ 59 j: 車乂 ^ , . 2 和電壓運算模組53、56舍铽 整到一運算裝置50申。 會··先 定位==11 較二與故障定位器5所執行的本發明故障 苐較佳貫施例包含圖5的以下步驟: ^驟7G .第-量測模組u接收由⑽系統_傳來 、一 °步時間kAi,而據以測得第-參考電壓v1(k)、Vl(k_ 1)、V1(k-2)與第一參考電;Ali(k)、ii(k♦另一方面,第二 量測模組21也接收該同步時間,而據以測得第二參考電壓 V2(k)、v2(k-l)、v2(k_2)與第二參考電流祕)、祕…。 步驟71 .设疋單元51為故障參數d設定一初始值。 步驟72:阻抗計算單元59在式⑴、(2)、(5)的基礎下 ,基於輸電線3的長度W、特徵阻抗Zc和傳播常數^以及 故障參數d,得到第一組阻抗和第三組阻抗。 亦即’求得第一阻抗Zl(d)、第二阻抗Y1(d)、電感 L1(d)電容Cl(d) ’以及第—阻抗Z2(d)、第二阻抗Y2(d) 、電感 L2(d)、電容 C2(d)。 10 201122503 步驟73 :運算模組52~ 一參考電壓v1(k)、Vi(k 二;方程式(2)~(4),利用第 、工㈣和第-組阻抗,求出第:!·2)和第—參考電流1州 運算模組55〜56基於方程式=障電壓VF1(M),並且 二組阻抗,求出第二故障電壓 而步驟73包括圖6的以下子步驟: 子步驟7Μ 算餘52基於絲式⑺和⑷ 使電抓IKk)、Ιι〇Μ)分別扣除「流到第二阻抗^⑷的穩 態與暫態電流」’來求出流往第—阻抗卯)的電流Ιζ1(Μ) 、Izl(k-l,d)。Iz2{k,d) = l2(k)~ Y2(d)V2^-V2^k~^· -C2(d 2 At (7) Finally, because of the GPS system 2〇〇, the power signal can be accurately measured. Synchronous voltage and current of the transformers 1, 2, so, regardless of which transient state (such as: sampling time index value k), from the transformer / or from the substation f 2 to derive the voltage level of the fault location F , will get the same value. In short, as long as you find the d that meets Vn(W)_[2(w)=〇, you can push it. At the distance dW from the transformer 2, the power line 3 has occurred. The first preferred embodiment of the present invention is applicable to the first connection of the transformer (i) built in the transformer i. The measuring module η, the wire connection - (d) the second measuring module 2 of the transformer 2, the butterfly solid modules 11, 21 - respectively measure the power signal on the power line 3, with the fault locator 5 for 201122503 As a reference for calculating the fault location, the fault locator 5 includes - the setting unit 5 ι, & ... group 52, - the first electric operation module, "3 - the second current operation module 55, - the first, the operation module 56, nose mold 55, and a damper-mode, and 57, the clamp module 58, and the impedance 3 is calculated as 59. And the module Ml 56 is coupled, and the module modulo 55, μ, The modules 53 , 56 , 58 are coupled respectively. Preferably, the current calculation module _ 59 j: the rut ^ , . 2 and the voltage calculation module 53 , 56 are rounded up to an arithmetic device 50. First Positioning ==11 Secondly, the fault of the present invention performed by the fault locator 5 preferably includes the following steps of FIG. 5: Step 7G. The first measuring module u receives the (10) system _, One step time kAi, and the first reference voltage v1(k), Vl(k_1), V1(k-2) and the first reference power are measured; Ali(k), ii(k♦ The second measurement module 21 also receives the synchronization time, and accordingly, the second reference voltages V2(k), v2(kl), v2(k_2), and the second reference current secret are detected. Step 71 The setting unit 51 sets an initial value for the fault parameter d. Step 72: The impedance calculating unit 59 is based on the length W of the power transmission line 3, the characteristic impedance Zc, and the propagation constant based on the equations (1), (2), and (5). ^ and the fault parameter d, get the first set of impedance and the first Group impedance. That is, 'determine the first impedance Zl (d), the second impedance Y1 (d), the inductance L1 (d) capacitance Cl (d) ' and the first impedance Z2 (d), the second impedance Y2 (d ), inductor L2 (d), capacitor C2 (d). 10 201122503 Step 73: computing module 52 ~ a reference voltage v1 (k), Vi (k two; equations (2) ~ (4), using the first, work (4) and the first group impedance, find the::·2) and the first reference current 1 state calculation modules 55 to 56 based on the equation = barrier voltage VF1 (M), and the two sets of impedances, find the second fault voltage Step 73 includes the following sub-steps of FIG. 6: Sub-step 7 算 The calculation 52 subtracts the steady-state and transient currents flowing to the second impedance ^(4) based on the silk patterns (7) and (4), respectively, to capture the IKk, Ιι〇Μ) 'To find the current Ιζ1(Μ) and Izl(kl,d) flowing to the first-impedance 卯.
,詳細來說’本例的實施態樣是:先藉由-穩態單元su 算出p(k)和v.1)的平均結果並放大Y1⑷倍,再藉由-暫態單元TU算HJ Vl(k)和νια_υ兩個相減除以㈣結果並 放大Cl(d)倍’然後再利用一掏取單元ρυ使電流“⑻扣除 穩態單元犯與暫態單元™的輸出,而得到電流Izl(k,d)。 清注意’隨著時間過去,第一電流運算模組52能依序 為索引值k=l,2,3···做計算,因此不但可根據Vi(k)、vjk—;!) 、Ii(k)求得電流 lzl(k,d),也能根據 ν#])、Vi(k 2)、Ii(k_ 1)求得電流 Izl(k-l,d)。 子步驟732 :第一電壓運算模組53基於方程式(2)和(3) ’使電壓VJk)扣除「第一阻抗Z1(d)的穩態與暫態壓降」, 來求出第一故障電壓Vp“k,d)。In detail, the implementation of this example is: first calculate the average result of p(k) and v.1 by the steady-state unit su and enlarge Y1(4) times, and then calculate HJ Vl by the transient unit TU. (k) and νια_υ are subtracted by (4) and amplified by Cl(d) times. Then, using a snapping unit ρυ, the current “(8) is deducted from the steady-state unit and the output of the transient unit TM, and the current Izl is obtained. (k, d). Note that as time passes, the first current calculation module 52 can calculate the index values k=l, 2, 3··· in order, so not only according to Vi(k), vjk -;!), Ii(k) finds the current lzl(k,d), and can also find the current Izl(kl,d) according to ν#]), Vi(k 2), Ii(k_ 1). 732: The first voltage calculation module 53 subtracts the "steady state and transient voltage drop of the first impedance Z1(d)" based on the equations (2) and (3) 'the voltage VJk" to obtain the first fault voltage Vp. "k,d).
詳細來說,本例的實施態樣是:先藉由一穩態單元SU 201122503 算出Wk,d)和Izl(k],d)的平均結果並放大Z1⑷倍,再藉 由一暫態單元TU算出Izl(k,d)和Izi(]M,d)兩個相減除以以 的、’.σ果並放大L1 (d)倍,然後再利用一操取單元ρυ使電壓 v,(k)扣除穩態單元su與暫態單元τυ的輸出,而得到電屢 VF1(k,d) 〇 子步驟733 :帛二電流運算模组55基於方程式(5)和⑺ 使電流I2(k)、I/k-i)分別扣除「流到第二阻抗γ2⑷的穩 態與暫態電流」,來求出流往第一阻抗Z2⑷的電流MM) 、IZ2(k-l,d)。 子步驟734 ·第二電壓運算模組56基於方程式⑺和⑹ ’使電壓v2(k)扣除「第一阻抗Z2⑷的穩態與暫態壓降」, 來求出第二故障電壓VF2(k,d)。 本例中’該等電壓運算模組52、55时絲樣相似, 該等電流運算模組53、56的實施態樣也相似。而子步驟 733〜734的執行順序不限於在子步驟731〜732之後,為了爭 取更短的疋位時間,較佳地子步驟733〜734會與子步驟 731~732平行執行。 步驟74 :設定單元51使一比較參數設定為:「故障參 數」加上「一逼近步階J」,即d+J。 乂驟75 .運算模組52〜53、55〜56基於方程式(2)~(7), 求出電力k號於「與變電器2距離處的一第—比 較電壓Vndd+e)和一第二比較電壓Vp2(k,d+❼。 由於此步驟的執行方式類似於步驟73,故不再费述。 12 201122503 ‘ 步驟76:逼近模組57計算該第一、第二故障電壓的差 值/(M) ’並利用該差值來更新該故障參數d,並基於更新 後的故障參數d重複步驟73~76’直到更新後的故障參數d 使該第一、第二故障電壓趨於接近,就令一定位參數d。t等 於d。 也就是說,逼近模組57會根據一非線性函數 /(Μ) = 來進行逼近。為了儘快求出符合 • 這個非線性函數f(k,d)的解,本實施例選用前述In detail, in this embodiment, the average result of Wk, d) and Izl(k], d) is first calculated by a steady-state unit SU 201122503 and amplified by Z1 (4) times, and then by a transient unit TU Calculate the two subtraction divided by Izl(k,d) and Izi(]M,d), and the '.σ fruit and amplify L1 (d) times, and then use a fetch unit ρυ to make the voltage v, (k) Deducting the output of the steady-state cell su and the transient cell τυ, and obtaining the electrical VF1(k,d) 〇 sub-step 733: The second current computing module 55 makes the current I2(k) based on equations (5) and (7), I/ki) deducts the "steady state and transient current flowing to the second impedance γ2 (4)" to obtain the currents MM) and IZ2 (kl, d) flowing to the first impedance Z2 (4). Sub-step 734: The second voltage calculation module 56 subtracts the "steady state and transient voltage drop of the first impedance Z2 (4)" from the voltage v2(k) based on equations (7) and (6)' to determine the second fault voltage VF2(k, d). In this example, the voltage calculation modules 52 and 55 are similar in wire form, and the implementations of the current operation modules 53 and 56 are similar. The order of execution of sub-steps 733-734 is not limited to being performed in sub-steps 731-732, and sub-steps 731-734 are preferably performed in parallel with sub-steps 731-732 in order to compete for shorter clamping times. Step 74: The setting unit 51 sets a comparison parameter to "fault parameter" plus "one approach step J", that is, d+J. Step 75. The calculation modules 52 to 53 and 55 to 56 obtain the electric power k number based on the equations (2) to (7), and obtain a first-comparison voltage Vndd+e at a distance from the transformer 2 and a first The comparison voltage Vp2(k, d+❼. Since the execution of this step is similar to the step 73, it will not be described. 12 201122503 'Step 76: The approach module 57 calculates the difference between the first and second fault voltages. /(M) 'and use the difference to update the fault parameter d, and repeat steps 73-76' based on the updated fault parameter d until the updated fault parameter d causes the first and second fault voltages to approach Therefore, a positioning parameter d.t is equal to d. That is, the approximation module 57 performs approximation according to a nonlinear function /(Μ) =. In order to find the coincidence as quickly as possible • This nonlinear function f(k,d Solution, this embodiment uses the aforementioned
MeMM5 一書提到的改良式正割(secant)法來實 現。根據此法,逼近模組57包括一演算單元572及一判斷 單元573,而步驟76包括圖7的以下子步驟: 子步驟761 :演算單元572計算該等故障電壓νρι(_ 、VF2(k,d)的差異而得到一逼近前信號/氏心,並計算該等 比較電壓VF1 (k’d+ ^)、Vp2(k,d+力的差異而得到—比較信號 + A,然後藉由正割法建議的式子(8),求取一逼近後 鲁參數dNEW。 δ (8) f(k,d + S)-f(k,d) a子步驟762 :判斷單元573比較是否滿足n和,左 是-誤差容忍值,卜丨代表χ的絕對值。t判斷結果為否,則 執行子步驟763 ;若為真,則跳到子步驟764。 、子步驟763:判斷單元573比較「已執行子步驟761的 次數」是否等於-計次容忍㈣。若是,則執行子步驟崩 13 201122503 ,若否,則使下一個故障參數d設定為這個dNEw,並跳回 步驟73。 子步驟764 :設定單元51使定位參數tpt設定為該逼 近後參數cInew,至此達成逼近模組57的目的。 步驟77 :定位模組58更使定位參數dDpt乘上輸電線總 長W’且將「與變電器2距離遠」的輸電線位置當作 發生故障的位置’而結束本次故障定位法的流程。 值得注意的是,相較於習知技術總是試圖忽略或移除 那些例如衰減直流成分的暫態成分,本例的運算模組52、 53、55、56則是以動態相量描述方式保留了由電容c1(d)、 C2(d)和電感Ll(d)、L2(d)造成的暫態成分,所以相較於習 知技術,逼近模組57所根據的函數/(M) = ^()U)_W办⑷ ==〇更能貼切表達實際電路情形,使得故障定位精確度獲得 大幅改善。 =此外,運算模組52、53、55、56的動態相量描述方式 單純’加上逼近模組57採用較為簡易的改良式正割法,因 此電路實現成本遠比習%耐技術具備優勢。而且,子步 驟763中’判斷單元573會對「重複執行子步驟加的次The improved secant method mentioned in the book MeMM5 is implemented. According to this method, the approximation module 57 includes a calculation unit 572 and a determination unit 573, and the step 76 includes the following sub-steps of FIG. 7: Sub-step 761: the calculation unit 572 calculates the fault voltages νρι(_, VF2(k, d) the difference is obtained by approximating the pre-signal/heart, and calculating the comparison voltage VF1 (k'd+ ^), Vp2 (k, d + force difference to obtain - comparison signal + A, and then by secant method The proposed equation (8) is obtained by approximating the post-lu parameter dNEW. δ (8) f(k,d + S)-f(k,d) a sub-step 762: the judging unit 573 compares whether n and Left is the error tolerance value, and divination represents the absolute value of χ. If the result of the determination is no, then sub-step 763 is performed; if true, then sub-step 764 is reached. Sub-step 763: Judgement unit 573 compares "executed Whether the number of sub-steps 761 is equal to - the count tolerance (four). If yes, the sub-step collapse 13 201122503 is performed, and if not, the next fault parameter d is set to this dNEw, and jumps back to step 73. Sub-step 764: setting The unit 51 sets the positioning parameter tpt to the post-approximation parameter cInew, thus achieving the purpose of approaching the module 57. Step 77 The positioning module 58 ends the process of the fault location method by multiplying the positioning parameter dDpt by the total length W' of the power line and the position of the power line that is "distant from the transformer 2" as the location where the fault occurred. In contrast, conventional techniques always attempt to ignore or remove transient components such as attenuating DC components. The computing modules 52, 53, 55, and 56 of this example are retained by dynamic phasor description. The transient components caused by the capacitors c1(d), C2(d) and the inductors L1(d), L2(d), so the function of the approximation module 57 is /(M) = ^(compared to the prior art). U)_W (4) ==〇 can more closely express the actual circuit situation, so that the fault location accuracy is greatly improved. In addition, the dynamic phasor description of the operation modules 52, 53, 55, 56 is simply 'plus approximation The module 57 adopts a relatively simple modified secant method, so the circuit implementation cost is far superior to the conventional technology. Moreover, in the sub-step 763, the 'judging unit 573 will add the repeated sub-steps.
Li二更可有效確保本例故障定位器5能如期地在系 、先要求的時間内,找出輸電線3的故障位置。 14 201122503 第二較佳實施例之原理介紹與推導 一般來說,少於80公里(km)的輸電線稱為短程輸電線 ,80~250km稱中程,而多於250km則稱長程。基本上,第 一較佳實施例適用於任何短、中、長程的輸電線。而為了 提供更經濟快速的做法,第二較佳實施例更揭露了 一種短 程與中程輸電線專用的故障定位器及方法。 前述尸ower —書中,已證明:當使用一Li II can effectively ensure that the fault locator 5 of this example can find the fault location of the power line 3 in the required time within the system and the required time. 14 201122503 Introduction and Derivation of the Principles of the Second Preferred Embodiment In general, transmission lines of less than 80 km (km) are called short-range transmission lines, 80 to 250 km are called medium-range, and more than 250 km are called long-range. Basically, the first preferred embodiment is applicable to any short, medium, and long-range power transmission line. In order to provide a more economical and rapid practice, the second preferred embodiment further discloses a fault locator and method dedicated to short- and medium-range transmission lines. The aforementioned corpse ower - in the book, has proved: when using one
中程輸電線時,sinh(x)會近似X,tanh(;c)也會近似X。因此, 第一阻抗Z2(d)與第二阻抗Y2(d)可趨近如式(9),且式(9)更 將Z2(d)解釋成「一第一阻抗因子ZE」的d倍,並將Y2(d) 解釋成「一第二阻抗因子YE」的d倍。其中,各因子由於 對應元件的非線性特性而呈現複數(complex number)型態, 並具有一實部與一虛部。For medium-range transmission lines, sinh(x) will approximate X, and tanh(;c) will also approximate X. Therefore, the first impedance Z2(d) and the second impedance Y2(d) may approach the equation (9), and the equation (9) further interprets Z2(d) as d times the "one first impedance factor ZE". And interpret Y2(d) as d times the "one second impedance factor YE". Among them, each factor exhibits a complex number type due to the nonlinear characteristic of the corresponding element, and has a real part and an imaginary part.
Z2(d) = Zc sinh(^iW) ^ZcjdW = dZE Y2{d)·Z2(d) = Zc sinh(^iW) ^ZcjdW = dZE Y2{d)·
Zc •tanh 2 J 2ZcZc •tanh 2 J 2Zc
dYE (9)dYE (9)
故,電感L2(d)與電容C2(d)可整理成式(10),並且,式 (10)更將L2(d)解釋成「一電感因子LE」的d倍,並將 C2(d)解釋成「一電容因子CE」的d倍。 L2(d 卜丄.Imag[Zc. =也£ ωι C2(rf) = ]magTherefore, the inductance L2(d) and the capacitance C2(d) can be organized into the equation (10), and the equation (10) further interprets L2(d) as d times the "one inductance factor LE", and C2(d) ) is interpreted as d times the "one capacitance factor CE". L2(d 卜丄.Imag[Zc. =also £ ωι C2(rf) = ]mag
TdW ~2Zc dCc (10) 的 以此類推,可求得電感Ll(d)相當於「電感因子Le (1-d)倍,電容Cl(d)相當於「電容因子CE」的(1-d)倍。TdW ~2Zc dCc (10) and so on, can find the inductance Ll (d) is equivalent to "inductance factor Le (1-d) times, capacitance Cl (d) is equivalent to "capacitance factor CE" (1-d ) times.
Ll(rf)« — · lmag[Zc γ{\ -d)w]= {l-d)LE ωι 15 201122503 201122503 (11) r(\-d)w ~Tic~ 進一步將這些等效元件Zl(d)、Ll(d)、Yl(d)、Cl(d)、 Z2(d)、L2(d)、Y2(d)、C2⑷代入 ,就會整理出一個變數為d的二次多項式(12),且其解如式 (13)。Ll(rf)« — · lmag[Zc γ{\ -d)w]= {ld)LE ωι 15 201122503 201122503 (11) r(\-d)w ~Tic~ Further these equivalent elements Zl(d) , Ll (d), Yl (d), Cl (d), Z2 (d), L2 (d), Y2 (d), C2 (4) substitution, will sort out a quadratic polynomial (12) with a variable d, And its solution is as in (13).
Axd2+Bxd + C = 0 (12) d __8±办2 一 4AC 2A (13) 也導入了動態相量描述 其中,多項式的係數A、B、C 方式,分別如下: 2 ΔεΥε JYMrvi(k^) V2(k)-V2(k-1)\ l Δί At J^£^£ + ceZ£) g_^i_£W+/z2 EW+/d_£(fc-1)+ 2^Ak)+v^k-i) 2 E E £ (k -1) + [z2^)-~^e ^ At ------- A/ Δί 味)-味-1) Δί i^E^E ^ ^Ε^ε) ΔίAxd2+Bxd + C = 0 (12) d __8±do 2 4AC 2A (13) The dynamic phasor description is also introduced. The coefficients A, B, and C of the polynomial are as follows: 2 ΔεΥε JYMrvi(k^) V2(k)-V2(k-1)\ l Δί At J^£^£ + ceZ£) g_^i_£W+/z2 EW+/d_£(fc-1)+ 2^Ak)+v^ki) 2 EE £ (k -1) + [z2^)-~^e ^ At ------- A/ Δί 味)-味-1) Δί i^E^E ^ ^Ε^ε) Δί
Le 16 201122503 J^lLJt±ZE,£(.-i)l +避普^ Δί ε 而心-£(幻代表著:在索引值時’將因子YE、CE代入 式⑷所得結果U代表著:在索引值k時,將因子Ye 、CE代入式(7)所得結果。另外,由於所有因子皆屬複數型 態,故可預期地該等係數信冑A、B、c與「式⑽的 解d」都會是複數。 ^ 一 利用k樣的解二次方程式法,就可直接以求出 的d當作定位參數d τ- 數dopt,而不需要像第一較佳實施例進 覆的迭代運算,故笛-杳 置的時帛—貫施例可更有效地縮短找出故障位 卜係數4號A、B、c *但相關於電壓Vi(k VKk)於二個取樣時間 吋门的電壓變化,也會相關於電流/d五㈨ 、:2_£(幻於二個取樣時間的 - j隻化所以本例也能達到貼切 地描繪電路暫態特性的目的。 第二較佳實施例之實現方式 6之第二較佳實施例適用 量 >則模組11,並輕接一内 參閱圖8,本發明故障定位器 於耦接一内建於變電器1的第一 17 201122503 建於變電器2的第二量測模組21β故障定位器6包括一因 子產生單元6!、一第一電流運算模組62、—第二電流運算 模組63、一係數產生單元64、一求解單元65及一定位模 組66 〇 而故障定位器6所執行的本發明故障定位方法之第二 較佳實施例包含圖9的以下步驟: 步驟80··第一量測模組u接收由Gps系統傳來 的-同步時間k^,而據以測得第一參考電壓v〆 1)、v1(k-2)與第一參考電流Ii(k)、ri㈣。另一方二 量:模…接收該同步時間,而據以測得 : v2(㈣-υ、ν·2)與第二參考電流_、卿^ 步驟8!:因子產生單元61產生 阻抗因子ΖΕ、第二阳丁巴栝了第- Γ . 抗因子Υε、電感因子le,與電容因早 CE。產生方式為.·· E畀罨谷因子 再乘上特徵阻 再除以兩倍的 使輸電線的傳播常數m總長w相乘 抗Zc,而得到第一阻抗因子心; 使輸電線的傳播常數 特―,而得到第二二::乘 電二抗因子ZE的虛部’再除以角頻率叫來得到 取出第二阻抗因子γ 電容因子CE。 的虛。卩,再除以角頻率叫來得到 18 201122503 - 步驟82 :第一電流運算模組62在式(4)的基礎下’以因 • 子Ye、CE來分別調整第一參考電流ijk)、Kk-i),而產生 一第一因子電流 Izl E(k)、Izl E(k-l)。 詳細來說’本例的實施態樣是:先藉由一穩態單元su 算出\^(1〇和VJk-l)的平均結果並放大丫]£倍,再藉由一暫 態單元TU算出VKk)* VJk-1)兩個相減除以&的結果並放 大(^倍,然後再利用一擷取單元pu使電流11(]〇扣除穩態 單兀SU與暫態單元TU的輸出,而得到第一因子電流 Φ Izl-E(k)。且以類似的方式由Vi(k-l)、VKk-2)和IKk-l)算出Le 16 201122503 J^lLJt±ZE, £(.-i)l + 普普^ Δί ε and heart-£(the illusion represents: when indexing the value of the factor YE, CE into the formula (4) U represents: When the index value k is indexed, the factors Ye and CE are substituted into the result of equation (7). In addition, since all the factors are of the complex type, it is expected that the coefficients of the coefficients A, B, c and the solution of the equation (10) d" will be a complex number. ^ By using the k-like solution quadratic equation method, the obtained d can be directly used as the positioning parameter d τ-number dopt without the iteration like the first preferred embodiment. Operation, so the flute-spot timing--the example can more effectively shorten the faulty position factor 4, A, B, c* but related to the voltage Vi(k VKk) at two sampling time The voltage change is also related to the current /d five (9),: 2_£ (the illusion of the two sampling times - j only so this example can also achieve the purpose of aptly depicting the circuit transient characteristics. Second preferred embodiment The second preferred embodiment of the implementation manner 6 is applicable to the module 11 and is connected to the inside of the module. The fault locator of the present invention is coupled to the built-in variable. The first measurement module 21β fault locator 6 built in the transformer 2 includes a factor generating unit 6!, a first current computing module 62, and a second current computing module 63. A second preferred embodiment of the fault location method of the present invention performed by a coefficient generating unit 64, a solving unit 65 and a positioning module 66, and the fault locator 6 comprises the following steps of FIG. 9: Step 80: First The measurement module u receives the synchronization time k^ transmitted from the GPS system, and measures the first reference voltages v〆1), v1(k-2) and the first reference currents Ii(k), ri(4). The other two quantities: the modulo ... receive the synchronization time, and according to the measurement: v2 ((four) - υ, ν · 2) and the second reference current _, qing ^ step 8!: the factor generating unit 61 generates an impedance factor ΖΕ, The second yang Dingba smashed the first - Γ. The anti-factor Υ ε, the inductance factor le, and the capacitance due to early CE. The production method is .·· E 畀罨 因子 factor multiplied by the characteristic resistance and then divided by twice the power transmission line The propagation constant m is the total length w multiplied by the anti-Zc, and the first impedance factor is obtained; the propagation constant of the transmission line is special, and the second is obtained. :: The imaginary part of the second factor ZE is divided by the angular frequency to obtain the second impedance factor γ capacitance factor CE. The virtual 卩 is divided by the angular frequency to get 18 201122503 - Step 82: A current calculation module 62 generates a first factor current Izl E(k) by using the equations (4) to adjust the first reference current ijk, Kk-i, respectively, by the terms Ye and CE. Izl E(kl). In detail, the implementation of this example is: first calculate the average result of \^(1〇 and VJk-1) by a steady-state unit su and amplify 丫]£倍, and then calculate by a transient unit TU VKk)* VJk-1) Divide the two subtractions by the result of & and amplify (^ times, then use a snapping unit pu to subtract the steady state unit SU and the output of the transient unit TU from the current 11(]〇 And obtain the first factor current Φ Izl-E(k) and calculate in a similar manner from Vi(kl), VKk-2) and IKk-l)
Izi_E(k-l)。 步驟83 .第二電流運算模組63在式⑺的基礎下,以因 -子Ye、CE來分別調整第二參考電流砂卜咖十而產生 一第二因子電 實施態樣類似步驟82,且較佳地與步驟82平行執行。Izi_E(k-l). Step 83. The second current operation module 63 generates a second factor electrical implementation similar to step 82 by adjusting the second reference current sanding by using the sub-Ye and the CE, respectively, based on the equation (7). It is preferably performed in parallel with step 82.
步驟84 .係數產生單元64根據參考電壓% υ、v2(k)、V2㈣與因子電流wk)、Μ—e⑹)、^⑻ 、Wk-i) ’並且結合步驟8i得到的所有因子,而在式 (:4)的基礎下’產生三個分別代表餘a、b、c的係數信 就0 步驟85 :求解軍& A _算出兩個分Γ具有一實:㈣ 步選出那個虛部趨近:。的實二和-虛部的可能解,並進- 的可能解,來使其實部當作定位 19 201122503 參數。 步驟86 :定位模組66以「與變電器2距離<~ w遠」 的輸電線3位置當作發生故障的位置。 會選用虛部趨近於〇的可能解,是因為:用以描述故 障位置F的「距離〜.W」必定是-個實數,故此參數dopt 的虛。P月定較佳為〇,礙於第二較佳實施例是以近似值為出 發點’所以選擇虛部趨近於〇者即可。 紅上所述’前述實施例中,該等運算模組52~53、 55~56、62~63導入了動態相量描述方式,使逼近模組”與 求解單元65得以在保留暫態成分的條件下算出定位參數 ~ ’所以輯定位精確度比習知佳,且所使㈣電路也比 DFT單純,故確實能達成本發明之目的。 惟以上所述者,僅為本發明之較佳實施例而已,當不 能以此限定本發明實施之範圍,即大凡依本發明申請專利 範圍及發明說明内容所作之簡單的等效變化與修飾皆仍 屬本發明專利涵蓋之範圍内。 【圖式簡單說明】 圖1是一示意圖,說明輸電線在兩變電器間發生了故 障; 圖2是-方塊圖,說明第—變電器與故障位置間的等 效電路; 圖3是一電路圖,說明故障位置與第二變電器間的等Step 84. The coefficient generating unit 64 combines all the factors obtained by the step 8i according to the reference voltages % υ, v2(k), V2(4) and the factor currents wk), Μ-e(6)), ^(8), Wk-i)' On the basis of (:4), 'generate three coefficient letters representing the remaining a, b, and c respectively. Step 85: Solve the army & A _ Calculate the two branches with one real: (4) Step out the imaginary part to approach :. The possible solutions of the real two and - imaginary parts, and the possible solutions of the - imaginary part, to make the actual part as a positioning parameter 19 201122503. Step 86: The positioning module 66 uses the position of the power line 3 "distance from the transformer 2 <~ w away" as the position where the failure occurs. The possible solution of the imaginary part approaching 〇 is chosen because: "distance ~.W" used to describe the fault location F must be a real number, so the parameter dopt is imaginary. The P month is preferably 〇, and the second preferred embodiment is such that the approximation is the exit point ′ so that the imaginary part is selected to be closer to the 。. In the above-mentioned embodiment, the computing modules 52-53, 55-56, and 62-63 introduce a dynamic phasor description mode, so that the approximating module and the solving unit 65 can retain the transient components. Under the condition, the positioning parameter is calculated, and the positioning accuracy is better than that of the well-known, and the circuit of (4) is also simpler than the DFT, so the object of the present invention can be achieved. However, the above is only the preferred embodiment of the present invention. However, the scope of the present invention is not limited by the scope of the present invention, and the simple equivalent changes and modifications made by the present invention are still within the scope of the present invention. Figure 1 is a schematic diagram showing the failure of the power line between the two transformers; Figure 2 is a block diagram showing the equivalent circuit between the first transformer and the fault location; Figure 3 is a circuit diagram showing the fault location and Second transformer, etc.
20 201122503 效電路; 圖4是一方塊圖 實施例; 圖5是一流程圖 佳實施例; 圖6是一流程圖, ,說明本發明故障定位器之第一 ,說明本發明故障定位方法之第 說明求得故障電壓的流程; 圖7是一流程圖,說明逼近模組的執行步驟;20 201122503 effect circuit; FIG. 4 is a block diagram embodiment; FIG. 5 is a flow chart preferred embodiment; FIG. 6 is a flow chart illustrating the first of the fault locator of the present invention, illustrating the fault location method of the present invention. Describe the flow of finding the fault voltage; FIG. 7 is a flow chart illustrating the execution steps of the approach module;
圖8是一方塊圖 實施例;及 圖9是一流程圖 佳實施例。 說明本發明故障定位器之第二 說明本發明故障定位方法之第 較佳 一較 較佳 二較Figure 8 is a block diagram embodiment; and Figure 9 is a flow chart preferred embodiment. The second description of the fault locator of the present invention illustrates the first preferred method of the fault locating method of the present invention.
21 201122503 【主要元件符號說明】 100 · ......三相電力系統 SU........穩態單元 200 · ……全球定位衛星系統 TU........暫態單元 1 ' 2 ••…變電器 PU........擷取單元 11… ......第一量測模組 Cl(d)、C2(d) 電容 21·.· ……第二量測模組 Gl(d)、G2(d) 電導 3 ..·· ……輸電線 Ll(d)、L2(d) 電感 5、6 ••…故障定位器 Rl(d)、R2(d) 電阻 50.·· ……運算裝置 Yl(d)、Y2(d) 第二阻抗 51.··· Zl(d)、Z2(d) 第一阻抗 52 ' 62 ·.第一電流運算模組 70〜77····第一實施例的執 53·.. ……第一電壓運算模組 行步驟 55 ' 63 .·第二電流運算模組 731〜734求取故障電壓的 56··. ……第二電壓運算模組 步驟 57··· ……逼近模組 761~764逼近模組的執行 572 · ……演算單元 步驟 573 · ……判斷單元 80〜86.·.·第二實施例的執 58 ' 6 6 ··定位模組 行步驟 59... ……阻抗計算單元 61··. ……因子產生單元 64.·. ……係數產生單元 65... ……求解單元21 201122503 [Explanation of main component symbols] 100 · ...... Three-phase power system SU........ Steady-state unit 200 · ...... Global Positioning Satellite System TU........ State Unit 1 ' 2 ••... Transformer PU........ Capture Unit 11.........The first measurement module Cl(d), C2(d) Capacitor 21·.· ......Second measurement module Gl(d), G2(d) Conductance 3 ........ ...... Transmission line Ll(d), L2(d) Inductance 5, 6 ••... Fault locator Rl(d) , R2 (d) Resistor 50.··... Computing device Yl(d), Y2(d) Second impedance 51.··· Zl(d), Z2(d) First impedance 52 ' 62 ·. First The current calculation modules 70 to 77········································ 56··. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . The second embodiment of the implementation 58 '6 6 · positioning module step 59 ... ... impedance calculation unit 61 · ·. 64. · unit. Coefficient generating unit ...... 65 ... ...... solving unit
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