JPH09167639A - Explosive joining device for electric wire - Google Patents

Abstract

PROBLEM TO BE SOLVED: To reduce an explosion sound, to prevent an explosion gas an scattered objects caused by an explosion from inflicting damage on persons and installations standing in the vicinity, and to execute work safely even in an urban district, on a steel tower, or in an underground disposed passage, when power transmission wires, power distribution wires, or the like are joined together by means of the explosion of an explosive compound. SOLUTION: This is a small sized and light weight device to be used in the case electric wires 3 are joined together by exploding an explosive compound 1, wherein the explosive compound 1 and a joint part of the electric wires 3 are housed therein in a quasi-sealed state and its strength is established according to the kind and quantity of the explosive compound 1 to be used, and a high pressure gas and an explosion sound generated by an explosion are exhausted and propagated, through passages through which the wires 3 are led out from a container to the exterior, with the pressure reduced and with the sound eliminated, and therefore no danger exists in the proximity, the sound being sufficiently reduced, and explosion work, which was heretofore extremely difficult to be executed in an urban district, on a steel tower for laying electric wires, or in an underground disposed passage, can be executed safely and easily without producing noise pollution.

Description

Detailed Description of the Invention

[0001]

BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to the so-called explosive pressure welding of electric wires, in which the ends of two electric wires are joined by utilizing the explosive pressure of explosives therein, and more broadly, the explosive processing of metals and ceramics. In order to ensure safety and avoid noise pollution, work that could only be done in remote remote areas of the mountains, safely, and with extremely low explosion noise, can be performed in urban areas. Of equipment.

[0002]

2. Description of the Related Art Conventionally, for carrying out explosive pressure welding and explosive processing (hereinafter, explosive pressure welding, etc.), materials for explosive pressure welding and explosives are placed on the ground, or "development silencer", "pressure technology" It is usually carried out in a large stationary explosion-muffling device as described on page 37, March 1988. By transporting the device to an arbitrary point and using it, the safety of work can be improved. I was not able to receive the convenience of avoiding pollution caused by noise.

[0003]

SUMMARY OF THE INVENTION In order to avoid expansion of high-pressure gas caused by explosion of explosives, generation of scattered matter, loud noise, etc., mainly an explosion chamber made of steel, an explosion silencer or an explosion container, etc. It has been performed to explode explosives in a device, which is called a device (hereinafter referred to as a device), which is shielded from the surroundings in a sealed or semi-sealed state. Here, the state referred to as a closed state is a state in which the gas and the like in the device is blocked from the surroundings by the wall of the device, it is almost closed with a semi-closed state, but a passage through which a specific small amount of gas can pass is set. The semi-closed state in the present invention is a state defined later. According to the conventional technology, the wall of the device is made sturdy in order to solve the problem that the explosive explosive exerts extremely large stress on the device, sometimes projects high-speed solid debris to the surroundings, and produces a loud sound. In addition, it was inevitable to be large in order to keep it away from the explosion source as much as possible. Therefore, it has been difficult to carry the device to a place where an electric wire erection work is required to connect the electric wires and enjoy the convenience. To solve this problem and control the various phenomena associated with the above explosion while being lightweight and small, to develop a portable and safe device,
There are the following problems.

1) For the explosion of a specific amount of explosive,
There is no clear guideline as to how much stress is generated by the explosion and how much strength should be given to the wall of the device against it. 2) In order to suppress the loud sound that accompanies the explosion, the explosive sound can be suppressed almost completely and the faint sound can be transmitted to the outside if the explosive is sealed and exploded in a strong metal container. , If such a closed container is used, the explosive gas generated by the explosion will be trapped in the container, and when the container is opened, the gas will suddenly open due to the internal pressure and the gas may blow out, which may be dangerous to the operator. Further, it is difficult to introduce a part of the wire having fine irregularities on its surface like an electric wire and to seal it.

[0005]

[Means for Solving the Problem] In a device provided with a closed or semi-closed container for explosive explosives inside, a) whether the container can be divided into an upper part and a lower part at the substantially vertical center of the container,
A device that can be divided into two parts, left and right, at the approximate center of the horizontal position of the container.
b) There are two passages through which electric wires can pass in the part to be divided. c) The passage has a structure that allows the electric wires to be removed from the device when the device is divided. d) Except for passages through which electric wires can pass. The part is in a sealed state against the leakage of explosive gas caused by the explosion of explosives and the propagation of explosive sound, and e) the passageway through which the electric wire can pass is when the joint between the explosive and electric wire is stored inside the device. The explosive gas and the explosive sound leak through the gap between the electric wire and the passage to the outside of the device, but at that time, the explosive gas and the sound are set so that they can go through two or more stages of gas and acoustic expansion processes. It was used as an explosive joining device for electric wires. Further, the explosive joining apparatus is characterized in that the strength is set such that the maximum stress received by the structural strength portion of the container due to the explosion is 1/2 or less of the tensile strength of the constituent materials.

It is considered that the above problems can be solved by taking the following measures. Each number corresponds to the above-mentioned problem number. 1) For each type of explosive, its explosion speed and density, and the amount of gas generated by the explosion per unit amount of explosive are known,
Furthermore, since the amount of shock given to the wall surface by the shock wave generated from it can be obtained from the literature, it is possible to design a device having a structural strength that can withstand the amount of shock, and the explosive charge necessary for joining a specific electric wire. Since it is possible to obtain the amount, it is possible to develop a small, lightweight and portable device while satisfying them. 2) The closed type is a semi-closed type in order to avoid the danger of high-pressure gas generated by explosions staying inside, and the fact that the surface of the wire is uneven makes it possible to explode along the wire surface. Avoid the danger of opening the equipment by letting the gas automatically blow out from the equipment by the internal pressure.
In addition, by providing two or more expansion chambers in the passage through which the explosive gas blows out from the device along the surface of the electric wire, the two functions of lowering the pressure of the high pressure gas and silencing the explosion sound can be activated, resulting in danger and loud sound. It is possible to solve these two problems at the same time.

First, the impact applied to the wall surface of the device by the shock wave generated at the time of explosion and the stress applied to the device in connection with it will be examined. FIG. 1 shows a device according to the present invention in which a joint and an explosive are placed in the center of the device, and an electric wire is guided to the outside of the device through a passage provided at a position of 180 ° on the wall surface of the cylindrical device. 1 is an explosive, 2 is a metal tube for joining electric wires, 3 is an electric wire, 4
Is the upper part of the device, 5 is the lower part of the device, hidden by the electric wire 3 and the divided part is not visible, but the device is divided into two parts 4 and 5 so that the electric wire 3 after joining can be taken out from the device is there.
Further, 6 is a passage of an electric wire, 7 is a partition wall that separates a plurality of expansion chambers 8 provided in the passage, 9 is an electric detonator, 10 is a circuit for conducting electricity to energize the electric detonator, and 11 is an insulating material. Is. The shape of the device is assumed to be a cylindrical shape, but for example, a container having a polygonal cross section instead of a cylindrical shape and a spherical container as long as they have basic knowledge about material mechanics, the present invention It is possible to easily make an appropriate design by using a textbook of material mechanics and the like.

First, the impact stress applied to the wall surface of the device by the explosion of the explosive 1 and the stress applied to the device by the impact stress are obtained by the following procedure. Generally, the pressure of the shock wave generated by the explosion of explosive is 3
It is known to be inversely proportional to the power and proportional to the amount of explosive.
Therefore, if the concept of equivalent dose is introduced in order to easily obtain the shock wave pressure for any distance and any dose, the equivalent dose Z can be expressed by the following equation. Z = R / W ^1/3 ......... 1) where R is the distance from the center of the explosive; m, W is the amount of explosive; k
g.

First, let us consider obtaining the stress in the radial direction of the body of the apparatus. In this case, first, it is necessary to obtain the kinetic energy applied to the inner wall surface of the body of the device 4 or 5, so R is the distance from the center of the explosive to the device wall, and W is the weight of the explosive to be detonated in the container. Equivalent to. When determining the strength of a container, it is finally required to know its strain or load stress. The load or strain due to static pressure can be obtained by finding a value that balances the static load pressure against the wall surface and the resulting deformation stress of the container, but when impact pressure is applied, it is a transient phenomenon. Therefore, it cannot be determined by static balance. In such a case, the kinetic energy given to the wall surface by the impact pressure and the deformation energy stored in the container when the wall surface is displaced by the kinetic energy are deformed and the deformation energy stored in the container is found. Know the stress. For the procedure, it is first necessary to know the reflected impulse Ir. For a wide range of equivalent dose Z values, US Government published Supressive Shields (HNDM111
0-1-2) Jan. 23, 1978, pp. 3-15, 16 and Fig. 3-6, with the equivalent dose Z on the horizontal axis, the reflex impulse divided by the 1/3 power of the dose I _r A graph in which / W ^1/3 is plotted on the vertical axis is shown, and I _r / W ^1/3 can be easily obtained from the calculated equivalent dose Z.

According to the above 1), the equivalent dose Z is calculated, the value obtained by dividing the reflection impulse I _r corresponding to that value by W ^1/3 is obtained, and it is multiplied by W ^1/3 to obtain I _r . You can get it. However, the unit of the graph is equivalent dose Z is ft /
lb ^1/3 , and the unit of the value I _r / W ^1/3 obtained by dividing the reflex impulse by the 1/3 power of the dose is psi · sec / lb ^1/3 , so it is calculated in physical units. Therefore, it is necessary to convert to kg-m system. The unit after conversion is equivalent dose Z is m / k
g ^1/3 and I _r / W ^1/3 is kg · m / m ² · sec ² / kg
^Although it is ^1/3 , conversion of this degree can be easily performed by a person skilled in the art of technical calculation with reference to the present specification.

Furthermore, the kinetic energy KE given to the system can be derived from equation (2) from the reflected impulse I _r and the mass M of the material under pressure. KE = I _r ² / 2M ... 2) On the other hand, the deformation energy ΔEi due to the strain ε of the cylindrical portion of the device.
Is expressed by the equation 3). ΔEi = 2σεπRht / 2 = σεπRht (3) where σ: load stress on the cylinder, ε: strain rate of the cylinder, R: inner radius of the cylinder, h: height of the cylinder, t: meat of the cylinder Thickness, π; Circularity This assumes that the cylinder is thin, and
It can be applied when the length of the cylinder is not too long with respect to the diameter, but when it is thick or the length is sufficiently long with respect to the diameter, for example, when the length exceeds three times the diameter. in case of,
It is necessary to use the formula of a thick-walled cylinder, and to correct the portion where the length exceeds 3 times the diameter by changing the distance R from the center of the explosive and changing the pressure load direction. However, this degree can be easily corrected by those skilled in the art with reference to a material mechanics textbook or the like.

Here, if the kinetic energy KE obtained by the equation 2) and the energy ΔEi stored by the deformation of the container are balanced, then I _r ² / 2M = σεπRht can be set, and further, ε = σ / Ey ···· 4) However, Ey is Young's modulus, in the case of steel, 2.1 × 10 ¹¹ k
Since g · m / sec ² , σ = [I _r ² Ey / 2MπRht] ^1/2 ... 5) is obtained. Here, when obtaining the strain ε of the cylinder, σ
Is given by substituting the value of

The above is the procedure for obtaining the stress in the radial direction of the barrels applied to the inner wall surfaces of the barrels of the cylindrical devices 4 and 5 or the strain caused thereby. A method of determining the stress or strain that is vertically applied to the body by energy will be described. Basically, the load on the inner wall surface of the body can be treated in the same way.
That is, there is no difference in obtaining the kinetic energy KE from the distance from the center of the explosive and the dose, and the mass of the bottom and the lid. However, the upper part of the device 4 is the lower part of the device 5, the cylindrical body, and the connecting part of the devices 4 and 5 (not shown in FIG. 1).
It can be considered that the upper part of the device 4 and the lower part of the device 5 are pulled together via the cylindrical body and the connecting part of the devices 4 and 5 since they are integrated with each other. That is, the kinetic energy applied to the upper part of the device 4 and the lower part of the device 5 is converted into the strain energy in the vertical direction of the body and the joint. Kinetic energy K applied to the upper part of the device 4 and the lower part of the device 5 per unit area
E is obtained from the equation 2), and the masses of the upper part of the device 4 and the lower part of the device 5 are M4 and M5, respectively, and for the sake of simplicity, assuming that the reflected impulses Ir are the same, the kinetic energies per unit area KE4 and KE5, respectively. Is as follows: KE ₄ = I _r ² / 2M ₄・ ・ ・ ・ ・ ・ ・ ・ ・ ・ 6) KE ₅ = I _r ² / 2M ₅・ ・ ・ ・ ・ ・ ・ ・ ・ ・ 7)

Further, since the radii of the pressure receiving portions of the upper portion of the device 4 and the lower portion of the device 5 are equal to the radius of the body portion, both the pressure receiving areas are πR ² . Therefore, multiplying it by KE ₄ and KE ₅ gives each kinetic energy. Therefore the sum of the kinetic energy KE _{T ^{is, KE T = πR 2 I r}} 2 (M 4 + M 5) / (2M 4 M 5) ···· 8) , and the deformation of the body portion and the coupling portion of support it Since it is energy, the cross-sectional area perpendicular to the vertical axis of the body is A, the length is L, and the joint is provisionally several bolts, and the total cross-sectional area is A ', the length is L', and the strain of each is Is ε and ε ', and the common vertical stress is σ _V , the deformation energy ΔEi
Is ΔEi = E _y Σε _n ² A _n L _n ..... 9). Similar to the calculation of the radial load on the torso, kinetic energy and strain energy are set equal,
By introducing 4), the stress σ _V in the vertical direction between the body and the joint can be obtained.

The problem here is that the body portion is simultaneously loaded with the radial stress and the cylindrical axial stress. That is, the load is in a triaxial stress state. It is known that when triaxial stress is applied and the impact load condition which is a problem in the present invention, the material easily undergoes brittle fracture.
However, empirically, the load stress is 5% of the tensile strength of the material used.
It is less than 0%, preferably less than 30%, and if the design is appropriate, it can be used within a life range of about 10 ⁴ times unless a flaw that causes stress concentration during use is created. Also,
Since the intersection of the upper and lower planes and the cylinder becomes dangerous due to stress concentration, it is necessary to prevent the brittle fracture by giving a sufficient curvature to the joint or by devising a method for relaxing the stress concentration. As for how much curvature is required and how the stress concentration can be relaxed, it depends on the shape of the container, the degree of load, the required life, the material used, etc. It is difficult to specify in a general way, but if you have basic knowledge about material mechanics, you can design appropriately by referring to the specification of the present invention and textbooks of material mechanics. . However, with any suitable design, it is possible that the container may be damaged by imperfect flaws in use or latent defects in the material. As a safety measure against such accidents, it is necessary to consider, for example, in a sturdy cover so as not to injure the human body or equipment even if the container is broken and scattered. .

As described above, the method of obtaining the stress applied to the device by the shock wave generated when the explosive explodes in the closed or semi-closed device has been described. However, the device also determines the static internal pressure by the high pressure gas generated from the explosive. receive. The static internal pressure P _S is obtained by Expression 10). _{P S = f · W / V} ··················· 10) Here, P _S; generating internal pressure, f; explosive force, W, dose, V;
Container volume By knowing the internal pressure P _S applied to the container by this, the strain or stress of the container to which the internal pressure is applied can be obtained by referring to the textbook of material mechanics and the examples of the present specification. It is possible to easily know whether the container strength is suitable or not. However, in most cases, the strain or stress of the container due to the internal pressure P _S applied to the container is a. It is smaller than that due to the impact discussed in, and does not need to be a problem. When it becomes a problem, in a container with a relatively large volume, the impact pressure is low,
In the case of detonating explosive with a large amount of gas, such as ANFO, the static stress on the container may exceed the dynamic stress. In such a case, the design should be made to deal with static stress, but in the case of the device according to the present invention, it is necessary to make it a target, so a description by a concrete example is avoided here, but it is necessary. In this case, those skilled in the art can easily produce and design by referring to the above description, the reference book on appropriate explosive and the specification of the present invention.

Next, as a measure against the problem 2), in order to avoid the danger caused by the closed type, the semi-closed type is adopted so that the explosive gas is automatically ejected from the device by the internal pressure along the unevenness of the wire surface. In this process, two or more stages of expansion chambers are provided, and by doing so, the two functions of lowering the pressure of the high-pressure gas and silencing the explosion sound are activated, solving the two problems of danger and loud sound at the same time, and opening the device. Specific means for avoiding the danger of time will be described with reference to the drawings.

The passage 6 of the electric wire in FIG. 1 is made by dividing a metal tube into two and is fixed to the upper and lower parts 4 and 5 of the device by welding or mechanical means, and has a semicircular shape made of metal inside. Partition walls 7 having semicircular cutouts for passing electric wires are provided at intervals, and the electric wires and the partition walls 7 are provided between the adjacent partition walls 7.
2 shows a situation in which two or more expansion chambers 8 for expanding the explosive gas and the sound that have passed through the gap are provided for one passage. The passages 6 are joined to the upper part 4 and the lower part 5 of the device in approximately half, and when the explosive 1 and the metal tube 2 at the joint part of the electric wire are put inside the device and the upper part 4 and the lower part 5 of the device are closed together, While guiding the electric wire 3 to the outside of the device, the upper part and the lower part are combined to form one passage 6 on each side. The idea that the passage for guiding this electric wire to the inside of the device is a gas discharge passage and the acoustic and gas pressure are reduced at the same time is not limited to the idea of providing a gas expansion chamber in the passage. When joining the electric wire of, since the electric wire surface has irregularities, it causes pressure loss when passing gas,
It is also preferable because it has the effect of reducing the ejection pressure, that is, the velocity, and reducing the sound. The semicircular notch of the partition wall 7 for passing the electric wire 3 forming the wall of the expansion chamber is made circular when the upper and lower passages 6 are combined, and the circular diameter is 0 from the outer diameter of the electric wire. Greater than 1 mm, 2.0
The thickness is preferably smaller than 2.0 mm, but may exceed 2.0 mm when it is necessary to reduce the exhaust resistance. Further, the lower limit of 0.1 mm does not have any special meaning, and it means that even if there is an error in the outer diameter of the wire, the wire can be surely housed and the upper and lower passages can be aligned. . Furthermore, the diameter of the passage is 2.0 mm greater than the outer diameter of the wire.
In the case of a large size, the number of expansion chambers may be set to more than 2 to sufficiently reduce the pressure of the explosive gas and the sound, and then the gas and the sound are discharged to the outside of the device. preferable.

The spacing between adjacent partition walls 7 greatly affects the sound deadening effect when the passage is considered as an expansion type sound deadening mechanism.
Since the setting method is described in detail in a technical book on sound, those skilled in the art can easily set it with reference to them. However, the wire passage 6 is considered as a gas discharge path as well as a wire passage, but other parts of the device are hermetically closed or very close to hermetically closed to prevent leakage of explosive gas and sound. You need to be in a state. Therefore, at the joints between the device upper part 4'and the device lower part 5'and the electric wire passages 6 ', polymer materials such as rubber and plastic, inorganic gaskets such as carbon fiber, glass fiber and ceramic material, mechanical It is appropriate to achieve the leakage of the explosive gas and the explosion sound by keeping it in a closed state or a state close to it by a nesting structure, but what kind of gasket or structure is adopted is a design choice.

The connecting flange 12 is for connecting the upper part 4 of the device and the lower part 5 of the device with a connecting bolt 13 to withstand the explosive stress. In this figure, the flange and the bolt are adopted, but other methods are available. , Such as bayonet, clamp or pin, which are usually used for mechanical connection,
Anything can be used, with no inconvenience in use and strength already meeting the requirements already mentioned, the choice being at the discretion of the designer.

FIG. 2 is a view of the electric wire explosive joining apparatus shown in FIG. 1 as seen from a right angle direction. The respective part numbers correspond to the parts in FIG. 1, and the same numbers are marked with “′” to distinguish them. 1 and 2, the device is illustrated as being divided into upper and lower parts, but this is simply a matter of how to draw or how to place the device. Since the device will be split left and right, the direction of splitting is not an essential issue. Speaking darely, if a leg or a base is attached so that the device can be easily left stationary, it is determined by its design and attachment, and this is also within the discretion of the designer. Hereinafter, the present invention will be described in more detail with reference to Examples and will be compared with Comparative Examples.

[0022]

BEST MODE FOR CARRYING OUT THE INVENTION

<Example 1> An explosive 100 g of an explosive was internally detonated to manufacture an electric wire explosion joining device for joining an electric wire made of a stranded aluminum wire having a diameter of 18.2 mm. A cylinder made of high-tensile steel having an outer diameter of 230 mm, an inner diameter of 200 mm, and a height of 100 mm and a tensile strength of 60 kgf / mm ² is prepared as the upper part 4 of the apparatus body, and the opening on one side of the cylinder is made of the same material having a thickness of 15 mm. It was closed with steel to form the ceiling of the device. The cylindrical portion and the ceiling portion were connected by an arc having an inner radius of 20 mm and an outer radius of 35 mm. As a result, the distance inside the device of the ceiling from the end of the cylindrical opening on the opposite side of the ceiling is 120 mm.
It became. The cylindrical opening has an outer diameter of 40 mm and an inner diameter of 30 m.
m, 250 mm long SS41 steel tube divided into halves along the longitudinal axis, placed at 180 ° to each other so as to radiate from the center of the device. One end of the split tube was welded and fixed to the body of the device.
Grooves and corresponding portions are formed so that the joints of the ends of the cylindrical portions of the upper part 4 and the lower part 5 of the device and the mating pipes of the pipes divided into halves accompanying each other are nested with each other. Providing a protrusion.

In the inside of the halved pipe, 110 mm, 70 mm, 50 mm and 27.5 mm from the end on the device side.
With a space of 5 mm, a circular plate having a thickness of 5 mm, an outer diameter of 30 mm, and an inner diameter of 19 mm and having a hole formed therein was divided into halves, which were attached by welding as partition plates. At that time, in the part where the pipe divided into half of the device body is attached, make a semicircular hole so that the position and diameter match the hole of the semicircle provided in the partition plate, and It was a passage. 16mm in diameter at the center of the ceiling of the device
With a through hole, the outer diameter is adjusted to the diameter of the through hole, and the height is adjusted to the thickness of the ceiling by fitting the plug of fluororesin, and the outer diameter is 40 mm, the inner diameter is 10 mm, and the thickness is 4 mm. A perforated disc was applied and the edges of the disc were spot-welded and fixed to the device at three locations. Insert a steel shaft with a diameter of 3 mm and a length of 30 mm on its central axis and male threads of M3 and P = 0.5 on both ends over a length of 10 mm, and use nuts at both ends. It was fixed and used as an electric circuit for energizing an electric detonator to initiate a detonation. However, this electric circuit is not always necessary for the configuration of the device, and the electric wire coming out from the detonator is sufficiently thin (two covered electric wires of 1 mm or less each),
Take it out of the device through the wire passage along with the wire to be joined and connect it to the parallel vinyl-coated wire for energization,
Electric detonation may be used.

Further, the center of the plate thickness is separated by 30 mm from the open end of the device, and the inner diameter is 230 m parallel to the end of the device.
m, outer diameter 350 mm, thickness 15 mm, tensile strength 60 kg
Perforated disc made of high-tensile steel of f / mm ² , radius 145m
Six holes having a diameter of 25 mm were formed equidistantly at the position of m, and the groove was sufficiently formed to firmly weld it as a flange. The same thing was manufactured as the lower part of the device except that no electric circuit was provided in the central part of the ceiling. Outer diameter 18.2mm
30 aluminum wires with a diameter of 2.6 mm are used for 2.6
It is an electric wire twisted around 7 mm steel wires and has a length of 0.
2 pieces of 6m are prepared, and each end has an outer diameter of 25m
It was inserted into an aluminum tube having a diameter of m, an inner diameter of 19 mm, and a length of 100 mm, and the end of the tube was fixed with an adhesive tape of vinyl chloride so that the abutted portion was located at the center of the tube. In addition, the outer diameter of 49mm in the center of the aluminum tube,
95g of black carlit explosive with inner diameter of 25mm and length of 60mm
Was put in a paper cylinder having a thickness of 0.2 mm on the outside, and the No. 6 electric detonator was similarly fixed to the one end with tape. Electric wire and aluminum tube, explosive,
Install the electric detonator at the bottom of the device so that the electric wire passes through the semicircular hole provided in the partition plate of the steel pipe attached to the device, and the explosive is located in the center of the device. One was connected to the electrical path above the device and the other to the device body. The upper part of the device was attached to the lower part of the device, and six hexagonal bolts of M24, P = 3 with a neck length of 100 mm were passed through the holes provided in the flange, and the nuts were tightened and fixed. In addition, the half of the pipe that is the passage of the electric wire is stacked so that the upper and lower sides are aligned and become one pipe, and the end part is wrapped with a steel strip with a clamp,
The clamp was tightened and fixed.

The device was placed on the ground, the parallel vinyl-coated electric wires were attached to the electric path and the device body, and electricity was supplied to the electric detonator to detonate the explosive. As a result, a small, low explosion sound was heard, and a rubbing sound of explosive gas blown out from the gap between the electric wire and the electric wire passage was heard for about 1 second. The acoustic level measured at a distance of 20 m was 48 phon in A characteristics. It was
In addition, since the gas was blown out for about 1 second, it is estimated that the pressure of the explosion gas was sufficiently reduced at the outlet of the electric wire passage, which is the outlet, which is the electric wire passage and the expansion chamber. It was judged that the pipe separated by the partition plate which doubled as the sound deadening room had achieved its purpose. When the nut was loosened, the bolt was removed, and the electric wire was taken out, the two electric wires were fastened and joined by an aluminum tube. Such an experiment was repeated 58 times by changing the amount of explosive in the range of 100 g to 60 g, but the explosion sound was always the same, and no damage was observed in the device, and it was considered to be sufficiently practical. Judged

Here, the load applied to the device by this experiment is obtained. First, the equivalent dose Z was obtained from the formula 1). However, the same table is based on the TNT explosive, in the case of black Carlit explosives, since explosive shock may be considered to 0.6 times the TNT, T from dose W _BC black Carlit explosive
To obtain the NT equivalent equivalent dose W _TNT , it is necessary to multiply by that multiple. For replacing various explosives with a dosage based on TNT, see the TNT of the explosive energy of the explosive.
It is only necessary to multiply the explosive energy by the ratio of the explosive energy to the explosive energy, and the explosive energy values of various explosives can be easily known from a handbook or reference books on explosives. W _TNT = 0.6W _BC = 0.6 × 95g = 57g Since the distance R from the center of the explosive to the device wall is 0.1m, Z = R / W ^1/3 = 0.1m / (0.057kg) ^1/3 =
0.2598m / kg ^{1/3 When} this value is converted into feet-pounds, Z = 0.65
52 ft / lb ^1/3 , and the corresponding I _r / W ^1/3 is 0.4 psi · sec / l from the table of the above-mentioned US government publication.
It turns out that it is b ^1/3 . When converted into m-kg units, 3.59 × 10 ³ kg · m / m ² · sec ² / kg
It is ^1/3 . To obtain the reflected impulse I _r from this, W
^Since it is sufficient to multiply by ^1/3 , I _r = 3.59 × 10 ³ kg · m / m ² · sec ² / kg ^1/3 × (0.057 kg) ^1/3 = 1.38 × 10 ³ kg · m / m ² · sec

Assuming that the thickness of the wall is 15 mm and the height of each of the upper half and the lower half is 100 mm, and for simplicity, the upper and lower parts of the device are integrated, the area S of the inner wall of the cylindrical body of the device is , 0.126 m ² , and the weight of the body including the flange is about 28 kg. Therefore, the impact I _r0 received by the inner wall of the cylindrical body of the device is I _r0 = I _r × S = 1.38 × 10 ³ kg · m · sec / sec ² · m ² × 0.126 m ² = 1.74 × 10 ² kg · m · sec / sec ² , and the kinetic energy KE is calculated from the equation 3) as follows: KE = I _r0 ² /2M=(1.74×10 ² kg · m / sec) ² / (2 × 28 kg ) = 5.40 × 10 ² J For simplicity, consider the structure as a thin-walled cylinder and from Equations 3) and 4), ΔEi = σεπRht ε = σ / Eyσ = (ΔEiEy / πRht) ^1/2 , Since ΔEi = KE, R is the average of the inner and outer diameters of the cylinder, and R = 0.108 m, t = 0.015 m, h
= 0.2 m, σ = [5.4 × 10 ² kg · m ² · sec × 2.1 × 10 ¹¹ kg · m / m ² · sec ² /(π×0.108 m × 0.015 m × 0.2 m)] ^1/2 = 3.34 × 10 ⁸ kg · m / m · sec ² = 334 MPa = 34.0 kgf / mm ²

That is, the stress applied to the body of the apparatus is 334MP.
a = 34.0 kgf / mm ² and tensile strength is 60 kgf /
Since steel of mm ² was used, it can be seen that it can sufficiently withstand. For the sake of simplicity, the calculation was performed assuming that only the material forming the wall surface of the apparatus body receives the stress. However, since the flange actually reinforces the wall surface, it can be considered that the stress received is lower. In the case of rigorous calculation, those skilled in the art having basic knowledge about deformation of material due to stress can easily perform calculation by using a textbook or reference book of material mechanics and a computer program by the finite element method.

However, even considering the reinforcement by the flange, considering that the load is impact stress and it is necessary to endure fatigue due to repeated use, when a load of this level is given, the tensile strength is increased. 60 kgf / mm ²
It is appropriate to use the above-mentioned high-strength steel, and for sufficient safety, it is preferable to use ultra-high-strength steel having a tensile strength exceeding 100 kgf / mm ² . At that time, the tensile strength of 80 kgf / m must be taken into consideration.
With steels up to about m ^2, it is possible to join by welding with a certain degree of difficulty, but if the tensile strength is more than that, deterioration of the tensile strength due to welding often becomes a problem, avoiding metallurgical joining, Mechanical bonding makes it necessary to maintain strength. However, this is also to the extent that a person skilled in the art of designing machinery can easily design it with reference to the present specification.

Next, the load on the ceiling and bottom of the device and the stress applied to the device by the load will be calculated. Similar to the case where the stress on the body is obtained, first, the equivalent dose Z is calculated. The distance R from the center of the explosive to the wall surface of the device is 0.12 m, so Z = R / W ^1/3 = 0.12 m / (0.057 kg) ^1/3 =
It is 0.3118 m / kg ^1/3 , and when converted to feet-pounds, Z = 0.78.
It becomes 62 ft / lb ^1/3 , and from the table of US government publications,
It can be seen that the corresponding I _r / W ^1/3 is 0.3 psi · sec / lb ^1/3 . Converting this to m-kg units,
It is 2.69 × 10 ³ kg · m / m ² · sec ² / kg ^1/3 . To obtain the reflected impulse I _r , multiply by W ^1/3 and I _r = 2.69 × 10 ³ kg · m / m ² · sec ² / kg ^1/3 × (0.057 kg) ^1/3 = 1 0.04 × 10 ³ kg ・ m / m ²・ sec

The ceiling and bottom of the device both have a thickness of 15 m.
m, and the inner radius is 100 mm, the areas S ′ of the ceiling and the bottom of the device are 0.031 m ² and the weight is about 3.7, respectively.
kg. Therefore, the impact I on the ceiling and bottom of the device I
_r1 is I _r1 = I _r × S ′ = 1.04 × 10 ³ kg · m · / sec · m ² × 0.031 m ² = 32 kg · m · sec / sec ² , and the kinetic energy KE is expressed by Equation 3 ), KE = I _r1 ² / 2M = (32 kg · m / sec) ² /(2×3.7 kg) = 1.40 × 10 ² J

This stress or kinetic energy is applied from the joint between the upper half of the body and the ceiling to the flange, the portion that receives the tensile stress of the bolt, and the joint between the bottom of the lower half of the equipment and the flange. Is applied as stress to the parts up to and is temporarily stored as deformation energy due to the load. Further, since the above-mentioned kinetic energy is applied to either the ceiling or the bottom, the amount of deformation due to the tensile stress of the entire device is doubled above. The sectional area A of the body is 0.
01m2, length L is 0.16
m, the total cross-sectional area A ′ of the bolt is 0.003 m ² , the effective length L ′ is 0.075 m, and the stress on the body of the device and the stress on the bolt are equal, so each part is made of the same material. Then, the equation (11) holds. E _y ε _n-1 A _n-1 = E _y ε _n A _n ... 11) Also, the cross-sectional area of the body is A ₀ , and the bolt is broken. Assuming that the area is A ₁ , from the above data, A ₀ / A ₁ = 101.32 cm ² /28.14 cm ² = 3.
6 11), ε ₁ = 3.6ε ₀ ΔEi = E _y Σε _n ² A _n L _n = E _y [ε ₀ ² A ₀ L ₀ + ε ₁ ² A ₁ L ₁ ] = ε ₀ ² E _y [A ₀ L ₀ + 12.96A ₁ L ₁ ]

The length L _{0 of the} portion of the body where the tensile stress is applied is 125 mm, and the length L _{1 of the} portion of the bolt where the tensile stress is applied.
Is 75 mm, ΔEi = 1.40 × 10 ² kg · m ² / sec ² = ε ₀ ² × 2.1 × 10 ¹¹ kg · m / m ² · sec ² [0.01 m ² × 0.125 m + 13 × 0.003m ² × 0.0 75m] = 8.77 × 10 ⁸ ε ₀ ² kg · m ² / sec ² ε ₀ = [1.40 × 10 ² /8.77×10 ⁸ ] ^1/2 = 4 × 10 ⁻⁴ ε ₁ = 3.6ε ₀ = 1.44 × 10 ⁻³ , and the tensile stress σ ₀ applied to the body and the tensile stress σ ₁ applied to the bolt are calculated from this, σ ₀ = E _y ε ₀ = 2.1 × 10 ¹¹ kg · m / m ² · sec ² × 4 × 10 ⁻⁴ = 8.4 × 10 ⁷ kg · m / m ² · sec ² = 84 MPa = 8.6 kgf / mm ² σ ₁ = 3.6σ a ^{_{0 = 252MPa = 25.7kgf / mm 2}} , both tensile strength is sufficiently lower than the tensile strength of the high-tensile steel 60 kgf / mm ^2, a withstand stress.

<Comparative example> The same electric wire joining experiment was conducted without using the apparatus. When the explosive is exploded, the sound at a distance of 20 m exceeds 130 phon, and the sand scatters from the stand on which a combination of electric wires to be connected with the explosive is placed and which has a height of about 30 cm and a diameter of about 2 m. Then, the joined electric wire flew at a height of 2 m from the ground and dropped to a point about 15 m away. Compared to this situation, the sound of the device is reduced, the ability to reduce the pressure inside the device while lowering the pressure of the high pressure gas generated by the explosion, and the ability to prevent scattering of surrounding objects and electric wires are sufficient. It was decided that there was.

[0035]

INDUSTRIAL APPLICABILITY The explosive joining device for electric wires according to the present invention can reduce the explosion sound of explosives to the extent that noise pollution is not affected in the surroundings, and the explosively joined electric wires and objects around explosives scatter. Since it is a small and lightweight device that is easy to work with, it can be used for wire joining work on, for example, steel towers and underground passages, improving work efficiency, safety, and economic efficiency of wire joining. , Has the effect of expanding the usable range of electric wire explosive coupling work.

[Brief description of the drawings]

1 is a schematic cross-sectional view of an apparatus according to the present invention.

FIG. 2 is a schematic side view of a device according to the present invention.

[Explanation of symbols]

 1 Explosive 2 Metal tube for joining electric wires 3 3'electric wires 4 4'Upper part of equipment 5 5'Lower part of equipment 6 6'Wire passages 7 7'Multiple bulkheads provided in passages 8 , Expansion chamber 9, electric detonator 10, 10 'conductive circuit for detonation 11 insulating material 12, 12' coupling flange 13, 13 'coupling bolt

 ──────────────────────────────────────────────────の Continuing on the front page (72) Inventor Masato Araki 2-31-31 Iwanamesaicho, Handa-shi, Aichi Prefecture Starship Co., Ltd.

Claims (2)

[Claims] 1. An explosive joining apparatus having a hermetically sealed or semi-hermetically sealed container for explosive explosives therein, comprising: a. The container can be divided, b. The container has a passageway through which an electric wire can pass, c. The passage has a structure in which the electric wire can be removed from the device when the device is divided. D. The parts other than the passages through which the electric wires pass are in a sealed state against the leakage of explosive gas caused by the explosion of explosives and the propagation of explosive sound. E. When the joint between the explosive and the electric wire is stored inside the device, the explosive gas and explosion sound pass through the gap between the electric wire and the passage and leak to the outside of the device. An explosive joining device for electric wire, characterized in that it is set so that it can go through the expansion process of gas and sound. 2. The explosive joining according to claim 1, wherein the strength is set such that the maximum stress received by the structural strength portion of the container due to the explosion is 1/2 or less of the tensile strength of the constituent material. apparatus.