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CN111597511A - An acceptance judgment method for glass insulator sampling test based on mathematical hypothesis testing - Google Patents

An acceptance judgment method for glass insulator sampling test based on mathematical hypothesis testing Download PDF

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CN111597511A
CN111597511A CN202010491250.5A CN202010491250A CN111597511A CN 111597511 A CN111597511 A CN 111597511A CN 202010491250 A CN202010491250 A CN 202010491250A CN 111597511 A CN111597511 A CN 111597511A
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叶建锋
陈应龙
高元杰
陈俊
郭雨
邓桂平
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Materials Branch of State Grid Hubei Electric Power Co Ltd
Material Co of State Grid East Inner Mongolia Electric Power Co Ltd
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Abstract

本发明提供一种基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,所述玻璃绝缘子抽样试验是指用户收到供应商供货的玻璃绝缘子后所开展的样品抽样检验检测工作,验收是指依据抽样检验检测结果决定是否接收该批次供货产品的一系列操作。所述方法具体步骤如下:步骤一:选定假设检验的相关参数;步骤二:确定一次抽样方案的样本大小、合格质量水平及预设合格判定数和不合格判定数;步骤三:计算出统计检验量的观测值;步骤四:决定是否接收。本发明提升了玻璃绝缘子到货抽检验收效率,解决了玻璃绝缘子验收手段少的问题,确保了用户和供应商双方的权益。

Figure 202010491250

The invention provides a method for judging acceptance of glass insulator sampling test based on mathematical hypothesis testing. A series of operations that determine whether or not to accept the batch of products supplied by the sampling inspection test results. The specific steps of the method are as follows: step 1: select relevant parameters for hypothesis testing; step 2: determine the sample size, qualified quality level and preset number of qualified judgments and unqualified judgments of a sampling plan; step 3: calculate statistics The observed value of the test quantity; Step 4: Decide whether to accept or not. The invention improves the sampling and acceptance efficiency of the glass insulator upon arrival, solves the problem of few acceptance methods for the glass insulator, and ensures the rights and interests of both users and suppliers.

Figure 202010491250

Description

一种基于数学假设检验的玻璃绝缘子抽样试验验收判定方法An acceptance judgment method for glass insulator sampling test based on mathematical hypothesis testing

技术领域technical field

本发明涉及电力物资采购验收领域,具体是一种基于数学假设检验的玻璃绝缘子抽样试验验收判定方法。The invention relates to the field of electric power material procurement and acceptance, in particular to a method for judging acceptance of a glass insulator sampling test based on a mathematical hypothesis test.

背景技术Background technique

在电力物资设备采购的环节中,抽样试验是一个决定设备是否验收的关键环节。绝缘子在电力安全生产中起着至关重要的作用,而玻璃绝缘子更是电力部门最广泛和最大量使用的物资,抽样试验和验收一般推荐依据GBT1001.1-2003标称中压高于1000V的架空线路绝缘子第1部分交流系统用瓷或玻璃绝缘子元件--定义,试验方法和判定准则开展。但当提交验收的由同一制造厂在相同生产条件下生产的同一结构的一批或多批绝缘子数量较大时(多于10000只时),GBT1001.1-2003推荐将它们分成每批由2000至10000只绝缘子组成的适当批量数,按协商的数量从批中随机抽取。这种抽样规则和判定准则给供货方和用户因质量验收管理带来较多的工作量,且容易出现样品混乱的现象;又由于抽样协商的数量范围较大,质量控制风险较大。In the process of purchasing power materials and equipment, sampling test is a key link to determine whether the equipment is accepted or not. Insulators play a vital role in the safe production of electricity, and glass insulators are the most widely used materials in the power sector. Sampling tests and acceptance are generally recommended according to GBT1001.1-2003. The nominal medium voltage is higher than 1000V. Overhead line insulators Part 1 Porcelain or glass insulator elements for alternating current systems -- Definitions, test methods and criteria for development. However, when the number of one or more batches of insulators of the same structure produced by the same manufacturer under the same production conditions is large (more than 10,000 pieces) submitted for acceptance, GBT1001.1-2003 recommends that they be divided into batches of 2,000 pieces each. Appropriate batch number consisting of up to 10,000 insulators, randomly selected from the batch according to the negotiated quantity. Such sampling rules and judgment criteria bring more workload to suppliers and users due to quality acceptance management, and are prone to the phenomenon of sample confusion; and due to the large range of sampling negotiation, the risk of quality control is high.

因此有必要针对供货批的数量多于10000只时抽样验收试验存在的问题,参照GBT1001.1-2003按千分之四的最高抽样数量一次抽样,并探讨其对应的判定方法。Therefore, it is necessary to take a sampling according to the maximum sampling quantity of four thousandths according to GBT1001.1-2003 for the problems existing in the sampling acceptance test when the quantity of the supply batch is more than 10,000, and discuss the corresponding judgment method.

发明内容SUMMARY OF THE INVENTION

本发明的目的是提出一种基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,一站式解决在玻璃绝缘子抽样手续复杂且容易混乱的问题,以满足物资抽检高效率低风险的需求,提升玻璃绝缘子到货验收把控手段,进一步提高电力安全生产水平。The purpose of the present invention is to propose a method for judging the acceptance of glass insulator sampling test based on mathematical hypothesis testing, which can solve the problem of complicated and chaotic sampling procedures in glass insulators in one stop, so as to meet the requirements of high efficiency and low risk in material sampling inspection, and improve glass insulators. Insulator arrival acceptance control means to further improve the level of power safety production.

本发明采用如下技术方案:The present invention adopts following technical scheme:

一种基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,包括如下步骤:A method for judging acceptance of glass insulator sampling test based on mathematical hypothesis testing, comprising the following steps:

步骤一:选定假设检验的相关参数,所述假设检验的相关参数具体包括原假设H0、非正态总体大样本参数检验所需参数单侧样本数q、样本数n、显著性水平α、检验统计量的观测值T、自由度υ、自由度υ无穷大时t分布表的单侧值

Figure BDA0002521102540000021
Step 1: Select the relevant parameters of the hypothesis test, the relevant parameters of the hypothesis test specifically include the null hypothesis H 0 , the parameters required for the non-normal population large sample parameter test, the number of one-sided samples q, the number of samples n, and the significance level α , the observed value of the test statistic T, the degree of freedom υ, the one-sided value of the t distribution table when the degree of freedom υ is infinite
Figure BDA0002521102540000021

步骤二:确定一次抽样方案的样本数n、合格质量水平AQL/%及预设合格判定数Ac和不合格判定数ReStep 2: Determine the number of samples n, the qualified quality level AQL/% and the preset qualified judgment number A c and the unqualified judgment number Re of the primary sampling plan;

步骤三:根据步骤二确定的一次抽样方案的样本数n、合格质量水平AQL/%及预设合格判定数Ac和不合格判定数Re,计算统计检验量的观测值;Step 3: According to the sample number n of the primary sampling plan determined in step 2, the qualified quality level AQL/% and the preset qualified judgment number A c and the unqualified judgment number Re , calculate the observed value of the statistical test quantity;

步骤四:用查t分布表得到的单侧值

Figure BDA0002521102540000022
和预设合格判定数及不合格判定数的观测值比较,决定一次抽样后是否接收该批量产品。Step 4: Use the one-sided value obtained by looking up the t distribution table
Figure BDA0002521102540000022
Compare with the observed value of the preset qualified judgment number and unqualified judgment number to decide whether to accept the batch of products after one sampling.

进一步的,步骤三计算统计检验量的观测值的公式为:Further, the formula for calculating the observed value of the statistical test quantity in step 3 is:

检验统计量的观测值

Figure BDA0002521102540000023
The observed value of the test statistic
Figure BDA0002521102540000023

其中n为样本数,

Figure BDA0002521102540000024
为单侧样本数q的极大似然估计,
Figure BDA0002521102540000025
p为单侧概率。where n is the number of samples,
Figure BDA0002521102540000024
is the maximum likelihood estimate of the one-sided sample size q,
Figure BDA0002521102540000025
p is the one-sided probability.

进一步的,步骤三中,检验假设时将合格质量水平AQL值作为假设分界Further, in step 3, the qualified quality level AQL value is used as the hypothesis boundary when testing the hypothesis

H0:p≤0.01 H1:p>0.01 (4)H 0 : p≤0.01 H 1 : p>0.01 (4)

总体X~B(1,p) (5)Overall X~B(1,p) (5)

样本服从B分布,需要变成N(0,1)分布,再按t分布来查表;The sample obeys the B distribution and needs to be changed to N(0,1) distribution, and then look up the table according to the t distribution;

单侧样本数q的极大似然估计是:The maximum likelihood estimate of the one-sided sample size q is:

Figure BDA0002521102540000031
Figure BDA0002521102540000031

且近似有and approximately have

Figure BDA0002521102540000032
Figure BDA0002521102540000032

当H0成立时,p≤0.01,从而取检验统计量的观测值:When H 0 is established, p≤0.01, thus taking the observed value of the test statistic:

Figure BDA0002521102540000033
Figure BDA0002521102540000033

于是由

Figure BDA0002521102540000039
So by
Figure BDA0002521102540000039

得到检验的拒绝域为:The rejected domains that are checked are:

Figure BDA0002521102540000034
Figure BDA0002521102540000034

代入

Figure BDA0002521102540000035
即可得到检验统计量的观测值T,其中显著性水平α为原假设H0成立,因观测值进入了拒绝域,从而作出拒绝的结论的作第一类错误的概率。substitute
Figure BDA0002521102540000035
The observation value T of the test statistic can be obtained, in which the significance level α is the probability that the null hypothesis H 0 is established, and the observation value enters the rejection domain, thus making a rejected conclusion as the probability of type 1 error.

进一步的,步骤四具体为:用查t分布表得到的单侧值

Figure BDA0002521102540000036
根据步骤三计算获得预设合格判定数的观测值,若预设合格判定数的观测值小于单侧值
Figure BDA0002521102540000037
则预设合格判定数正确,则接收本批次产品;若预设合格判定数的观测值大于等于单侧值
Figure BDA0002521102540000038
预设不合格判定数正确,则进入加倍重复试验程序。Further, step 4 is specifically: use the one-sided value obtained by looking up the t distribution table
Figure BDA0002521102540000036
Calculate and obtain the observed value of the preset qualified judgment number according to step 3, if the observed value of the preset qualified judgment number is less than the one-sided value
Figure BDA0002521102540000037
If the preset qualified judgment number is correct, the batch of products will be accepted; if the observed value of the preset qualified judgment number is greater than or equal to the one-sided value
Figure BDA0002521102540000038
If the preset number of unqualified judgments is correct, enter the double-repetition test procedure.

本发明一站式解决在玻璃绝缘子抽样手续复杂且容易混乱的问题,提升了玻璃绝缘子到货抽检验收效率,解决了玻璃绝缘子验收手段少的问题,确保了用户和供应商双方的权益。The invention solves the problem that the sampling procedure of glass insulators is complicated and easy to be confused in one stop, improves the sampling inspection and acceptance efficiency of glass insulators upon arrival, solves the problem of few acceptance methods for glass insulators, and ensures the rights and interests of both users and suppliers.

附图说明Description of drawings

图1是本发明基于数学假设检验的玻璃绝缘子抽样试验验收判定方法的流程示意图。FIG. 1 is a schematic flow chart of the acceptance judgment method of the glass insulator sampling test based on the mathematical hypothesis test of the present invention.

具体实施方式Detailed ways

下面将结合本发明中的附图,对本发明中的技术方案进行清楚、完整地描述。The technical solutions in the present invention will be clearly and completely described below with reference to the accompanying drawings in the present invention.

图1所示为本发明基于数学假设检验的玻璃绝缘子抽样试验验收判定方法的流程示意图,所述基于数学假设检验的玻璃绝缘子抽样试验验收判定方法包括如下步骤:1 shows a schematic flowchart of a method for judging acceptance of glass insulator sampling test based on mathematical hypothesis testing of the present invention. The method for judging acceptance of glass insulator sampling test based on mathematical hypothesis testing includes the following steps:

步骤一:选定假设检验的相关参数;Step 1: Select relevant parameters for hypothesis testing;

所述步骤一中,假设检验的相关参数具体为原假设H0、非正态总体大样本参数检验所需参数单侧样本数q、样本数n、显著性水平α、检验统计量的观测值T、自由度υ、自由度υ无穷大时t分布表的单侧值

Figure BDA0002521102540000041
所述假设检验的相关参数来源于下列数学原理和公式:In the first step, the relevant parameters of the hypothesis test are specifically the null hypothesis H 0 , the one-sided sample number q, the sample number n, the significance level α, and the observed value of the test statistic required for the non-normal population large-sample parameter test. One-sided value of t distribution table when T, degree of freedom υ, and degree of freedom υ are infinite
Figure BDA0002521102540000041
The relevant parameters of the hypothesis test are derived from the following mathematical principles and formulas:

(1)假设检验的特点(1) Features of hypothesis testing

反证法思想:为了判断某一事件是否成立,首先提出某一假设,并认为这个假设是成立的,一般把这个假设称为原假设或零假设,并常以H0表示,然后再根据这个假设进行推理。在这个假设成立的条件下,如果导致一个不合理的现象出现,就否定这个假设;否则,就接受这个假设,从而对事件的性质作出判断。Contradictory thinking: In order to judge whether a certain event is true, first put forward a certain hypothesis, and think that this hypothesis is true, this hypothesis is generally called the null hypothesis or null hypothesis, and is often expressed as H 0 , and then proceed according to this hypothesis. reasoning. Under the condition that this assumption is established, if an unreasonable phenomenon occurs, the assumption is rejected; otherwise, the assumption is accepted, so as to make a judgment on the nature of the event.

(2)非正态总体大样本参数检验(2) Non-normal population large sample parameter test

总体X~B(1,p) (1)Overall X~B(1,p) (1)

单侧样本数q的极大似然估计:Maximum likelihood estimate of the one-sided sample size q:

Figure BDA0002521102540000051
Figure BDA0002521102540000051

由大样本正态逼近性质近似有:The properties approximated by the large sample normal approximation are:

Figure BDA0002521102540000052
Figure BDA0002521102540000052

即左边的式子服从0,1分布。That is, the expression on the left obeys the 0,1 distribution.

(3)假设检验的两类错误(3) Two types of errors in hypothesis testing

如果原假设H0成立,但因观测值进入了拒绝域,从而作出了拒绝的结论,称作第一类错误。第一类错误是“以真为假”的错误,也称“弃真”错误,根据定义,显著性水平α恰好是犯第一类错误的概率(在判定中取α=0.01)。If the null hypothesis H 0 is established, but because the observed value enters the rejection domain, the conclusion of rejection is made, which is called the first type of error. The first type of error is the error of "taking the true as a false", also known as the "discarding the true" error. According to the definition, the significance level α is exactly the probability of making the first type of error (take α=0.01 in the judgment).

如果原假设H0不成立,但因为观测值处于接受域,从而作出了接受该假设的结论,称作第二类错误。这类错误是“以假当真”的错误,也称“取伪”错误,通常把犯第二类错误的概率用β表示。If the null hypothesis H 0 does not hold, but because the observations are in the receptive field, the conclusion that the hypothesis is accepted is called Type II error. This type of error is the error of "taking false as true", also known as "taking false" error, usually the probability of making the second type of error is represented by β.

人们当然希望α和β都小,但这很难做到。因为,一般来说,α小,β就大;β小,则α大。所以通常做法是:在固定α的前提下,适当增大样本容量,以减小β。One would of course want both α and β to be small, but that's hard to do. Because, in general, when α is small, β is large; when β is small, α is large. Therefore, the usual practice is to increase the sample size appropriately to reduce β under the premise of fixing α.

(4)t分布表(4) t distribution table

当样本服从0,1分布时,根据单侧概率p和自由度υ有t值。When the sample obeys the 0, 1 distribution, there is a t value according to the one-sided probability p and the degree of freedom υ.

表1 t分布表Table 1 t distribution table

Figure BDA0002521102540000061
Figure BDA0002521102540000061

步骤二:确定一次抽样方案的样本大小、合格质量水平及预设合格判定数和不合格判定数;Step 2: Determine the sample size, qualified quality level, and the preset number of qualified and unqualified judgments for the primary sampling plan;

所述步骤二中,按表2的产品批量来确定样本大小(即样本数n),合格质量水平AQL/%、预设合格判定数Ac和不合格判定数Re。产品批量按万只为单位,并按千分之四抽样。In the second step, the sample size (ie the number of samples n), the qualified quality level AQL/%, the preset qualified judgment number A c and the unqualified judgment number R e are determined according to the product batches in Table 2. The batch of products is in units of 10,000, and sampling is performed by 4/1,000.

表2 部分一次抽样方案Table 2 Partial one-shot sampling plan

Figure BDA0002521102540000062
Figure BDA0002521102540000062

步骤三:计算出统计检验量的观测值;Step 3: Calculate the observed value of the statistical test quantity;

所述步骤三中,以样本数n为80时,预设合格判定数Ac=2,预设不合格判定数Re=3为例,具体计算观测值T为:In the third step, when the number of samples n is 80, the preset number of qualified judgments A c =2, and the preset number of unqualified judgments Re =3 as an example, the specific calculation observation value T is:

以样本数n为80时,Ac=2;Re=3为例计算分析如下:Taking the sample number n as 80, A c =2; Re =3 as an example, the calculation and analysis are as follows:

检验假设(将合格质量水平AQL值作为假设分界)Test the hypothesis (use the acceptable quality level AQL value as the hypothesis boundary)

H0:p≤0.01 H1:p>0.01 (4)H 0 : p≤0.01 H 1 : p>0.01 (4)

总体X~B(1,p) (5)Overall X~B(1,p) (5)

思路方法:样本服从B分布,需要变成N(0,1)分布,再按t分布来查表。Way of thinking: The sample obeys the B distribution, which needs to be changed to N(0,1) distribution, and then look up the table according to the t distribution.

单侧样本数q的极大似然估计是:The maximum likelihood estimate of the one-sided sample size q is:

Figure BDA0002521102540000071
Figure BDA0002521102540000071

且近似有and approximately have

Figure BDA0002521102540000072
Figure BDA0002521102540000072

当H0成立时,p≤0.01,从而取检验统计量的观测值:When H 0 is established, p≤0.01, thus taking the observed value of the test statistic:

Figure BDA0002521102540000073
Figure BDA0002521102540000073

于是由

Figure BDA0002521102540000079
So by
Figure BDA0002521102540000079

得到检验的拒绝域为:The rejected domains that are checked are:

Figure BDA0002521102540000074
Figure BDA0002521102540000074

代入

Figure BDA0002521102540000075
得到检验统计量的观测值T:substitute
Figure BDA0002521102540000075
Get the observed value T of the test statistic:

Figure BDA0002521102540000076
Figure BDA0002521102540000076

如发现3件次品,则If 3 defective products are found, then

Figure BDA0002521102540000077
Figure BDA0002521102540000077

观测值T:

Figure BDA0002521102540000078
Observation T:
Figure BDA0002521102540000078

步骤四:决定是否接收。Step 4: Decide whether to accept or not.

所述步骤四中,用查t分布表得到的单侧值

Figure BDA0002521102540000083
和预设合格判定数及不合格判定数的观测值比较,决定一次抽样后是否接收该批量产品。具体计算如下:In the step 4, use the one-sided value obtained by looking up the t distribution table
Figure BDA0002521102540000083
Compare with the observed value of the preset qualified judgment number and unqualified judgment number to decide whether to accept the batch of products after one sampling. The specific calculation is as follows:

Figure BDA0002521102540000082
Figure BDA0002521102540000082

查t分布表得Look up the t distribution table to get

t0.99=2.32 (15)t 0.99 = 2.32 (15)

预设合格判定数为2时的观测值1.34The observed value when the preset number of qualified judgments is 2 is 1.34

显然1.34<2.32 (16)Obviously 1.34 < 2.32 (16)

因此不能拒绝H0,即预设合格判定数正确,接收本批次产品。预设不合格判定数为3时的观测值2.52Therefore, H 0 cannot be rejected, that is, the preset number of qualified judgments is correct, and this batch of products is accepted. The observed value when the preset number of unqualified judgments is 3 is 2.52

显然2.52>2.32 (17)Obviously 2.52 > 2.32 (17)

因此拒绝H0,即预设不合格判定数正确,进入加倍重复试验程序。Therefore, H 0 is rejected, that is, the preset number of unqualified judgments is correct, and the double-repeat test procedure is entered.

同理可得出其它样本大小的观测值如表3所示Similarly, observations of other sample sizes can be obtained as shown in Table 3

表3 不同样本大小的检验统计量观测值Table 3 Test statistic observations for different sample sizes

Figure BDA0002521102540000081
Figure BDA0002521102540000081

显然表3中的验收时的观测值均小于2.32,拒收时的观测值大于2.32。Obviously, the observed values of acceptance in Table 3 are all less than 2.32, and the observed values of rejection are greater than 2.32.

以上所述,仅为本发明的具体实施方式,但本发明的保护范围并不局限于此,任何属于本技术领域的技术人员在本发明揭露的技术范围内,可轻易想到的变化或替换,都应涵盖在本发明的保护范围之内。因此,本发明的保护范围应该以权利要求的保护范围为准。The above are only specific embodiments of the present invention, but the protection scope of the present invention is not limited thereto. Any person skilled in the art can easily think of changes or substitutions within the technical scope disclosed by the present invention, All should be included within the protection scope of the present invention. Therefore, the protection scope of the present invention should be subject to the protection scope of the claims.

Claims (4)

1.一种基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,其特征在于包括如下步骤:1. a kind of glass insulator sampling test acceptance judgment method based on mathematical hypothesis test is characterized in that comprising the steps: 步骤一:选定假设检验的相关参数,所述假设检验的相关参数具体包括原假设H0、非正态总体大样本参数检验所需参数单侧样本数q、样本数n、显著性水平α、检验统计量的观测值T、自由度υ、自由度υ无穷大时t分布表的单侧值
Figure FDA0002521102530000011
Step 1: Select the relevant parameters of the hypothesis test, the relevant parameters of the hypothesis test specifically include the null hypothesis H 0 , the parameters required for the non-normal population large sample parameter test, the number of one-sided samples q, the number of samples n, and the significance level α , the observed value of the test statistic T, the degree of freedom υ, the one-sided value of the t distribution table when the degree of freedom υ is infinite
Figure FDA0002521102530000011
步骤二:确定一次抽样方案的样本数n、合格质量水平AQL/%及预设合格判定数Ac和不合格判定数ReStep 2: Determine the number of samples n, the qualified quality level AQL/% and the preset qualified judgment number A c and the unqualified judgment number Re of the primary sampling plan; 步骤三:根据步骤二确定的一次抽样方案的样本数n、合格质量水平AQL/%及预设合格判定数Ac和不合格判定数Re,计算统计检验量的观测值;Step 3: According to the sample number n of the primary sampling plan determined in step 2, the qualified quality level AQL/% and the preset qualified judgment number A c and the unqualified judgment number Re , calculate the observed value of the statistical test quantity; 步骤四:用查t分布表得到的单侧值
Figure FDA0002521102530000012
和预设合格判定数及不合格判定数的观测值比较,决定一次抽样后是否接收该批量产品。
Step 4: Use the one-sided value obtained by looking up the t distribution table
Figure FDA0002521102530000012
Compare with the observed value of the preset qualified judgment number and unqualified judgment number to decide whether to accept the batch of products after one sampling.
2.如权利要求1所述的基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,其特征在于:步骤三计算统计检验量的观测值的公式为:2. the glass insulator sampling test acceptance judgment method based on the mathematical hypothesis test as claimed in claim 1, is characterized in that: the formula of the observed value of step 3 calculating statistical test quantity is: 检验统计量的观测值
Figure FDA0002521102530000013
The observed value of the test statistic
Figure FDA0002521102530000013
其中n为样本数,
Figure FDA0002521102530000014
为单侧样本数q的极大似然估计,
Figure FDA0002521102530000015
p为单侧概率。
where n is the number of samples,
Figure FDA0002521102530000014
is the maximum likelihood estimate of the one-sided sample size q,
Figure FDA0002521102530000015
p is the one-sided probability.
3.如权利要求1所述的基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,其特征在于:步骤三中,检验假设时将合格质量水平AQL值作为假设分界3. the glass insulator sampling test acceptance judgment method based on mathematical hypothesis test as claimed in claim 1, is characterized in that: in step 3, when testing hypothesis, the qualified quality level AQL value is used as hypothesis boundary H0:p≤0.01 H1:p>0.01 (4)H 0 : p≤0.01 H 1 : p>0.01 (4) 总体X~B(1,p) (5)Overall X~B(1,p) (5) 样本服从B分布,需要变成N(0,1)分布,再按t分布来查表;The sample obeys the B distribution and needs to be changed to N(0,1) distribution, and then look up the table according to the t distribution; 单侧样本数q的极大似然估计是:The maximum likelihood estimate of the one-sided sample size q is:
Figure FDA0002521102530000021
Figure FDA0002521102530000021
且近似有and approximately have
Figure FDA0002521102530000022
Figure FDA0002521102530000022
当H0成立时,p≤0.01,从而取检验统计量的观测值:When H 0 is established, p≤0.01, thus taking the observed value of the test statistic:
Figure FDA0002521102530000023
Figure FDA0002521102530000023
于是由
Figure FDA0002521102530000024
So by
Figure FDA0002521102530000024
得到检验的拒绝域为:The rejected domains that are checked are:
Figure FDA0002521102530000025
Figure FDA0002521102530000025
代入
Figure FDA0002521102530000026
即可得到检验统计量的观测值T,其中显著性水平α为原假设H0成立,因观测值进入了拒绝域,从而作出拒绝的结论的作第一类错误的概率。
substitute
Figure FDA0002521102530000026
The observation value T of the test statistic can be obtained, in which the significance level α is the probability that the null hypothesis H 0 is established, and the observation value enters the rejection domain, thus making a rejected conclusion as the probability of type 1 error.
4.如权利要求1所述的基于数学假设检验的玻璃绝缘子抽样试验验收判定方法,其特征在于:步骤四具体为:用查t分布表得到的单侧值
Figure FDA0002521102530000027
根据步骤三计算获得预设合格判定数的观测值,若预设合格判定数的观测值小于单侧值
Figure FDA0002521102530000028
则预设合格判定数正确,则接收本批次产品;若预设合格判定数的观测值大于等于单侧值
Figure FDA0002521102530000029
预设不合格判定数正确,则进入加倍重复试验程序。
4. the glass insulator sampling test acceptance judgment method based on mathematical hypothesis test as claimed in claim 1, is characterized in that: step 4 is specifically: the one-sided value that obtains with looking up t distribution table
Figure FDA0002521102530000027
Calculate and obtain the observed value of the preset qualified judgment number according to step 3, if the observed value of the preset qualified judgment number is less than the one-sided value
Figure FDA0002521102530000028
If the preset qualified judgment number is correct, the batch of products will be accepted; if the observed value of the preset qualified judgment number is greater than or equal to the one-sided value
Figure FDA0002521102530000029
If the preset number of unqualified judgments is correct, enter the double-repetition test procedure.
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