CN111248858A - Photoacoustic tomography reconstruction method based on frequency domain wavenumber domain - Google Patents
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Abstract
Description
技术领域technical field
本发明属于一种成像重建方法,特别涉及一种光声断层成像重建方法。The invention belongs to an imaging reconstruction method, in particular to a photoacoustic tomographic imaging reconstruction method.
背景技术Background technique
光声成像是一种新兴的成像技术,为临床成像提供了潜在的视角和机遇。光声断层成像是光声成像的一个重要分支,其优势在于成像深度较深,可达数厘米,符合临床成像的基本需求。目前已有基于环形阵列声学换能器(全角度探测)的光声断层成像用于乳腺的检查,然而环形声学探测器受其固有形状结构限制,难以用于与更多部位的光声成像和临床检查。基于手持式(有限角度探测)的声学换能器,其优势在于灵活便携,同时便于与目前临床上常用的超声成像结合,是光声断层成像的发展趋势。光声断层成像区别于其他光声成像技术的最显著特点在于光声断层成像需要将采集到的射频数据进行重建才能获得光声图像,目前常用的重建方法包括时间反演法、滤波反投影法,这两种方法对于全角度探测的光声断层成像具有较好效果;然而对于手持式的声学换能器,由于只采集了有限角度的信号,上述两种方法难以实现精确的重建成像。另一方面,二维矩阵声学换能器是一种新兴的手持式声学换能器,可以直接进行三维成像,目前还没有可以对二维矩阵声学换能器进行重建的方法。因此,目前亟需一种新型的光声重建算法,实现基于二维矩阵声学换能器的光声有限角度探测下的精确重建成像。Photoacoustic imaging is an emerging imaging technique that offers potential perspectives and opportunities for clinical imaging. Photoacoustic tomography is an important branch of photoacoustic imaging, and its advantage lies in the deep imaging depth, which can reach several centimeters, which meets the basic needs of clinical imaging. At present, photoacoustic tomography based on annular array acoustic transducer (full angle detection) has been used for breast examination. However, the annular acoustic detector is limited by its inherent shape and structure, and it is difficult to be used for photoacoustic imaging and imaging of more parts. clinical examination. The acoustic transducer based on hand-held (limited angle detection) has the advantage of being flexible and portable, and at the same time, it is easy to combine with ultrasound imaging commonly used in clinical practice, which is the development trend of photoacoustic tomography. The most notable feature of photoacoustic tomography that is different from other photoacoustic imaging techniques is that photoacoustic tomography needs to reconstruct the collected radio frequency data to obtain photoacoustic images. Currently, the commonly used reconstruction methods include time inversion method and filtered back projection method. , these two methods have good effect on photoacoustic tomography imaging with full-angle detection; however, for hand-held acoustic transducers, because only signals from a limited angle are collected, the above two methods are difficult to achieve accurate reconstruction imaging. On the other hand, the two-dimensional matrix acoustic transducer is an emerging handheld acoustic transducer that can directly perform three-dimensional imaging, and there is no method that can reconstruct the two-dimensional matrix acoustic transducer. Therefore, a new type of photoacoustic reconstruction algorithm is urgently needed to realize accurate reconstruction imaging under the limited angle detection of photoacoustics based on two-dimensional matrix acoustic transducers.
发明内容SUMMARY OF THE INVENTION
本发明的目的在于针对上述已有技术的不足,提供一种基于频域波数域的光声断层成像重建方法,该方法适用于二维矩阵声学换能器,可以在频率域和波数域内进行光声信号的三维重建,同时降低了有限角度下信号采集不全的影响,重建计算量较小,此外由于不是基于对时域信号的空间投影,大大减少了投影伪迹的影响。The purpose of the present invention is to provide a method for reconstructing photoacoustic tomography based on the frequency domain and wavenumber domain, which is suitable for a two-dimensional matrix acoustic transducer, and can perform optical imaging in the frequency domain and the wavenumber domain. The three-dimensional reconstruction of the acoustic signal also reduces the influence of incomplete signal acquisition under a limited angle, and the reconstruction calculation amount is small. In addition, because it is not based on the spatial projection of the time domain signal, the influence of projection artifacts is greatly reduced.
为了实现上述目的,本发现的基于频域波数域的光声断层成像重建方法,包含以下步骤:In order to achieve the above purpose, the photoacoustic tomography reconstruction method based on the frequency domain and wavenumber domain of the present invention includes the following steps:
(1)、获取二维矩阵声学换能器采集到的射频数据R(x,y,z=0,t),以及二维矩阵声学换能器的系统参数和待测物体的声速分布V(z′)。其中二维矩阵声学换能器是基于线阵的超声换能器,射频数据R(x,y,z=0,t)是实时采集的或事先保存好的,x,y是沿二维矩阵声学换能器的位置坐标,且x,y是相互垂直的,z是垂直二维矩阵声学换能器方向的位置坐标,t是表示时间顺序的坐标,二维矩阵声学换能器的系统参数为二维矩阵声学换能器的采样频率fs、二维矩阵声学换能器的阵元数量n、二维矩阵声学换能器的阵元间距pt。(1) Acquire the radio frequency data R (x, y, z=0, t) collected by the two-dimensional matrix acoustic transducer, as well as the system parameters of the two-dimensional matrix acoustic transducer and the sound velocity distribution V ( z'). The two-dimensional matrix acoustic transducer is an ultrasonic transducer based on a linear array, the radio frequency data R(x, y, z=0, t) is collected in real time or saved in advance, and x, y are along the two-dimensional matrix The position coordinates of the acoustic transducer, and x, y are perpendicular to each other, z is the position coordinate of the vertical two-dimensional matrix acoustic transducer direction, t is the coordinate representing the time sequence, and the system parameters of the two-dimensional matrix acoustic transducer is the sampling frequency fs of the two-dimensional matrix acoustic transducer, the number n of the array elements of the two-dimensional matrix acoustic transducer, and the array element spacing pt of the two-dimensional matrix acoustic transducer.
(2)、对采集到的射频数据R(x,y,z=0,t)进行时间增益补偿,得到补偿射频数据s(x,y,z=0,t)。其中时间增益补偿的具体方法为将射频数据R(x,y,z=0,t)的每一列上的数值乘以加权函数Y(t),Y(t)=at+1。即s(x,y,z=0,t)=R(x,y,z=0,t)×(at+1),1<a<5;由于a大于1,随着时间的增大,射频数据会被相应地方法,以抵消声学信号在传播过程中的损失。(2) Perform time gain compensation on the collected radio frequency data R (x, y, z=0, t) to obtain compensated radio frequency data s (x, y, z=0, t). The specific method of time gain compensation is to multiply the value on each column of the radio frequency data R(x, y, z=0, t) by the weighting function Y(t), where Y(t)=at+1. That is, s(x, y, z=0, t)=R(x, y, z=0, t)×(at+1), 1<a<5; since a is greater than 1, it increases with time , the RF data will be processed accordingly to counteract the loss of the acoustic signal during propagation.
(3)、对补偿射频数据s(x,y,z=0,t)按x,y和t进行三维傅里叶变换,得到频域数据Φ(kx,ky,z=0,f),再对Φ((kx,ky,z=0,f)进行插值,得到空间波数域数据Φ′(kx,ky,kz,t=0),其中kx是沿x方向的波数,ky是沿y方向的波数,kz是沿z方向的波数,f是频率。由波动方程可知,z=0平面(二维矩阵声学换能器所处位置)的频域数据Φ(kx,ky,z=0,f)与探测平面内的初始位置(t=0)的空间波数域数据Φ′(kx,ky,kz,t=0)相差一个相位因子因此对Φ(kx,ky,z=0,f)进行插值即可得到Φ′(kx,ky,kz,t=0);此处需要强调的是频域数据Φ(kx,ky,z=0,f)与原始采集到的射频数据互为傅里叶变换对,而空间波数域数据Φ′(kx,ky,kz,t=0)与待重建的图像互为傅里叶变换对。作为优选的,插值方法是Φ′(kx,ky,kz,t=0)=∫Φ(kx,ky,z=0,f)M(kx,ky,kz,f)df,其中: (3) Perform three-dimensional Fourier transform on the compensated radio frequency data s(x, y, z=0, t) according to x, y and t to obtain frequency domain data Φ(k x , ky , z=0, f ), and then interpolate Φ((k x , ky , z=0, f) to obtain spatial wavenumber domain data Φ′(k x , ky , k z , t=0), where k x is the direction along x The wave number in the direction, ky is the wave number along the y direction, k z is the wave number along the z direction, and f is the frequency. It can be known from the wave equation that the frequency domain of the z=0 plane (where the two-dimensional matrix acoustic transducer is located) The data Φ(k x , ky , z=0, f) differs by one from the spatial wavenumber domain data Φ′(k x , ky , k z , t=0) of the initial position (t=0) in the detection plane Phase factor Therefore, Φ(k x , ky , z=0, f) can be interpolated to obtain Φ′(k x , ky , k z , t=0); what needs to be emphasized here is the frequency domain data Φ(k x , ky , z=0, f) and the originally collected radio frequency data are Fourier transform pairs, while the spatial wavenumber domain data Φ′ (k x , ky , k z , t=0) and the data to be reconstructed The images are Fourier transform pairs of each other. Preferably, the interpolation method is Φ'(k x , ky , k z , t=0)=∫Φ(kx, ky, z=0, f)M(k x , ky , k z , f) df, where:
(4)、对空间频域数据Φ′(kx,ky,kz,t=0)进行三维傅里叶逆变换,得到空间幅度数据s′(x,y,z,t=0)。(4), perform three-dimensional inverse Fourier transform on spatial frequency domain data Φ' (k x , ky , k z , t=0) to obtain spatial amplitude data s' (x, y, z, t=0) .
(5)、对空间幅度数据s′(x,y,z,t=0)进行解调取包络处理,再进行对比度调节,最终获得光声重建图像s*,其中解调取包络的方法为正交解调法或希尔伯特解调法,对比度调节方法,可以是对数压缩法,也可以是将解包络后得到的数据做n次幂,其中0<n<2。(5) Demodulate the spatial amplitude data s' (x, y, z, t=0) to obtain the envelope, and then adjust the contrast, and finally obtain the photoacoustic reconstructed image s*, in which the demodulation takes the envelope The method is the quadrature demodulation method or the Hilbert demodulation method, and the contrast adjustment method can be a logarithmic compression method, or the data obtained after de-enveloping can be raised to the power of n, where 0<n<2.
(6)、对声速分布v(z′)进行优化,将优化得到的V2(z′)数据代入步骤(3)至步骤(5)中,得到最终组织对比度CTR最高的光声重建图像S2*;(6) Optimizing the sound velocity distribution v(z'), and substituting the optimized V 2 (z') data into steps (3) to (5) to obtain a photoacoustic reconstructed image S with the highest tissue contrast CTR 2 *;
其中声速分布V(z′)进行优化的具体步骤为:The specific steps for optimizing the sound velocity distribution V(z') are:
(1)、设置优化次数计数器t=0,设置最大优化次数T,T的取值范围为3-10,随机生成N个声速分布V1(z′)作为初始样本集合K1,N的取值范围为300-1000,其中每个声速分布中声速的范围随机在1350-1650m/s以内;(1), set the optimization times counter t=0, set the maximum optimization times T, the value range of T is 3-10, and randomly generate N sound velocity distributions V 1 (z′) as the initial sample set K 1 , the value of N is The value range is 300-1000, where the range of sound speed in each sound speed distribution is randomly within 1350-1650m/s;
(2)、对上述步骤中的每个声速分布V1(z′)对光声图像进行重建,重建步骤为前文所述的光声断层成像重建方法中步骤(1)至步骤(5)所述的重建方法,得到N个光声重建图像Si*,计算每个光声重建图像Si*的CTR,CTR的具体计算方式为光声重建图像Si*中目标物体与背景的灰度值之比;(2) Reconstructing the photoacoustic image for each sound velocity distribution V 1 (z′) in the above steps, and the reconstruction steps are the steps (1) to (5) in the above-mentioned photoacoustic tomography reconstruction method. According to the reconstruction method described above, N photoacoustic reconstructed images Si* are obtained, and the CTR of each photoacoustic reconstructed image Si * is calculated. The specific calculation method of CTR is the grayscale of the target object and the background in the photoacoustic reconstruction image Si*. ratio of values;
(3)、对N个计算得到的CTR按数值大小进行降序排序,选择前30%较大CTR对应的声速分布构成样本集合Ka,选择前30%-60%较大CTR对应的声速分布构成样本集合Kb,Ka和Kb的样本数量均为0.3N;(3) Sort the N calculated CTRs in descending order of numerical value, select the sound velocity distribution corresponding to the first 30% larger CTRs to form the sample set Ka, and select the sound velocity distribution corresponding to the first 30%-60% larger CTRs to form The number of samples in the sample set K b , K a and K b are all 0.3N;
(4)、从Ka中随机选择一个声速分布样本Va(z′),从Kb中随机选择一个声速分布样本Vb(z′),将两个声速分布样本的均值作为融合后的声速分布Vc(z′);(4) Randomly select a sound speed distribution sample V a (z') from Ka, randomly select a sound speed distribution sample V b ( z' ) from K b , and take the mean value of the two sound speed distribution samples as the fused Sound velocity distribution V c (z');
(5)、重复步骤(4),得到0.2N个融合后的声速分布Vc(z′),将步骤(4)Ka和Kb中未被选择的声速分布与融合后的声速分布Vc(z′)一起构成样本集合K2,K2的样本数量均为0.4N;(5) Repeat step (4) to obtain 0.2N fused sound velocity distributions V c (z′), and compare the unselected sound velocity distributions in step (4 ) Ka and K b with the fused sound velocity distribution V c (z') together constitute a sample set K 2 , and the number of samples in K 2 is 0.4N;
(6)、以K2作为初始样本集合重复步骤(2)-(6),不断更新声速分布的样本集合;(6), repeat steps (2)-(6) with K 2 as the initial sample set, continuously update the sample set of the sound velocity distribution;
(7)、当t=T时,完成对声速分布V(z′)的优化,选择最终样本集合中CTR最大的样本作为最终的声速分布V2(z′)。(7) When t=T, the optimization of the sound velocity distribution V(z′) is completed, and the sample with the largest CTR in the final sample set is selected as the final sound velocity distribution V 2 (z′).
本发明与现有技术相比,具有如下有益效果:Compared with the prior art, the present invention has the following beneficial effects:
对于基于手持式的二维矩阵声学换能器的光声断层重建,本发明提出的重建方法具有重建图像分辨率高、信噪比高、伪影少,重建计算速度快的优点。For the photoacoustic tomography reconstruction based on the hand-held two-dimensional matrix acoustic transducer, the reconstruction method proposed in the present invention has the advantages of high reconstructed image resolution, high signal-to-noise ratio, less artifacts, and fast reconstruction calculation speed.
附图说明Description of drawings
图1是本发明的流程图;Fig. 1 is the flow chart of the present invention;
图2是二维矩阵声学换能器采集示意图;Figure 2 is a schematic diagram of a two-dimensional matrix acoustic transducer acquisition;
图3是基于仿真的点声源射频数据重建结果;Fig. 3 is the reconstruction result of point sound source RF data based on simulation;
图4是基于仿真的血管射频数据重建结果的二维截面;FIG. 4 is a two-dimensional cross-section of the reconstruction result of the vascular radiofrequency data based on simulation;
图5是基于真实探测的血管模型射频数据重建结果的二维截面。FIG. 5 is a two-dimensional cross-section of the reconstruction result of the RF data of the blood vessel model based on the real detection.
具体实施方式Detailed ways
为了使本发明的目的、技术方案及优点更加清楚明白,以下结合附图及实施例,对本发明进行进一步详细说明。In order to make the objectives, technical solutions and advantages of the present invention clearer, the present invention will be further described in detail below with reference to the accompanying drawings and embodiments.
如图1所示,是本发明一种基于频域波数域的光声断层成像重建方法的流程图。As shown in FIG. 1 , it is a flow chart of a photoacoustic tomography reconstruction method based on the frequency domain and wavenumber domain of the present invention.
步骤(1),获取二维矩阵声学换能器采集到的射频数据R(x,y,z=0,t),以及二维矩阵声学换能器的系统参数和待测物体的声速分布V(z′)。其中二维矩阵声学换能器是基于线阵的超声换能器,射频数据R(x,y,z=0,t)是实时采集的或事先保存好的;如图2所示,是二维矩阵声学换能器采集示意图,x,y是沿二维矩阵声学换能器的位置坐标,且x,y是相互垂直的,z是垂直二维矩阵声学换能器方向的位置坐标,t是表示时间顺序的坐标;二维矩阵声学换能器的系统参数为二维矩阵声学换能器的采样频率fs、二维矩阵声学换能器的阵元数量n、二维矩阵声学换能器的阵元间距pt、声速分布v2(z′)。重建图像的宽度为pt×n,重建图像的高度由射频数据的长度、二维矩阵声学换能器的采样频率fs以及声速共同决定。Step (1), obtain the radio frequency data R (x, y, z=0, t) collected by the two-dimensional matrix acoustic transducer, as well as the system parameters of the two-dimensional matrix acoustic transducer and the sound velocity distribution V of the object to be measured (z'). The two-dimensional matrix acoustic transducer is an ultrasonic transducer based on a linear array, and the radio frequency data R(x, y, z=0, t) is collected in real time or saved in advance; as shown in Figure 2, the two Schematic diagram of the acquisition of the 2D matrix acoustic transducer, x, y are the position coordinates along the 2D matrix acoustic transducer, and x, y are perpendicular to each other, z is the position coordinate perpendicular to the direction of the 2D matrix acoustic transducer, t is the coordinate representing the time sequence; the system parameters of the two-dimensional matrix acoustic transducer are the sampling frequency fs of the two-dimensional matrix acoustic transducer, the number of elements n of the two-dimensional matrix acoustic transducer, the two-dimensional matrix acoustic transducer The array element spacing pt and the sound velocity distribution v 2 (z'). The width of the reconstructed image is pt×n, and the height of the reconstructed image is determined by the length of the radio frequency data, the sampling frequency fs of the two-dimensional matrix acoustic transducer, and the speed of sound.
步骤(2),对采集到的射频数据R(x,y,z=0,t)进行时间增益补偿,得到补偿射频数据s(x,y,z=0,t)。其中时间增益补偿的具体方法为将射频数据R(x,y,z=0,t)的每一列上的数值乘以加权函数Y(t),Y(t)=2t+1。即s(x,y,z=0,t)=R(x,y,z=0,t)×(2t+1);随着时间的增大,射频数据会被相应地方法,以抵消声学信号在传播过程中的损失。In step (2), time gain compensation is performed on the collected radio frequency data R(x, y, z=0, t) to obtain compensated radio frequency data s (x, y, z=0, t). The specific method of time gain compensation is to multiply the value on each column of the radio frequency data R(x, y, z=0, t) by the weighting function Y(t), Y(t)=2t+1. That is, s(x, y, z=0, t)=R(x, y, z=0, t)×(2t+1); as time increases, the radio frequency data will be counteracted accordingly to cancel The loss of an acoustic signal during propagation.
步骤(3),再对补偿射频数据s(x,y,z=0,t)按x和t进行二维傅里叶变换,得到频域数据Φ(kx,ky,z=0,f),再对Φ((kx,ky,z=0,f)进行插值,得到空间波数域数据Φ′(kx,ky,kz,t=0),其中kx是沿x方向的波数,ky是沿y方向的波数,kz是沿z方向的波数,f是频率。Step (3), perform two-dimensional Fourier transform on the compensated radio frequency data s(x, y, z=0, t) according to x and t to obtain frequency domain data Φ(k x , ky , z=0, f), and then interpolate Φ((k x , ky , z=0, f) to obtain spatial wavenumber domain data Φ′(k x , ky , k z , t=0), where k x is the edge The wave number in the x direction, ky is the wave number in the y direction, k z is the wave number in the z direction, and f is the frequency.
由波动方程可知,z=0平面(二维矩阵声学换能器所处位置)的频域数据Φ(kx,ky,z=0,f)与探测平面内的初始位置(t=0)的空间波数域数据Φ′(kx,ky,kz,t=0)相差一个相位因子因此对Φ(kx,ky,z=0,f)进行插值即可得到Φ′(kx,ky,kz,t=0)。It can be known from the wave equation that the frequency domain data Φ(k x , ky , z=0, f) of the z=0 plane (where the two-dimensional matrix acoustic transducer is located) is related to the initial position in the detection plane (t=0 ) of the spatial wavenumber domain data Φ′(k x , ky , k z , t=0) differs by a phase factor Therefore, Φ'(k x , ky , k z , t=0) can be obtained by interpolating Φ(k x , ky , z=0, f).
此处需要强调的是频域数据Φ(kx,ky,z=0,f)与原始采集到的射频数据互为傅里叶变换对,而空间波数域数据Φ′(kx,ky,kz,t=0)与待重建的图像互为傅里叶变换对。因此建立了已知数据和待重建图像之间的联系。作为优选的,插值方法为加权反演插值:It should be emphasized here that the frequency domain data Φ(k x , ky , z=0, f) and the originally collected RF data are mutual Fourier transform pairs, while the spatial wavenumber domain data Φ′(k x , k y , k z , t=0) and the image to be reconstructed are mutual Fourier transform pairs. A link between the known data and the image to be reconstructed is thus established. Preferably, the interpolation method is weighted inversion interpolation:
Φ′(kx,ky,kz,t=0)=∫Φ(kx,ky,z=0,f)M(kx,ky,kz,f)df,其中:Φ'(k x , ky , k z , t=0)=∫Φ(k x , ky , z=0, f)M(k x , ky , k z , f)df, where:
步骤(4),再对空间频域数据Φ′(kx,ky,kz,t=0)进行二维傅里叶逆变换,得到空间幅度数据s′(x,y,z,t=0)。Step (4), perform two-dimensional inverse Fourier transform on the spatial frequency domain data Φ'(k x , ky , k z , t=0) to obtain spatial amplitude data s'(x, y, z, t =0).
步骤(5),采用希尔伯特解调法对空间幅度数据s′(x,y,z,t=0)进行解调取包络处理,再进行对数压缩调节对比度,获得光声重建图像s*。Step (5), using the Hilbert demodulation method to demodulate the spatial amplitude data s' (x, y, z, t=0) to obtain envelope processing, and then perform logarithmic compression to adjust the contrast to obtain photoacoustic reconstruction image s*.
步骤(6),对s*计算组织对比度CTR,CTR是图像中组织的图像亮度与图像中背景位置的图像亮度的比值,对声速分布v(z′)进行优化,将优化得到的V2(z′)数据代入步骤(3)至步骤(5)中,得到最终组织对比度CTR最高的光声重建图像S2*;Step (6), calculate the tissue contrast CTR for s*, CTR is the ratio of the image brightness of the tissue in the image to the image brightness of the background position in the image, optimize the sound velocity distribution v(z'), and optimize the obtained V 2 ( z') data are substituted into steps (3) to (5) to obtain a photoacoustic reconstructed image S 2 * with the highest final tissue contrast CTR;
其中声速分布v(z′)进行优化的具体步骤为:The specific steps for optimizing the sound velocity distribution v(z') are as follows:
(1)、设置优化次数计数器t=0,设置最大优化次数T,T的取值范围为3-10,随机生成N个声速分布V1(z′)作为初始样本集合K1,N的取值范围为300-1000,其中每个声速分布中声速的范围随机在1350-1650m/s以内;(1), set the optimization times counter t=0, set the maximum optimization times T, the value range of T is 3-10, and randomly generate N sound velocity distributions V 1 (z′) as the initial sample set K 1 , the value of N is The value range is 300-1000, where the range of sound speed in each sound speed distribution is randomly within 1350-1650m/s;
(2)、对上述步骤中的每个声速分布V1(z′)对光声图像进行重建,重建步骤为前文所述的光声断层成像重建方法中步骤(1)至步骤(5)所述的重建方法,得到N个光声重建图像S1*,计算每个光声重建图像S1*的CTR,CTR的具体计算方式为光声重建图像S1*中目标物体与背景的灰度值之比;(2) Reconstructing the photoacoustic image for each sound velocity distribution V 1 (z′) in the above steps, and the reconstruction steps are the steps (1) to (5) in the above-mentioned photoacoustic tomography reconstruction method. According to the reconstruction method described above, N photoacoustic reconstructed images S 1 * are obtained, and the CTR of each photoacoustic reconstructed image S 1 * is calculated. The specific calculation method of CTR is the grayscale of the target object and the background in the photoacoustic reconstructed image S 1 *. ratio of values;
(3)、对N个计算得到的CTR按数值大小进行降序排序,选择前30%较大CTR对应的声速分布构成样本集合Ka,选择前30%-60%较大CTR对应的声速分布构成样本集合Kb,Ka和Kb的样本数量均为0.3N;(3) Sort the N calculated CTRs in descending order of numerical value, select the sound velocity distribution corresponding to the first 30% larger CTRs to form the sample set Ka, and select the sound velocity distribution corresponding to the first 30%-60% larger CTRs to form The number of samples in the sample set K b , K a and K b are all 0.3N;
(4)、从Ka中随机选择一个声速分布样本Va(z′),从Kb中随机选择一个声速分布样本Vb(z′),将两个声速分布样本的均值作为融合后的声速分布Vc(z′);(4) Randomly select a sound speed distribution sample V a (z') from Ka, randomly select a sound speed distribution sample V b ( z' ) from K b , and take the mean value of the two sound speed distribution samples as the fused Sound velocity distribution V c (z');
(5)、重复步骤(4),得到0.2N个融合后的声速分布Vc(z′),将步骤(4)Ka和Kb中未被选择的声速分布与融合后的声速分布Vc(z′)一起构成样本集合K2,K2的样本数量均为0.4N;(5) Repeat step (4) to obtain 0.2N fused sound velocity distributions V c (z′), and compare the unselected sound velocity distributions in step (4 ) Ka and K b with the fused sound velocity distribution V c (z') together constitute a sample set K 2 , and the number of samples in K 2 is 0.4N;
(6)、以K2作为初始样本集合重复步骤(2)-(6),不断更新声速分布的样本集合;(6), repeat steps (2)-(6) with K 2 as the initial sample set, continuously update the sample set of the sound velocity distribution;
(7)、当t=T时,完成对声速分布V(z′)的优化,选择最终样本集合中CTR最大的样本作为最终的声速分布V2(z′)。(7) When t=T, the optimization of the sound velocity distribution V(z′) is completed, and the sample with the largest CTR in the final sample set is selected as the final sound velocity distribution V 2 (z′).
如图3所示,是基于仿真的点声源射频数据重建结果,原始图像是通过k-wave仿真软件生成的,其中采样频率fs=30Mhz、二维矩阵声学换能器的阵元数量n=192、二维矩阵声学换能器的阵元间距pt=0.2mm、声速v=1540m/s。利用二维矩阵声学换能器采集到射频数据R(x,y,z=0,t),分别进行时间反演重建和本发明方法的重建;结果表明,本发明方法的重建结果的横向分辨率显著优于时间反演重建方法。As shown in Figure 3, it is the reconstruction result of point sound source radio frequency data based on simulation. The original image is generated by k-wave simulation software, where the sampling frequency fs=30Mhz, the number of elements of the two-dimensional matrix acoustic transducer n= 192. The array element spacing of the two-dimensional matrix acoustic transducer is pt=0.2mm, and the speed of sound v=1540m/s. The radio frequency data R(x, y, z=0, t) is collected by the two-dimensional matrix acoustic transducer, and the time-reversal reconstruction and the reconstruction of the method of the present invention are carried out respectively; the results show that the lateral resolution of the reconstruction result of the method of the present invention is The rate is significantly better than the time-reversal reconstruction method.
图4所示,是基于仿真的血管射频数据重建结果的二维截面,原始数据是通过k-wave仿真软件生成的,其中采样频率fs=30Mhz、二维矩阵声学换能器的阵元数量n=192、二维矩阵声学换能器的阵元间距pt=0.2mm、声速v=z+1500m/s。利用二维矩阵声学换能器采集到射频数据R(x,y,z=0,t),分别进行滤波反投影重建和本发明方法的重建;结果表明,本发明方法的重建图像伪影远远小于滤波反投影重建,同时信噪比显著优于滤波反投影重建方法。Figure 4 shows a two-dimensional cross-section of the reconstruction result of the simulated blood vessel radio frequency data. The original data is generated by k-wave simulation software, where the sampling frequency is fs=30Mhz, and the number of elements of the two-dimensional matrix acoustic transducer is n. =192, the array element spacing of the two-dimensional matrix acoustic transducer is pt=0.2mm, and the speed of sound v=z+1500m/s. The radio frequency data R(x, y, z=0, t) is collected by the two-dimensional matrix acoustic transducer, and the filtered back-projection reconstruction and the reconstruction of the method of the present invention are respectively performed; the results show that the reconstructed image artifacts of the method of the present invention are far Much smaller than the filtered backprojection reconstruction, while the signal-to-noise ratio is significantly better than the filtered backprojection reconstruction method.
图5是基于真实探测的血管模型射频数据重建结果的二维截面,原始数据是利用血管模型实际采集得到的,其中采样频率fs=50Mhz、二维矩阵声学换能器的阵元数量n=192、二维矩阵声学换能器的阵元间距pt=0.25mm、声速v=z+1500m/s。利用二维矩阵声学换能器采集到射频数据R(x,y,z=0,t),分别进行滤波反投影重建和本发明方法的重建;结果表明,本发明方法的重建图像伪影远远小于滤波反投影重建,同时具有较好的轴向分辨率。Figure 5 is a two-dimensional cross-section of the reconstruction result of the radio frequency data of the blood vessel model based on the real detection. The original data is actually collected by using the blood vessel model, where the sampling frequency is fs=50Mhz, and the number of elements of the two-dimensional matrix acoustic transducer is n=192 , The array element spacing of the two-dimensional matrix acoustic transducer is pt=0.25mm, and the sound speed is v=z+1500m/s. The radio frequency data R(x, y, z=0, t) is collected by the two-dimensional matrix acoustic transducer, and the filtered back-projection reconstruction and the reconstruction of the method of the present invention are respectively performed; the results show that the reconstructed image artifacts of the method of the present invention are far Much smaller than filtered back-projection reconstruction, while having better axial resolution.
需要说明的是,在不冲突的情况下,本发明中的实施例及实施例中的特征可以相互组合。尽管本发明已进行了一定程度的描述,明显地,在不脱离本发明的精神和范围的条件下,可进行各个条件的适当变化。可以理解,本发明不限于所述实施方案,而归于权利要求的范围,其包括所述每个因素的等同替换。It should be noted that the embodiments of the present invention and the features of the embodiments may be combined with each other under the condition of no conflict. Although this invention has been described to a certain extent, it will be apparent that suitable changes in various conditions may be made without departing from the spirit and scope of the invention. It is to be understood that the invention is not limited to the embodiments described, but is to be included within the scope of the claims, which include equivalents for each of the elements described.
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