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CN111027157A - Design method of flexible support system of double-limb combined cross-section bending column of dust remover box body - Google Patents

Design method of flexible support system of double-limb combined cross-section bending column of dust remover box body Download PDF

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CN111027157A
CN111027157A CN201911323362.3A CN201911323362A CN111027157A CN 111027157 A CN111027157 A CN 111027157A CN 201911323362 A CN201911323362 A CN 201911323362A CN 111027157 A CN111027157 A CN 111027157A
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bending
limb
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connecting rod
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CN111027157B (en
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王登峰
赵婧同
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Jiangnan University
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Abstract

The invention discloses a design method of a flexible support system of a double-limb combined cross-section bending column of a dust remover box body, belonging to the technical field of structural engineering. The invention provides a design method of a flexible support system of a bending column with a double-limb combined section of a box body of a dust remover, which can be used for designing the flexible support system consisting of a support rod and a connecting rod, is reliable and reasonable in design and has extremely high application prospect in the aspect of designing the flexible support system of the bending column with the double-limb combined section of the box body of the dust remover.

Description

Design method of flexible support system of double-limb combined cross-section bending column of dust remover box body
Technical Field
The invention relates to a design method of a flexible support system of a double-limb combined cross-section bending column of a dust remover box body, belonging to the technical field of structural engineering.
Background
The dust remover is an important environment-friendly device which is widely applied to industries such as electric power, metallurgy, chemical industry, building materials and the like and is used for eliminating smoke dust. The capture and collection of the smoke dust particles are all completed in the box body of the dust remover, so the box body is one of the most important process parts of the dust remover. The enclosure structure of the medium and large dust collector box bodies generally adopts a stiffening wallboard-H-shaped section upright post structure system or a stiffening wallboard-rectangular pipe section upright post structure system.
In order to ensure the tightness, the wall plate in the stiffening wall plate-H-shaped section upright post structure system or the stiffening wall plate-rectangular pipe section upright post structure system is continuously welded and connected with one side of the upright post. When the wallboard in the box receives the horizontal load that negative pressure and wind load formed, the horizontal load that acts on the wallboard can transmit and distribute to the stand for the stand bears the horizontal distribution load, and simultaneously, axial pressure is born at the stand top, therefore, the stand in the wallboard-H shape cross-section stand structural system of putting more energy into or the wallboard-rectangular pipe cross-section stand structural system of putting more energy into is actually a buckling component, i.e. the buckling post.
Due to the process requirements in the aspect of discharge distance and the design consideration in the aspects of strength and stability when bearing larger load, the upright columns in the stiffening wallboard-H-shaped section upright column structure system or the stiffening wallboard-rectangular tube section upright column structure system of some dust collectors can be designed into a wider section, namely a double-limb combined section is adopted. Two single-limb bending columns with double-limb combined sections are connected at the neutral axis position by adopting a stiffening connecting wallboard with an angle steel stiffening rib. In order to reduce the slenderness ratio of the single-limb bending column in the double-limb combined section column and improve the rigidity of the double-limb combined section column, a support rod (usually a hot-rolled circular steel tube) perpendicular to the direction of the box body wall plate and the connecting wall plate between two limbs is arranged on the whole double-limb combined section column to provide transverse support for the two single-limb bending columns.
In order to provide support in a transverse load action plane for two single-limb bending columns at the same time, the arrangement modes of the support rods are mainly two, one is a conventional support mode that the support rods are directly welded on the two single-limb bending columns in the double-limb combined section column (if the support rods are H-shaped section single-limb bending columns, the support rods directly act on the flange middle points of the single-limb bending columns), and in the support mode, the support rods independently form a support system, namely the conventional flexible support system of the double-limb combined section bending columns of the dust remover box body; the other type is a special flexible supporting system which is characterized in that connecting rods (usually hot rolled channel steel) are connected between single-limb bending columns, a support rod does not directly act on the single-limb bending columns but is supported at the middle point of the connecting rods between the two single-limb bending columns, the support rod is indirectly connected with the middle point of the connecting rods to form a supporting mode of translational restraint in the direction vertical to the wall plate of the two single-limb bending columns, and in the supporting mode, the support rod and the connecting rods jointly form a supporting system, namely the special flexible supporting system of the double-limb combined section bending column of the dust remover box body.
At present, when a stiffening wallboard-H-shaped section upright column structure system or a stiffening wallboard-rectangular pipe section upright column structure system of a dust remover box body is designed, in order to ensure the integral stability of the structure and the reliability and effectiveness of a supporting system, the flexible supporting system of the double-limb combined section bending column needs to be structurally designed. However, in the prior art, only a design method for a conventional axial compression column flexible support system (see the reference in the specification of steel structure stability design manual (the third edition)) exists, and a design method for a bending column special flexible support system does not exist, which greatly increases the actual design and manufacturing difficulty of the special flexible support system. Therefore, a design method of a special flexible support system of the double-limb combined cross-section bending column is urgently needed to be developed.
Disclosure of Invention
[ problem ] to
The invention aims to provide a structural design method of a flexible support system of a double-limb combined cross-section bending column of a dust remover box body.
[ solution ]
In order to solve the technical problem, the invention provides a design method of a flexible support system of a double-limb combined cross-section bending column of a box body of a dust remover, which comprises the following steps:
the method comprises the following steps: designing a double-limb combined section bending column of a flexible supporting system according to requirements, and preliminarily trying to set the preset sectional area value of a middle support rod in the flexible supporting system to be A1The preset value of the minimum turning radius of the cross section is i1(ii) a Determining the total height L of the upright column, the height L of the support column and the length L of the middle support rod of the double-limb combined section bending column of the flexible support system1The value of (d); calculating the initial supporting rigidity gamma of the flexible supporting system according to the preset value and the numerical value0
Initial support stiffness γ0Calculated according to the following formula:
Figure BDA0002327732250000021
where ζ is a coefficient in which the nonlinear influence of the decrease in the rigidity of the flexible support system with the increase in the supporting force is taken into consideration, and E is the structural steel elastic modulus, and the above formula is calculated such that E is 2.06 × 105N/mm2
The flexible supporting system is made of Q235 steel or Q345 steel, and the middle supporting rod is a type a section or a type b section of the axial compression member;
when the material of the flexible supporting system is Q235 steel and the middle support rod is a class a section of the axial center compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000022
when the material of the flexible supporting system is Q235 steel and the middle support rod is a b-type section of the axial center compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000023
when the material of the flexible supporting system is Q345 steel and the middle support rod is a class a section of the axial center compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000031
when the material of the flexible supporting system is Q345 steel and the middle support rod is a b-type section of the axial compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000032
in the formula, λ1The length-to-thickness ratio of the middle support rod is obtained;
length-thin ratio lambda of middle stay bar1Satisfies the following formula:
λ1=l1/i1
among the above values, the sectional area of the middle stay bar is preset value A1In mm unit2Length of middle stay bar l1The unit of (1) is mm, the unit of the preset value i of the minimum turning radius of the cross section of the strut is mm, and the unit of the elastic modulus E of the material is N/mm2Initial support stiffness γ0The unit of (A) is N/mm;
step two: determining an axial pressure design value N borne by the top of a double-limb combined cross-section bending column of a flexible supporting system to be designed, transversely and uniformly distributing load design values q borne by a span, and calculating to obtain the maximum supporting force F of the single-limb bending column according to the axial pressure N, the transversely and uniformly distributed load q, the linear rigidity K of the single-limb bending column, the height l of a supporting column, the supporting rigidity gamma of the flexible supporting system and the number N of middle supports;
when n is 1, the maximum supporting force F satisfies the following formula:
F=γΔAB
in the formula,. DELTA.ABThe deflection of the single-limb bending column at the middle supporting position is obtained by taking gamma as gamma in the formula during initial calculation0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000033
Deflection delta of single-limb bending column at middle supportABSatisfies the following formula:
Figure BDA0002327732250000034
in which C and S are single-limb bending columnsFlexural rigidity coefficient, MFBAThe bending moment at the fixed end of the single-limb bending column segment is hinged at one end and fixedly connected at one end, K is the linear rigidity of the single-limb bending column, and L is L/2;
in the above numerical values, the unit of the height l of the support column is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection delta of the single-limb bending column at the middle support partABThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is 2, the maximum supporting force F satisfies the following formula:
F=γΔAB
in the formula,. DELTA.ABThe deflection of the single-limb bending column at the middle L/3 and 2L/3 column heights is obtained by taking gamma as gamma in the formula during initial calculation0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000041
Middle L/3 and 2L/3 column height displacement deltaABSatisfies the following formula:
Figure BDA0002327732250000042
wherein C and S are flexural rigidity coefficient of single-limb bending column, MFBAFor bending the fixed end bending moment of a column segment for a single limb with one hinged end and one fixed end, MFBCThe fixed end bending moment of the bending component is fixedly connected with the two ends, K is the linear rigidity of the single-limb bending column, and L is equal to L/3;
in the numerical values, the unit of the height L of the support columns is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection delta of the single-limb bending column at the middle L/3 and 2L/3 column heightsABThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is 3, the maximum supporting force F satisfies the following formula:
F=γΔAC
in the formula,. DELTA.ACFor single limb bendingThe mid-span deflection is calculated by taking gamma as gamma in the formula0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000043
Mid-span deflection delta of single-limb bending columnACSatisfies the following formula:
ΔAC=ΔABBC
Figure BDA0002327732250000044
in the formula, c11=K(C+S),c12=-γl/2,c13=N-γl/2-2K(C+S)/l,c21=KC,c22=3γl/2-N,c23=γl/2-K(C+S)/l,c31=K(2C2-S2)/C,c32=K(S2-C2)/(Cl),c33=-K(C+S)/l,d1=-ql2/2,d2=3ql2/2-MFBC,d3=-MFBC-MFBA;θAFor bending the column corner, theta, at the column top for a single limbBFor single limb bending column corner, delta, at quarter column heightABAnd ΔACRespectively the deflection of one fourth of the single-limb bending column and the deflection of one half of the column height (because of symmetry, the column corner at the column top of the single-limb bending column is equal to the column corner at the column bottom of the single-limb bending column, the column corner at the column height of one fourth of the single-limb bending column is equal to the column corner at the column height of three fourth of the single-limb bending column, the deflection of the bending column at the column height of one fourth of the single-limb bending column is equal to the deflection of the bending column at the column height of three fourth of the single-limb bending column), deltaBCThe deflection of the high part of the column is increased relative to the deflection of the high part of the column, C and S are the bending rigidity coefficient of the single-limb bending column, MFBAFor bending the fixed end bending moment of a column segment for a single limb with one hinged end and one fixed end, MFBCThe fixed end bending moment of the bending component is fixedly connected with the two ends, K is the linear rigidity of the single-limb bending column, and L is equal to L/4;
in the above numerical values, the unit of the height l of the column between the supports is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection value delta of each item of the column isAC、ΔABAnd ΔBCThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is 4, the maximum supporting force F satisfies the following formula:
F=γΔAC
in the formula,. DELTA.ACThe deflection of the single-limb bending column at the 2L/5 and 3L/5 column heights is obtained by taking gamma as gamma in the formula during initial calculation0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000051
Deflection delta of 2L/5 and 3L/5 column height of single-limb bending columnACSatisfies the following formula:
ΔAC=ΔABBC
Figure BDA0002327732250000052
ΔAB=(CθA+SθB)l/(C+S);
ΔBC=l[(2C-S)θC+SθB]/(C+S);
in the formula, a11=K(S-C),a12=2K(C-S),a13=2K(S-C),a21=K(S2-C2)+(Nl-2γl2)C,a22=K(C2-S2)+(Nl-3γl2)S,a23=γl2(S-2C),a31=-Cγl2,a32=K(C2-S2)+(Nl-2γl2)S,a33=3K(S2-C2)+(Nl-γl2)(2C-S),b1=-MFBA-MFBC,b2=-(C+S)(MFBA+2ql2),b3=-(C+S)ql2;θAFor bending the column corner, theta, at the column top for a single limbBThe column corner theta at the height of one fifth of the column is formed by pressing a single limbCThe column corner, delta, at two fifths of the height of the column for single limb bendingABThe deflection of the bending column at the height of one fifth of the bending column of the single limb (because of symmetry, the column corner at the top of the bending column of the single limb is equal to the column corner at the bottom of the bending column of the single limb, the column corner at the height of one fifth of the bending column of the single limb is equal to the column corner at the height of four fifth of the bending column of the single limb, the column corner at the height of two fifth of the bending column of the single limb is equal to the column corner at the height of three fifth of the bending column of the single limb, the deflection of the bending column at the height of one fifth of the bending column of the single limb is equal to the deflection of the bending column at the height of four fifth of the bending column of the single limb), deltaBCThe deflection of the single-limb bending column at the height of two fifths of the column is increased compared with the deflection at the height of one fifths of the column, C and S are bending rigidity coefficients of the single-limb bending column, MFBAFor bending the fixed end bending moment of a column segment for a single limb with one hinged end and one fixed end, MFBCThe fixed end bending moment of the single-limb bending column segment is fixedly connected with two ends, K is the linear rigidity of the single-limb bending column, and L is L/5;
in the above numerical values, the unit of the height l of the column between the supports is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection value delta of each item of the column isAC、ΔABAnd ΔBCIn units of mm, the displacement delta at the column heights of the middle L/5 and 4L/5ABThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is greater than 4, calculating the maximum supporting force F according to the condition that n is 4;
wherein, the bending rigidity coefficient C of the single-limb bending column meets the following formula:
Figure BDA0002327732250000061
the bending rigidity coefficient S of the single-limb bending column meets the following formula:
Figure BDA0002327732250000062
in the formula, k is a calculation coefficient;
the calculation coefficient k satisfies the following formula:
Figure BDA0002327732250000063
fixed end bending moment M of single-limb bending column segment with one hinged end and one fixed endFBAThe following formula is satisfied such that the pole segments are positive for clockwise rotation and negative for counterclockwise rotation:
Figure BDA0002327732250000064
fixed end bending moment M with two ends fixedly connected with single-limb bending column segmentFBCThe following formula is satisfied such that the pole segments are positive for clockwise rotation and negative for counterclockwise rotation:
Figure BDA0002327732250000065
the linear rigidity K of the single-limb bending column meets the following formula:
K=EIc/l;
in the formula IcThe bending moment of inertia of the section of the single-limb bending column around the bending axis of the single-limb bending column is E, and the elasticity modulus of structural steel is E;
the single-limb bending column is biaxial symmetric hot-rolled section steel or a welded combined section component;
when the single-limb bending column is hot-rolled section steel, the section inertia moment I of the single-limb bending column around the bending axis thereofcCan be obtained by directly inquiring a profile steel table;
when the single-limb bending column is a welding combined section component, if the single-limb bending column is a welding H-shaped section, the section inertia moment I of the single-limb bending column around the bending axis thereofcSatisfies the following formula:
Figure BDA0002327732250000066
wherein H is the total height of the welded H-shaped section, B is the width of the welded H-shaped section, t1For welding webs of H-section, t2The thickness of the flange of the H-shaped section;
if the single-limb bending column is the section of the welded rectangular pipe, the section inertia moment I of the single-limb bending column around the bending axis thereofcSatisfies the following formula:
Figure BDA0002327732250000071
in the formula, a1For welding the length of the cross-section of rectangular tubes parallel to the bending axis, a2The length of the side of the section of the welded rectangular tube, which is perpendicular to the bending axis side, is t ', and the thickness of the section of the welded rectangular tube is t';
if the single-limb bending column is the section of the welded circular tube, the section inertia moment I of the single-limb bending column around the bending axis thereofcSatisfies the following formula:
Ic=π[D4-(D-2t″)4]/64
in the formula, D is the outer diameter of the section of the welding circular tube, and t' is the wall thickness of the section of the welding circular tube;
of the above numerical values, MFBAHas the unit of N.mm, MFBCHas a unit of N.mm, and the section inertia moment I of the single-limb bending column around the bending axis thereofcIn mm unit4
Step three: requires the flexural integral stability of the connecting rod to calculate the stress sigmacr2Not exceeding the design value f of the strength of the connecting rod steel2Calculating the stress sigma from the flexural global stability of the connecting rodcr2Calculating to obtain the section modulus W of the connecting rod around the bending axis2A lower limit value of (d); tangential supporting rigidity gamma provided by flexible supporting system to single-limb upright postTIs more than or equal to the lower limit value gamma of the supporting rigidity requirement of the flexible supporting system on the single-limb upright postcrTangential support stiffness γ to the single-limb column provided by the flexible support systemTCalculating to obtain the inertia moment I of the section of the connecting rod around the bending axis of the connecting rod2A lower limit value of (d); according to the section modulus W of the connecting rod about its bending axis2And the section moment of inertia I2Lower limit of (2)Preliminarily determining the section specification of the connecting rod by inquiring a profile steel meter;
section modulus W of connecting rod around bending axis thereof2Satisfies the following formula:
Figure BDA0002327732250000072
in the formula I2As the length of the connecting rod,
Figure BDA0002327732250000073
the above formula is taken in the preliminary calculation for the overall stability factor when the connecting rod is used as a flexural member
Figure BDA0002327732250000074
f2Determining according to the steel product trade mark of the steel product used by the connecting rod and the design standard of the steel structure;
tangential support stiffness gamma provided by flexible support system to single-limb upright columnTSatisfies the following formula:
Figure BDA0002327732250000075
wherein η is the ratio of the bending flexibility of the connecting rod to the axial compression flexibility of the middle stay bar, FEIs the euler critical force of the middle stay bar;
euler critical force F of middle stayESatisfies the following formula:
FE=π2EA11 2
moment of inertia I of the cross-section of the connecting rod about its bending axis2And a ratio η of link bending compliance to intermediate strut axial compliance satisfies the following equation:
Figure BDA0002327732250000081
of the above values, the link length l2In mm, the second moment of inertia of the section of the connecting rod about its axis of bending I2In mm unit4Connecting rodSection modulus W around its bending axis2In mm unit3Tangential support stiffness gamma provided by the flexible support system to the single-limb uprightTHas the unit of N/mm, and the lower limit value gamma of the supporting rigidity requirement of the flexible supporting system on the single-limb upright postcrHas a unit of N/mm, a unit of N is the maximum supporting force F, and the Euler critical force F of the middle supporting rodEThe unit of (a) is N;
step four: obtaining the section modulus W of the connecting rod around the bending axis according to the section specification of the connecting rod preliminarily determined in the step three2And the section moment of inertia I2The actual value of (c); according to the third step, the section inertia moment I of the connecting rod around the bending axis is preliminarily determined2The actual values are calculated to obtain the ratio η of the bending flexibility of the connecting rod to the axial flexibility of the middle support rod and the actual support rigidity gamma provided by the flexible support system to the single-limb upright post, the actual support rigidity gamma provided by the flexible support system to the single-limb upright post is substituted into the step two to recalculate to obtain the maximum support force F, the recalculated maximum support force F is substituted into the step three to recalculate the bending integral stability calculation stress sigma of the connecting rod by checkingcr2And the tangential supporting rigidity gamma provided by the flexible supporting system to the single-limb upright postTWhether the requirement is met or not, and checking the axial pressure integral stable bearing capacity F of the middle supporting rod according to the maximum supporting force F obtained by recalculationcrWhether the requirement is met, wherein the stress sigma is calculated by calculating the flexural integral stability of the connecting rodcr2Overall stability factor when the connecting rod is used as a flexural member
Figure BDA0002327732250000085
The integral stability coefficient of the bent member in the steel structure design standard is determined according to the section specification of the connecting rod; calculating stress sigma if the whole of the connecting rod is bent stablycr2If the requirement is not met, the connecting rod with a larger section needs to be replaced, and the section modulus W of the connecting rod with the larger section around the bending axis of the connecting rod with the larger section is used2' Replacing original design connecting rod section modulus W2If the flexible support system provides tangential support stiffness gamma to the single-limb upright columnTAnd the bearing capacity F of the middle support rod for stabilizing the whole axle pressurecrIf one of them does not meet the requirements, the section needs to be replacedThe middle stay bar with larger surface is used for increasing the sectional area determination value A of the middle stay bar in the rear flexible supporting system1' Preset value of cross-sectional area of middle stay bar in alternative flexible supporting system A1To increase the minimum turning radius i of the section of the rear middle strut1' Preset value of radius of gyration of section in place of middle stay i1And repeating the first step to the fourth step until the stress sigma of the whole bending stability of the connecting rod is calculatedcr2The tangential supporting rigidity gamma provided by the flexible supporting system to the single-limb upright columnTAnd the bearing capacity F of the middle support rod for stabilizing the whole axle pressurecrAll meet the requirements;
the actual support stiffness gamma provided by the flexible support system to the single-limb upright column satisfies the following formula:
Figure BDA0002327732250000082
stress sigma is calculated by integral stability of bending of connecting rodcr2The requirements to be met are as follows:
Figure BDA0002327732250000083
the ratio η of the link bending compliance to the axial compliance of the center strut satisfies the following equation:
Figure BDA0002327732250000084
tangential support stiffness gamma provided by flexible support system to single-limb upright columnTThe requirements to be met are as follows:
Figure BDA0002327732250000091
bearing capacity F of middle stay bar for integrally stabilizing axial compressioncrThe requirements to be met are as follows:
2F≤Fcr;=
bearing capacity F of middle stay bar for integrally stabilizing axial compressioncrSatisfies the following formula:
Figure BDA0002327732250000092
in the formula (I), the compound is shown in the specification,
Figure BDA0002327732250000093
the axial compression integral stability coefficient of the middle stay bar is determined according to the slenderness ratio lambda of the middle stay bar1And the section classification of the axial compression steel member is determined according to the Steel Structure design Standard f1Determining the design value of the strength of the steel of the middle stay bar according to the steel grade of the steel used for the middle stay bar and the design standard of a steel structure;
among the above values, the design value f of the strength of the steel material of the middle stay bar1Has a unit of N/mm2And the bearing capacity F of the middle support rod is integrally stabilized by axial compressioncrThe unit of (d) is N.
In one embodiment of the invention, the double-limb combined-section bending column comprises two single-limb bending columns, a connecting wallboard welded between the two single-limb bending columns, and a stiffening rib welded on the connecting wallboard and vertical to the two single-limb bending columns; the flexible supporting system of the double-limb combined cross-section bending column comprises a connecting rod and a middle supporting rod; the connecting rod is welded between the two single-limb bending columns and is positioned on the connecting line of the centroids of the sections of the two single-limb bending columns; the middle stay bar is perpendicular to the connecting wall plate and welded at one half of the connecting rod in the length direction.
In one embodiment of the invention, the single-limb bending column is a biaxial symmetric steel member, and H-shaped cross-section and rectangular pipe cross-section steel members are more adopted in the engineering.
In one embodiment of the present invention, when the single-limb bending column is an H-shaped section steel member, the connecting wall plate is welded between the webs of the two single-limb bending columns, and the connecting rod is welded between the webs of the two single-limb bending columns.
In one embodiment of the invention, the connecting rod is a symmetrical section steel member.
In one embodiment of the present invention, the link is a channel steel, a rectangular tube-section steel member, or an H-section steel member.
In an embodiment of the present invention, when the connecting rod is a channel, the connecting rod includes a channel flange and a channel web, the opening of the connecting rod faces downward (toward the column bottom), the channel flange is parallel to the connecting wall plate, the channel web is perpendicular to the connecting wall plate, and the middle brace is welded to the channel flange.
In one embodiment of the invention, the middle stay is a steel member having a biaxial symmetric section.
In one embodiment of the present invention, the middle stay is a circular-tube-section steel member, a rectangular-tube-section steel member, or an H-section steel member.
In one embodiment of the present invention, the cross section of the middle stay is a cross section of the middle stay perpendicular to the Y axis.
In one embodiment of the invention, the total height of the upright column is the total height of the single-limb bending column.
In one embodiment of the invention, the inter-strut height refers to the spacing between the middle struts, i.e. the lateral strut spacing of the single-limb bending strut.
In one embodiment of the invention, a single limb with one end hinged and one end fixed bends the fixed end bending moment of the column section to make the clockwise rotation of the column section positive and the counterclockwise rotation of the column section negative.
In one embodiment of the invention, the span is the distance between adjacent support points of the members.
In one embodiment of the invention, when n ≧ 1, the middle supports are equally spaced.
The invention also provides application of the design method in designing the flexible support system of the double-limb combined section bending column.
In one embodiment of the invention, the flexible supporting system of the double-limb combined-section bending column bears the combined action of transversely uniform load and axial pressure of the column top.
In one embodiment of the invention, the flexible supporting system of the double-limb combined cross-section bending column is a flexible supporting system of a double-limb combined cross-section bending column of a dust remover box body.
[ advantageous effects ]
The invention provides a design method of a flexible support system of a bending column with a double-limb combined section of a box body of a dust remover, which can be used for designing the flexible support system consisting of a support rod and a connecting rod, is reliable and reasonable in design and has extremely high application prospect in the aspect of designing the flexible support system of the bending column with the double-limb combined section of the box body of the dust remover.
Drawings
FIG. 1 is a schematic view of a three-dimensional model of a stiffened wall panel-column structure system of a dust collector box body envelope.
Fig. 2 is a schematic front view of a flexible supporting system of a double-limb combined cross-section bending column of a dust remover box body.
FIG. 3 is a schematic top view of a flexible support system of a double-limb combined cross-section press bending column of a dust remover box body.
In fig. 1-3, 1 is a single-limb bending column, 2 is a box body wallboard, 3 is a box body wallboard stiffening rib, 4 is a flexible supporting system, 5 is a connecting rod, 6 is a middle supporting rod, 7 is a front flange of a single-limb upright column with an H-shaped cross section, 8 is a rear flange of the single-limb upright column with the H-shaped cross section, 9 is a web of the single-limb upright column with the H-shaped cross section, 10 is a connecting wallboard between two limbs, 11 is an angle steel stiffening rib on the connecting wallboard, 12 is a flange of a channel steel connecting rod, and 13 is a web of the channel steel connecting rod.
FIG. 4 is a schematic view of a press bending column with a center support.
Figure 5 is a schematic diagram of a press bending column calculation with four mid-supports.
FIG. 6 is a graph showing the relationship between the supporting force and the supporting rigidity (with four middle supports) under different parameters.
Fig. 7 shows the deformation of a central strut with an initial defect under axial force.
Fig. 8 is a schematic of the deformation at the support point.
FIG. 9 is a graph of the value of 2/(2+ ζ) versus the value of ψ.
FIG. 10 is a plot of maximum deflection Δ at the support point versus η values.
Fig. 11 is a plot of maximum support force F at the support point versus η values.
Detailed Description
The invention will be further elucidated with reference to the embodiments and the drawings.
The calculations for studying the two-limb combination cross-section buckling columns in the following examples are assumed to be: the two ends of the bending column are restrained by the simple supports, the top of the column is stressed by axial pressure N, and the midspan is stressed by transversely and uniformly distributed loads q. In the following examples, it is considered that the central struts are equally spaced, assuming equal column lengths l and equal linear stiffnesses between the support points, K-EIcL is calculated as follows. Because current engineering designs do not take plastic development into account, elasticity calculations are used in the examples below. Since the response of the press bending member is non-linear, influenced by the load path, the following example assumes in the calculation that the laterally uniform load on the press bending column increases in proportion to the concentrated pressure at the top of the column in synchronism with the increase in the load.
The first step is calculation of the supporting force borne by the double-limb combined section bending column:
a simplified calculation diagram of the buckling column with a middle brace is shown in figure 4, considering the symmetry of the structure and the load, and the turning angle theta of the point BB=0,θA=-θC
MAB=K[CθA+SθB-(C+S)ΔAB/l]=0;
Figure BDA0002327732250000111
MBA=K[CθB+SθA-(C+S)ΔAB/l]+MFBA=K(S-C)θA+MFBA
Wherein C and S are bending rigidity coefficients of the single-limb bending column,
Figure BDA0002327732250000112
Figure BDA0002327732250000113
MFBAthe fixed end bending moment of the single-limb bending column segment with one end hinged (point A in the figure) and one end fixedly connected (point B in the figure) is calculated:
Figure BDA0002327732250000114
(the bending moment is positive to rotate the column section clockwise and negative to rotate the column section counter-clockwise).
The bending moment balance condition of the AB section is as follows:
MBA+NΔAB+FAl-ql2/2=0;
from the horizontal force balance conditions:
FA=ql-FB/2;
the conditions of coordination of the deformation at the support can be derived:
FB=γΔAB
wherein gamma is the axial deformation rigidity of the middle support rod;
the calculation formula is arranged to obtain:
Figure BDA0002327732250000121
a simplified calculation diagram of the buckling column with four middle support rods is shown in FIG. 5, considering the symmetry of the structure and the load, thetaD=-θC
For point A, there are:
MAB=K[CθA+SθB-(C+S)ΔAB/l]=0;
∴CθA+SθB=(C+S)ΔAB/l;
for point B:
MBA=K[CθB+SθA-(C+S)ΔAB/l]+MFBA
MBC=K[CθB+SθC-(C+S)ΔBC/l]+MFBC
MBA+MBC=0;
in the formula, MFBC is fixed end bending moment with two ends fixedly connected with a single limb bending column segment,
Figure BDA0002327732250000122
for point C:
MCB=K[CθC+SθB-(C+S)ΔBC/l]+MFCB
MCD=K(CθC-SθC)+MFCD
∵MCB+M CD0, and MFCB=-MFCD
∴(2C-S)θC+SθB=(C+S)ΔBC/l;
The bending moment balance condition of the AB section is as follows:
MBA+NΔAB+FAl-ql2/2=0;
in the formula, FA=5ql/2-FB-FC,FB=γΔAB,FC=γ(ΔABBC);
The bending moment balance condition of the BC section is obtained as follows:
MCB+MBC+NΔBC+(3ql/2-FC)l-ql2/2=0;
after the above calculation formulas are arranged, the value of theta can be obtainedA、θBAnd thetaCExpressed in the form:
Figure BDA0002327732250000123
in the formula, a11=K(S-C),a12=2K(C-S),a13=2K(S-C),a21=K(S2-C2)+(Nl-2γl2)C,a22=K(C2-S2)+(Nl-3γl2)S,a23=γl2(S-2C),a31=-Cγl2,a32=K(C2-S2)+(Nl-2γl2)S,a33=3K(S2-C2)+(Nl-γl2)(2C-S),b1=-MFBA-MFBC,b2=-(C+S)(MFBA+2ql2),b3=-(C+S)ql2
Solved to thetaA、θBAnd thetaCThen, the delta can be obtainedABAnd ΔBCAnd then obtaining the supporting force at each supporting point:
FB=γΔAB,FC=γ(ΔABBC);
the deflection of the bending column at the supporting point when two middle supporting rods are arranged can be solved by the same method, and the supporting force is FB=γΔAB
Figure BDA0002327732250000131
The deflection value of the bending column at the supporting point when three equidistant middle supporting rods exist can be obtained by solving the following linear equation set:
Figure BDA0002327732250000132
in the formula, c11=K(C+S),c12=-γl/2,c13=N-γl/2-2K(C+S)/l,c21=KC,c22=3γl/2-N,c23=γl/2-K(C+S)/l,c31=K(2C2-S2)/C,c32=K(S2-C2)/(Cl),c33=-K(C+S)/l,d1=-ql2/2,d2=3ql2/2-MFBC,d3=-MFBC-MFBA
In the formula, thetaBIs the column angle at L/4 column height, DeltaABAnd ΔAC=(ΔABBC) The bending column deflection at L/4 and L/2 respectively.
In order to verify the correctness of the analytical solution, the analytical method and the finite element method proposed herein are respectively adopted for several embodiments to solve the bending column bending value at the supporting point. The finite element solution is carried out by adopting an ANSYS program, and the single-limb bending column is simulated and supported by adopting a BEAM188 BEAM unitThe rod is simulated by a COMBIN14 spring unit, the geometric nonlinear effect is considered, the structural steel material adopts an elastomer, and the elastic modulus E is 2.06 multiplied by 105MPa。
Example 1:
the height L of the upright post of the dust remover box body is 16460 mm; the number n of the supports in the middle of the upright is 1; the height l of the support column is 8230mm, and the section inertia moment I of the single-limb bending columncIs 1.14X 108mm4The supporting rigidity gamma is 91391N/mm; the axial pressure N was 314000N, the lateral load q was 37.31N/mm, and the buckling column deflection values at the support points calculated using the first step analytical solution and the nonlinear finite element solution are shown in table 1.
Example 2 to example 4:
examples 2 to 4 with respect to example 1, only the number n of supports in the middle of the column was changed, and the specific structural parameters and the bending column deflection values at the support points calculated by the analytic solution of the first step and the nonlinear finite element solution are shown in table 1.
Example 5:
the height L of the upright post of the dust remover box body is 18000 mm; the number n of the supports in the middle of the upright is 1; the height l of the support column is 9000mm, and the section inertia moment I of the single-limb bending columncIs 1.31X 108mm4The supporting rigidity gamma is 120709N/mm; the axial pressure N was 462300N, the lateral load q was 42.64N/mm, and the buckling column deflection values at the support points calculated using the first step analytical solution and the nonlinear finite element solution are shown in table 1.
Example 6 to example 7:
examples 6 to 7 with respect to example 5, only the number n of supports in the middle of the column was changed, and the specific construction parameters and the bending column deflection values at the support points calculated by the analytic solution of the first step and the nonlinear finite element solution are shown in table 1.
Example 8:
example 8 only the bending column section moment of inertia I was changed from example 4cIs 9.74 multiplied by 107mm4. The specific construction parameters and the bending values of the buckling column at the supporting points calculated by the analytic solution of the first step and the nonlinear finite element solution are shown in table 1.
Example 9:
example 9 only the strut stiffness γ was changed to 73113N/mm relative to example 4. The specific construction parameters and the bending values of the buckling column at the supporting points calculated by the analytic solution of the first step and the nonlinear finite element solution are shown in table 1.
Example 10:
example 10 only the loading was changed relative to example 4: n was 471000N and the transverse load q was 55.97N/mm. The specific construction parameters and the bending values of the buckling column at the supporting points calculated by the analytic solution of the first step and the nonlinear finite element solution are shown in table 1.
TABLE 1 comparison of bending values of a bending column at a support point calculated by the method of the present invention and a finite element method
Figure BDA0002327732250000141
Note: deltaAC=ΔABBC
The comparison of the calculation results shows that the maximum deviation of the analytic solution and the nonlinear finite element solution is 1.6%, and the analytic solution is accurate and reliable. When the single-limb buckling column height, the single-limb buckling column section moment of inertia, the middle support rod rigidity and the load are unchanged through examining comparative examples 1 to 4 and examples 5 to 7, the calculation result shows that the larger the number of middle supports, the smaller the deflection at the support point and the smaller the required support force. The more the number of supports is, the more the calculation result tends to be equal, therefore, when the number of middle support rods exceeds 4, the supporting force can be calculated by 4 middle support rods in a biased manner. Considering comparative example 4 and example 8, when the total height of the upright post, the rigidity of the middle support rod, the support number and the load are not changed, the linear rigidity of the single-limb bending column is reduced (actually, the bending rigidity of the upright post is weakened), the maximum bending value at each support point is increased, and the maximum support force is increased. The relationship curve of the maximum supporting force and the supporting rigidity when the K, l, N and q values are different is shown in figure 6. Examining the curves of comparative example 4, example 9 and fig. 6, the support stiffness was increased, the deflection value at the support point was significantly decreased, and the support force was increased to a small extent. This shows that the influence of the stiffness of the middle stay bar on the supporting force is small when the linear stiffness of the single-limb bending column, the height of the single-limb bending column and the supporting number and load are unchanged.
The second step is that the support rigidity of the flexible support system formed by the middle support rod and the connecting rod of the double-limb combined section bending column is calculated:
considering the initial deflection and the manufacturing and installation deviation of the middle stay bar under the action of the dead weight, the initial deformation of the middle stay bar is as follows:
Figure BDA0002327732250000151
in the formula, w0ξ is the axial distance from any point on the strut to the distal end of the strut (the end away from the connecting rod);
after receiving the strut force of 2F, the deformation is shown in fig. 7 as follows:
Figure BDA0002327732250000152
in the formula, AmTo take into account the amplification factor of the second order effect,
Figure BDA0002327732250000153
FEis the euler critical force of the middle stay bar;
the axial deformation of the strut caused by bending is:
Figure BDA0002327732250000154
considering the bending deformation of the intermediate connecting rod, for the single-limb upright post, the deformation at the supporting action point is as shown in the attached figure 8, the two limbs are connected by the steel plate, because the steel plate is thin, the bending rigidity of the plate is safe, and the deformation at the supporting point is as follows:
Figure BDA0002327732250000155
for the middle stay bar, the dead weight is consideredInitial deflection under influence and manufacturing and mounting variations, taking w0=l1/500:
Figure BDA0002327732250000156
Figure BDA0002327732250000161
The secant stiffness γ of the support system is:
Figure BDA0002327732250000162
the rigidity of the support system decreases with increasing support force due to the consideration of the initial geometrical defects of the struts, and is non-linear, such that psi is F/FE
Figure BDA0002327732250000163
η is the ratio of the bending flexibility of the connecting rod to the axial flexibility of the middle stay rod
Figure BDA0002327732250000164
Then there are:
Figure BDA0002327732250000165
when the supporting force is calculated in the first step, the calculation derivation of the bending column bending value and the supporting force at the middle supporting point is based on the constant stiffness, the stiffness of the actual supporting system changes along with the increase of the load, so that an accurate solution can be obtained only by setting an initial stiffness value and then carrying out iterative calculation, the process is complex, and the method is not easy to apply in engineering, so that a simple and convenient method for determining the initial supporting stiffness which is deviated from safety is derived in the following.
Middle stay bar slenderness ratio lambda of bending column in dust remover1Generally controlled between 90 and 150, and the supporting force born by the middle supporting rod is 2F or less and F or lesscr(FcrTo stabilize the bearing capacity for the axial compression of the strut), thus:
Figure BDA0002327732250000166
the middle support rod of the dust remover is generally made of Q235 or Q345 steel and corresponds to a type a or type b section of a shaft center compression component in Steel Structure design Standard; for the stay rod with selected steel type and section type, the upper limit psi of psi valuemaxOnly with λ1Is related to
Figure BDA0002327732250000167
Can be used for characterizing the stiffness reduction of the support system caused by the action of the axial force of the stay rods, when η is equal to 0, namely the influence of the connecting rods on the stiffness is not considered, the relation curve of the value 2/(2+ zeta) and the value psi is shown in the attached figure 9, and the stiffness reduction amplitude is increased along with the increase of the stress of the middle stay rods, and the lambda is increased1The larger the rigidity reduction amplitude caused by the stress of the middle support rod is, the larger the rigidity reduction amplitude is; when in engineering design, the stress 2F of the stay bar is generally controlled to be 0.5Fcr~FcrSo that the psi value is 0.5 psimax~ψmax(ii) a Considering that the supporting force F is slightly increased as the initially set F value is decreased and γ is increased, the supporting system design conservatively takes 2F to 0.5FcrI.e. psi 0.5 psimaxThe gamma value of the time is used as the rigidity of the supporting system, and the deformation of the supporting point and the calculation of the supporting force are carried out; when psi is 0.5 psi for different steel type and section type stay barmax,λ1The numerical fitting of the least square method is carried out on the zeta value when the support force is 90-150, so that the zeta value used in the calculation of the initial support force can be calculated according to a fixed formula, the initial support rigidity can be obtained simply and conveniently according to the construction of a support system, and the specific process is as follows:
q235 steel is selected for manufacturing, a middle support rod (such as a hot-rolled seamless steel pipe) of a type a section of the axial compression member in the steel structure design standard can be calculated according to the following formula:
Figure BDA0002327732250000171
q235 steel is selected for manufacturing, a middle stay bar (such as a welded straight seam circular tube, a hot rolled H-shaped steel, a welded or rolled rectangular tube) of a b-type section of an axial compression member in the steel structure design standard can be calculated according to the following formula:
Figure BDA0002327732250000172
q345 steel is selected for manufacturing, the middle support rod of the a-type section of the axial compression member in the steel structure design standard is classified as the center, and zeta can be calculated according to the following formula:
Figure BDA0002327732250000173
q345 steel is selected for manufacturing, the middle support rod of the b-type section of the axial compression member in the steel structure design standard is classified as the center, and zeta can be calculated according to the following formula:
Figure BDA0002327732250000174
when the number n of the equal-spacing middle supporting rods is more than or equal to 3, the column deflection value and the supporting force of each supporting point are unequal, so that the rigidity of each supporting system is different; for the bending column with four unequal-rigidity supports, the displacement at the supporting point can be calculated according to the method of the first step, and only 6 coefficients in the calculation method of the bending column with four middle supporting rods need to be modified:
a21=K(S2-C2)+(Nl-γBl2-γCl2)C,a22=K(C2-S2)+(Nl-γBl2-2γCl2)S,a23=γCl2(S-2C),a31=-CγCl2,a32=K(C2-S2)+(Nl-2γCl2)S,a33=3K(S2-C2)+(Nl-γl2)(2C-S);
in the formula, gammaBSupport stiffness at column heights of L/5 and 4L/5, gammaCAt 2L/5 and 3L/5 column heightSupporting the stiffness.
For the stand column, the support structure and the load condition commonly used in the dust collector, the following examples were calculated by the above analytical method according to the equal support stiffness and the unequal stiffness, respectively.
Example 11:
the height L of the upright post of the dust remover box body is 16460 mm; the height l of the support column is 3292mm, and the section inertia moment I of the single-limb bending columncIs 1.14X 108mm4(ii) a Support stiffness gamma at L/5 and 4L/5 column heightsBIs 91391N/mm, gammaCTake 0.5 gammaB(ii) a The axial pressure N was 1226000N, the lateral load q was 20.36N/mm, and the equivalent and unequal support force ratios were obtained by the second analytical solution shown in Table 2.
Example 12:
example 12 only gamma is compared to example 11CIs changed into 2 gammaBTable 2 shows the specific structural parameters and the equivalent and non-equivalent support force ratio of the analytic solution support stiffness of the second step.
Example 13:
the height L of the upright post of the dust remover box body is 15000 mm; the height l of the support column is 3000mm, and the section inertia moment I of the single-limb bending columncIs 0.98X 108mm4(ii) a Support stiffness gamma at L/5 and 4L/5 column heightsB67911N/mm, gammaCTake 0.5 gammaB(ii) a The axial pressure N was 981000N, the lateral load q was 18.66N/mm, and the equivalent and unequal support force ratios were supported using the analytical solution of the second step, as shown in Table 2.
Example 14:
example 14 comparing example 13 with only γCIs changed into 2 gammaBTable 2 shows the specific structural parameters and the equivalent and non-equivalent support force ratio of the analytic solution support stiffness of the second step.
Example 15:
the height L of the upright post of the dust remover box body is 18000 mm; the height l of the support column is 3600mm, and the section inertia moment I of the single-limb bending columncIs 1.31X 108mm4(ii) a Support stiffness gamma at L/5 and 4L/5 column heightsBIs 120709N/mm, gammaCTake 0.5 gammaB(ii) a Axial pressureThe force N was 1471000N, the lateral load q was 25.73N/mm, and the equivalent and unequal support force ratios were determined by the second analytical solution as shown in Table 2.
Example 16:
example 16 only gamma is compared to example 15CIs changed into 2 gammaBTable 2 shows the specific structural parameters and the equivalent and non-equivalent support force ratio of the analytic solution support stiffness of the second step.
TABLE 2 comparison of equal and unequal support forces for equal support stiffness (four supports arranged at equal intervals)
Figure BDA0002327732250000181
Comparison of the results shows that the gamma values for the examples 11 to 16 in the table are calculated as unequal support stiffnessCRespectively taking 0.5 gammaBAnd 2 gammaBThe relative deviation is 4.0% at the maximum, as compared with the support force calculated as the support rigidity is equal, and the deviation decreases as the average value of the support rigidity increases. The middle support rods in the dust remover are identical in structure, and only the support rods are unequal in stress, which causes the difference of support rigidity. When lambda is1150F (the most flexible case of the strut), the strut is stressed by 2F from 0.5FcrIncrease to FcrDuring the process, the reduction amplitude of the rigidity of the supporting system is not more than 22 percent, namely the maximum variation range of the supporting rigidity ratio in the dust remover is as follows: gamma is not less than 0.78CBLess than or equal to 1.28 and less than or equal to 0.5 and less than or equal to gamma in the embodimentCBThe variation range is less than or equal to 2; and the initial rigidity (rigidity when the stay bar is not stressed) of the support system in the actual structure is larger, so that the deviation of a calculation result caused by unequal rigidity due to unequal stress of each support point is less than 4.0 percent, the deviation can be ignored, and the column deflection and the support force of each support point can be calculated according to the condition that the support rigidity is equal.
When the support is supported at the middle point of the connecting rod between the two single-limb bending columns, the bending deformation of the connecting rod can increase the flexibility of the support system,
Figure BDA0002327732250000191
additional compliance caused by the linkage can be characterized.When four supports are provided, the relation curve of the deflection at the maximum stress supporting point and the η value is shown in figure 10, the deflection is basically linearly increased along with the η value, the relation curve of the supporting force at the maximum supporting point and the η value is shown in figure 11, η is increased, the rigidity gamma of the supporting system is reduced, and the reduction amplitude of the supporting force is very small.
Example 17: design method of flexible support system of double-limb combined cross-section bending column of dust remover box body
The method comprises the following steps:
the method comprises the following steps: designing a double-limb combined section bending column of a flexible supporting system according to requirements, and preliminarily trying to set the preset sectional area value of a middle support rod in the flexible supporting system to be A1The preset value of the minimum turning radius of the cross section is i1(ii) a Determining the total height L of the upright column, the height L of the support column and the length L of the middle support rod of the double-limb combined section bending column of the flexible support system1The value of (d); calculating the initial supporting rigidity gamma of the flexible supporting system according to the preset value and the numerical value0
Initial support stiffness γ0Calculated according to the following formula:
Figure BDA0002327732250000192
where ζ is a coefficient in which the nonlinear influence of the decrease in the rigidity of the flexible support system with the increase in the supporting force is taken into consideration, and E is the structural steel elastic modulus, and the above formula is calculated such that E is 2.06 × 105N/mm2
The flexible supporting system is made of Q235 steel or Q345 steel, and the middle supporting rod is a type a section or a type b section of the axial compression member;
when the material of the flexible supporting system is Q235 steel and the middle support rod is a class a section of the axial center compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000193
when the material of the flexible supporting system is Q235 steel and the middle support rod is a b-type section of the axial center compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000194
when the material of the flexible supporting system is Q345 steel and the middle support rod is a class a section of the axial center compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000201
when the material of the flexible supporting system is Q345 steel and the middle support rod is a b-type section of the axial compression member, a coefficient zeta considering the nonlinear influence that the rigidity of the flexible supporting system is reduced along with the increase of the supporting force satisfies the following formula:
Figure BDA0002327732250000202
in the formula, λ1The length-to-thickness ratio of the middle support rod is obtained;
length-thin ratio lambda of middle stay bar1Satisfies the following formula:
λ1=l1/i1
among the above values, the sectional area of the middle stay bar is preset value A1In mm unit2Length of middle stay bar l1The unit of (1) is mm, the unit of the preset value i of the minimum turning radius of the cross section of the strut is mm, and the unit of the elastic modulus E of the material is N/mm2Initial support stiffness γ0The unit of (A) is N/mm;
step two: determining an axial pressure design value N borne by the top of a double-limb combined cross-section bending column of a flexible supporting system to be designed, transversely and uniformly distributing load design values q borne by a span, and calculating to obtain the maximum supporting force F of the single-limb bending column according to the axial pressure N, the transversely and uniformly distributed load q, the linear rigidity K of the single-limb bending column, the height l of a supporting column, the supporting rigidity gamma of the flexible supporting system and the number N of middle supports;
when n is 1, the maximum supporting force F satisfies the following formula:
F=γΔAB
in the formula,. DELTA.ABThe deflection of the single-limb bending column at the middle supporting position is obtained by taking gamma as gamma in the formula during initial calculation0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000203
Deflection delta of single-limb bending column at middle supportABSatisfies the following formula:
Figure BDA0002327732250000204
wherein C and S are flexural rigidity coefficient of single-limb bending column, MFBAThe bending moment at the fixed end of the single-limb bending column segment is hinged at one end and fixedly connected at one end, K is the linear rigidity of the single-limb bending column, and L is L/2;
in the above numerical values, the unit of the height l of the support column is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection delta of the single-limb bending column at the middle support partABThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is 2, the maximum supporting force F satisfies the following formula:
F=γΔAB
in the formula,. DELTA.ABThe deflection of the single-limb bending column at the middle L/3 and 2L/3 column heights is obtained by taking gamma as gamma in the formula during initial calculation0Determining the section specification of the middle stay and the section specification of the connecting rodAfter taking
Figure BDA0002327732250000211
Middle L/3 and 2L/3 column height displacement deltaABSatisfies the following formula:
Figure BDA0002327732250000212
wherein C and S are flexural rigidity coefficient of single-limb bending column, MFBAFor bending the fixed end bending moment of a column segment for a single limb with one hinged end and one fixed end, MFBCThe fixed end bending moment of the bending component is fixedly connected with the two ends, K is the linear rigidity of the single-limb bending column, and L is equal to L/3;
in the numerical values, the unit of the height L of the support columns is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection delta of the single-limb bending column at the middle L/3 and 2L/3 column heightsABThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is 3, the maximum supporting force F satisfies the following formula:
F=γΔAC
in the formula,. DELTA.ACFor the mid-span deflection of the single-limb bending column, the formula is that gamma is taken as gamma in the initial calculation0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000213
Mid-span deflection delta of single-limb bending columnACSatisfies the following formula:
ΔAC=ΔABBC
Figure BDA0002327732250000214
in the formula, c11=K(C+S),c12=-γl/2,c13=N-γl/2-2K(C+S)/l,c21=KC,c22=3γl/2-N,c23=γl/2-K(C+S)/l,c31=K(2C2-S2)/C,c32=K(S2-C2)/(Cl),c33=-K(C+S)/l,d1=-ql2/2,d2=3ql2/2-MFBC,d3=-MFBC-MFBA;θAFor bending the column corner, theta, at the column top for a single limbBFor single limb bending column corner, delta, at quarter column heightABAnd ΔACRespectively the deflection of one fourth of the single-limb bending column and the deflection of one half of the column height (because of symmetry, the column corner at the column top of the single-limb bending column is equal to the column corner at the column bottom of the single-limb bending column, the column corner at the column height of one fourth of the single-limb bending column is equal to the column corner at the column height of three fourth of the single-limb bending column, the deflection of the bending column at the column height of one fourth of the single-limb bending column is equal to the deflection of the bending column at the column height of three fourth of the single-limb bending column), deltaBCThe deflection of the high part of the column is increased relative to the deflection of the high part of the column, C and S are the bending rigidity coefficient of the single-limb bending column, MFBAFor bending the fixed end bending moment of a column segment for a single limb with one hinged end and one fixed end, MFBCThe fixed end bending moment of the bending component is fixedly connected with the two ends, K is the linear rigidity of the single-limb bending column, and L is equal to L/4;
in the above numerical values, the unit of the height l of the column between the supports is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection value delta of each item of the column isAC、ΔABAnd ΔBCThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is 4, the maximum supporting force F satisfies the following formula:
F=γΔAC
in the formula,. DELTA.ACThe deflection of the single-limb bending column at the 2L/5 and 3L/5 column heights is obtained by taking gamma as gamma in the formula during initial calculation0Taking the section specification of the middle supporting rod and the section specification of the connecting rod after determining
Figure BDA0002327732250000221
Deflection delta of 2L/5 and 3L/5 column height of single-limb bending columnACSatisfies the following formula:
ΔAC=ΔABBC
Figure BDA0002327732250000222
ΔAB=(CθA+SθB)l/(C+S);
ΔBC=l[(2C-S)θC+SθB]/(C+S);
in the formula, a11=K(S-C),a12=2K(C-S),a13=2K(S-C),a21=K(S2-C2)+(Nl-2γl2)C,a22=K(C2-S2)+(Nl-3γl2)S,a23=γl2(S-2C),a31=-Cγl2,a32=K(C2-S2)+(Nl-2γl2)S,a33=3K(S2-C2)+(Nl-γl2)(2C-S),b1=-MFBA-MFBC,b2=-(C+S)(MFBA+2ql2),b3=-(C+S)ql2;θAFor bending the column corner, theta, at the column top for a single limbBThe column corner theta at the height of one fifth of the column is formed by pressing a single limbCThe column corner, delta, at two fifths of the height of the column for single limb bendingABThe deflection of the bending column at the height of one fifth of the bending column of the single limb (because of symmetry, the column corner at the top of the bending column of the single limb is equal to the column corner at the bottom of the bending column of the single limb, the column corner at the height of one fifth of the bending column of the single limb is equal to the column corner at the height of four fifth of the bending column of the single limb, the column corner at the height of two fifth of the bending column of the single limb is equal to the column corner at the height of three fifth of the bending column of the single limb, the deflection of the bending column at the height of one fifth of the bending column of the single limb is equal to the deflection of the bending column at the height of four fifth of the bending column of the single limb), deltaBCThe deflection of the single-limb bending column at the height of two fifths of the column is increased compared with the deflection of the single-limb bending column at the height of one fifths of the column, and C and S are the deflection of the single limbBending stiffness coefficient of column, MFBAFor bending the fixed end bending moment of a column segment for a single limb with one hinged end and one fixed end, MFBCThe fixed end bending moment of the single-limb bending column segment is fixedly connected with two ends, K is the linear rigidity of the single-limb bending column, and L is L/5;
in the above numerical values, the unit of the height l of the column between the supports is mm, the unit of the axial pressure N is N, the unit of the transversely uniformly distributed load q is N/mm, and the deflection value delta of each item of the column isAC、ΔABAnd ΔBCIn units of mm, the displacement delta at the column heights of the middle L/5 and 4L/5ABThe unit of (3) is mm, the unit of the linear rigidity K of the single-limb bending column is N.mm, and the unit of the supporting rigidity gamma is N/mm;
when n is greater than 4, calculating the maximum supporting force F according to the condition that n is 4;
wherein, the bending rigidity coefficient C of the single-limb bending column meets the following formula:
Figure BDA0002327732250000231
the bending rigidity coefficient S of the single-limb bending column meets the following formula:
Figure BDA0002327732250000232
in the formula, k is a calculation coefficient;
the calculation coefficient k satisfies the following formula:
Figure BDA0002327732250000233
fixed end bending moment M of single-limb bending column segment with one hinged end and one fixed endFBAThe following formula is satisfied such that the pole segments are positive for clockwise rotation and negative for counterclockwise rotation:
Figure BDA0002327732250000234
fixed end bending moment M with two ends fixedly connected with single-limb bending column segmentFBCSatisfies the following formula so thatThe rod segment rotates positive clockwise and negative counter-clockwise:
Figure BDA0002327732250000235
the linear rigidity K of the single-limb bending column meets the following formula:
K=EIc/l;
in the formula IcThe bending moment of inertia of the section of the single-limb bending column around the bending axis of the single-limb bending column is E, and the elasticity modulus of structural steel is E;
the single-limb bending column is biaxial symmetric hot-rolled section steel or a welded combined section component;
when the single-limb bending column is hot-rolled section steel, the section inertia moment I of the single-limb bending column around the bending axis thereofcCan be obtained by directly inquiring a profile steel table;
when the single-limb bending column is a welding combined section component, if the single-limb bending column is a welding H-shaped section, the section inertia moment I of the single-limb bending column around the bending axis thereofcSatisfies the following formula:
Figure BDA0002327732250000236
wherein H is the total height of the welded H-shaped section, B is the width of the welded H-shaped section, t1For welding webs of H-section, t2The thickness of the flange of the H-shaped section;
if the single-limb bending column is the section of the welded rectangular pipe, the section inertia moment I of the single-limb bending column around the bending axis thereofcSatisfies the following formula:
Figure BDA0002327732250000241
in the formula, a1For welding the length of the cross-section of rectangular tubes parallel to the bending axis, a2The length of the side of the section of the welded rectangular tube, which is perpendicular to the bending axis side, is t ', and the thickness of the section of the welded rectangular tube is t';
if the single-limb bending column is the section of the welded round pipe, the single-limb bending column winds the welded round pipeSection moment of inertia I of bending axiscSatisfies the following formula:
Ic=π[D4-(D-2t″)4]/64
in the formula, D is the outer diameter of the section of the welding circular tube, and t' is the wall thickness of the section of the welding circular tube;
of the above numerical values, MFBAHas the unit of N.mm, MFBCHas a unit of N.mm, and the section inertia moment I of the single-limb bending column around the bending axis thereofcIn mm unit4
Step three: requires the flexural integral stability of the connecting rod to calculate the stress sigmacr2Not exceeding the design value f of the strength of the connecting rod steel2Calculating the stress sigma from the flexural global stability of the connecting rodcr2Calculating to obtain the section modulus W of the connecting rod around the bending axis2A lower limit value of (d); tangential supporting rigidity gamma provided by flexible supporting system to single-limb upright postTIs more than or equal to the lower limit value gamma of the supporting rigidity requirement of the flexible supporting system on the single-limb upright postcrTangential support stiffness γ to the single-limb column provided by the flexible support systemTCalculating to obtain the inertia moment I of the section of the connecting rod around the bending axis of the connecting rod2A lower limit value of (d); according to the section modulus W of the connecting rod about its bending axis2And the section moment of inertia I2The section specification of the connecting rod is preliminarily determined by inquiring a profile steel table;
section modulus W of connecting rod around bending axis thereof2Satisfies the following formula:
Figure BDA0002327732250000242
in the formula I2As the length of the connecting rod,
Figure BDA0002327732250000243
the above formula is taken in the preliminary calculation for the overall stability factor when the connecting rod is used as a flexural member
Figure BDA0002327732250000244
f2According to the grade of the steel used by the connecting rod, the steel structureDesign criteria are determined;
tangential support stiffness gamma provided by flexible support system to single-limb upright columnTSatisfies the following formula:
Figure BDA0002327732250000245
wherein η is the ratio of the bending flexibility of the connecting rod to the axial compression flexibility of the middle stay bar, FEIs the euler critical force of the middle stay bar;
euler critical force F of middle stayESatisfies the following formula:
FE=π2EA11 2
moment of inertia I of the cross-section of the connecting rod about its bending axis2And a ratio η of link bending compliance to intermediate strut axial compliance satisfies the following equation:
Figure BDA0002327732250000251
of the above values, the link length l2In mm, the second moment of inertia of the section of the connecting rod about its axis of bending I2In mm unit4Section modulus W of connecting rod around bending axis thereof2In mm unit3Tangential support stiffness gamma provided by the flexible support system to the single-limb uprightTHas the unit of N/mm, and the lower limit value gamma of the supporting rigidity requirement of the flexible supporting system on the single-limb upright postcrHas a unit of N/mm, a unit of N is the maximum supporting force F, and the Euler critical force F of the middle supporting rodEThe unit of (a) is N;
step four: obtaining the section modulus W of the connecting rod around the bending axis according to the section specification of the connecting rod preliminarily determined in the step three2And the section moment of inertia I2The actual value of (c); according to the third step, the section inertia moment I of the connecting rod around the bending axis is preliminarily determined2The actual value is calculated to obtain the ratio η of the bending flexibility of the connecting rod to the axial flexibility of the middle support rod and the actual supporting rigidity gamma provided by the flexible supporting system to the single-limb upright postSubstituting the actual support stiffness gamma provided by the upright column into the step two to recalculate to obtain the maximum support force F; substituting the recalculated maximum supporting force F into the step three to recalculate the flexural integral stability calculation stress sigma of the connecting rod by checkingcr2And the tangential supporting rigidity gamma provided by the flexible supporting system to the single-limb upright postTWhether the requirement is met or not, and checking the axial pressure integral stable bearing capacity F of the middle supporting rod according to the maximum supporting force F obtained by recalculationcrWhether the requirement is met, wherein the stress sigma is calculated by calculating the flexural integral stability of the connecting rodcr2Overall stability factor when the connecting rod is used as a flexural member
Figure BDA0002327732250000254
The integral stability coefficient of the bent member in the steel structure design standard is determined according to the section specification of the connecting rod; calculating stress sigma if the whole of the connecting rod is bent stablycr2If the requirement is not met, the connecting rod with a larger section needs to be replaced, and the section modulus W of the connecting rod with the larger section around the bending axis of the connecting rod with the larger section is used2' Replacing original design connecting rod section modulus W2If the flexible support system provides tangential support stiffness gamma to the single-limb upright columnTAnd the bearing capacity F of the middle support rod for stabilizing the whole axle pressurecrIf one of the two does not meet the requirement, the middle stay bar with a larger cross section needs to be replaced so as to increase the cross section determination value A of the middle stay bar in the rear flexible supporting system1' Preset value of cross-sectional area of middle stay bar in alternative flexible supporting system A1To increase the minimum turning radius i of the section of the rear middle strut1' Preset value of radius of gyration of section in place of middle stay i1And repeating the first step to the fourth step until the stress sigma of the whole bending stability of the connecting rod is calculatedcr2The tangential supporting rigidity gamma provided by the flexible supporting system to the single-limb upright columnTAnd the bearing capacity F of the middle support rod for stabilizing the whole axle pressurecrAll meet the requirements;
the actual support stiffness gamma provided by the flexible support system to the single-limb upright column satisfies the following formula:
Figure BDA0002327732250000252
stress sigma is calculated by integral stability of bending of connecting rodcr2The requirements to be met are as follows:
Figure BDA0002327732250000253
the ratio η of the link bending compliance to the axial compliance of the center strut satisfies the following equation:
Figure BDA0002327732250000261
tangential support stiffness gamma provided by flexible support system to single-limb upright columnTThe requirements to be met are as follows:
Figure BDA0002327732250000262
bearing capacity F of middle stay bar for integrally stabilizing axial compressioncrThe requirements to be met are as follows:
2F≤Fcr;=
bearing capacity F of middle stay bar for integrally stabilizing axial compressioncrSatisfies the following formula:
Figure BDA0002327732250000263
in the formula (I), the compound is shown in the specification,
Figure BDA0002327732250000264
the axial compression integral stability coefficient of the middle stay bar is determined according to the slenderness ratio lambda of the middle stay bar1And the section classification of the axial compression steel member is determined according to the Steel Structure design Standard f1Determining the design value of the strength of the steel of the middle stay bar according to the steel grade of the steel used for the middle stay bar and the design standard of a steel structure;
among the above values, the design value f of the strength of the steel material of the middle stay bar1Has a unit of N/mm2And the bearing capacity F of the middle support rod is integrally stabilized by axial compressioncrThe unit of (d) is N.
Example 18: design of flexible support system of double-limb combined cross-section bending column of dust remover box body
According to the method of the embodiment 17, a flexible supporting system which is derived from a double-limb combined section bending column in a box body structure of the dust remover, which is subjected to transversely uniformly distributed load and column top shaft pressure in actual engineering and consists of a supporting rod and a connecting rod is designed, and the structural size of the double-limb combined section bending column is as follows: the total height L of the upright column is 16460mm, the height L of the support middle column is 3292mm, the number n of the middle support rods of the bending column is 4, and the linear rigidity K of the upright column is 7.13 multiplied by 109N · mm, designed value of axial pressure at the top of the column N is 1226kN, designed value of transversely uniformly distributed load q in midspan q is 20.36N/mm, and length l of the stay bar19050mm, link length l2=1120mm。
The method comprises the following steps: preliminarily designed middle support rod made of Q235 steel
Figure BDA0002327732250000265
The straight slit steel pipe is a b-type axial compression bar section, and f is 215N/mm2λ 1120 according to formula
Figure BDA0002327732250000266
Calculating a coefficient ζ which takes into account a nonlinear influence that the rigidity of the support system decreases with an increase in the support force to be 0.108; cross-sectional area A of middle stay bar1=4015mm2Minimum radius of gyration i of cross section175.3mm, strut section moment of inertia I1=22787400mm4According to the formula
Figure BDA0002327732250000267
Calculating to obtain initial support rigidity gamma0=21677N/mm;
Step two: the L of the double-limb combined section bending column is 16460mm, L is 3292mm, K is 7.13X 109Nmm, N1226 kN, q 20.36N/mm, and let the support rigidity γ be γ0According to the formula
Figure BDA0002327732250000268
Calculated for four tracks (n-4) etcWhen the middle supporting rod is spaced, the maximum supporting force F of the single-limb upright is 69990N;
step three: designing the connecting rod according to the maximum supporting force F, wherein the length l of the connecting rod21120mm, hot rolled channel steel commonly used in engineering is selected as a connecting rod, and the connecting rod can be selected during primary design
Figure BDA0002327732250000271
Stability of connecting rod according to
Figure BDA0002327732250000272
Designing to obtain the net section modulus W of the connecting rod2≥202555mm3(ii) a According to the Euler critical force of the middle stay bar
Figure BDA0002327732250000273
And
Figure BDA0002327732250000274
the ratio η of the bending flexibility of the connecting rod to the axial flexibility of the middle stay bar is calculated to be less than or equal to 65.69, and the ratio is substituted into
Figure BDA0002327732250000275
It can be seen that the moment of inertia I of the connecting rod about its bending axis2≥395337mm4Therefore, the connecting rod is made of 22a channel steel W2=218000mm3,I2=23940000mm4
Step four: the moment of inertia I of the selected 22a channel steel2Re-substitution
Figure BDA0002327732250000276
Calculated to yield η ═ 1.085, prepared from
Figure BDA0002327732250000277
ψ=F/FECalculated zeta 0.089, and substituted
Figure BDA0002327732250000278
Obtaining the actual supporting rigidity gamma of the supporting system which is 28793N/mm; according to the parameters and formula of the designed brace rod and connecting rod
Figure BDA0002327732250000279
The maximum supporting force F of the single-limb stand column is calculated again to be 71.196kN, and the hot-rolled channel steel connecting rod is used as a flexural member
Figure BDA00023277322500002722
The values were calculated according to "steel structure design Standard":
Figure BDA00023277322500002710
wherein h, b and t are the total height of the section of the channel steel, the width of a flange and the average thickness, the unit is mm, the selected 22a channel steel is checked to obtain h which is 220mm, b which is 77mm and t which is 11.5 mm;
obtained by
Figure BDA00023277322500002711
Then, according to the design standard of steel structure, the corresponding calculation is obtained according to the following formula
Figure BDA00023277322500002712
Value substitution
Figure BDA00023277322500002713
The value:
Figure BDA00023277322500002714
is calculated to
Figure BDA00023277322500002715
And calculating corresponding according to the above formula
Figure BDA00023277322500002716
Value substitution
Figure BDA00023277322500002717
Value, the overall stability factor of the connecting rod as a flexural member can be obtained
Figure BDA00023277322500002718
According to
Figure BDA00023277322500002719
And
Figure BDA00023277322500002720
is calculated to obtain
Figure BDA00023277322500002721
The overall stability checking calculation of the connecting rod meets the requirement; according to
Figure BDA0002327732250000281
Calculating to obtain gammaT=28359N/mm≥γcr1347N/mm, the tangent rigidity of the whole supporting system meets the requirement; 2F according to
Figure BDA0002327732250000282
Calculating to obtain the stress of the middle stay bar
Figure BDA0002327732250000283
And the checking calculation of the whole stability of the stay bar is satisfied. Determining the design middle brace rod as
Figure BDA0002327732250000284
The straight slit steel pipe and the connecting rod are 22a channel steel, the bending overall stability of the connecting rod, the tangential rigidity of a supporting system and the axial compression overall stability of the stay bar can be met, and the flexible supporting system consisting of the stay bar and the connecting rod is reasonable in design.
Although the present invention has been described with reference to the preferred embodiments, it should be understood that various changes and modifications can be made therein by those skilled in the art without departing from the spirit and scope of the invention as defined in the appended claims.

Claims (10)

1.一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,所述方法包含如下步骤:1. a design method of a double-limb combined section compression-bending column flexible support system, is characterized in that, described method comprises the steps: 步骤一:根据需设计柔性支撑系统的双肢组合截面压弯柱,初步试设柔性支撑系统中中部撑杆的截面积预设值为A1,截面最小回转半径预设值为i1;确定需设计柔性支撑系统的双肢组合截面压弯柱的立柱总高L、支撑间柱高l以及中部撑杆长度l1的数值;根据上述预设值和数值计算得到柔性支撑系统的初始支撑刚度γ0Step 1: According to the need to design the double-limb composite cross-section compression-bending column of the flexible support system, the preset value of the cross-sectional area of the middle strut in the flexible support system is A 1 , and the preset value of the minimum turning radius of the section is i 1 ; The values of the total column height L, the column height l between the supports, and the length of the middle strut l 1 for the double-limb composite cross-section bending column for which the flexible support system needs to be designed; the initial support stiffness of the flexible support system is calculated according to the above preset values and numerical values γ 0 ; 初始支撑刚度γ0按照下述公式计算:The initial support stiffness γ0 is calculated according to the following formula:
Figure FDA0002327732240000011
Figure FDA0002327732240000011
式中,ζ为考虑了柔性支撑系统的刚度随着支撑力的增大而减小的非线性影响的系数,E为结构钢材弹性模量,上述公式在计算时取E=2.06×105N/mm2In the formula, ζ is a coefficient that takes into account the nonlinear effect of the stiffness of the flexible support system decreasing with the increase of the supporting force, E is the elastic modulus of the structural steel, and the above formula takes E=2.06×10 5 N in the calculation /mm 2 ; 上述数值中,中部撑杆的截面积预设值A1的单位为mm2,中部撑杆长度l1的单位为mm,撑杆截面最小回转半径预设值i1的单位为mm,材料弹性模量E的单位为N/mm2,初始支撑刚度γ0的单位为N/mm;Among the above values, the unit of the preset value A 1 of the cross-sectional area of the middle strut is mm 2 , the unit of the length l 1 of the middle strut is mm, and the unit of the preset value i 1 of the minimum radius of gyration of the strut section is mm, and the material elasticity The unit of modulus E is N/mm 2 , and the unit of initial support stiffness γ 0 is N/mm; 步骤二:确定需设计柔性支撑系统的双肢组合截面压弯柱柱顶所受轴向压力设计值N,跨中所受横向均布荷载设计值q,根据轴向压力N、横向均布荷载q、单肢压弯柱线刚度K、支撑间柱高l、柔性支撑系统的支撑刚度γ以及中部支撑的数目n计算得到单肢压弯柱的最大支撑力F;Step 2: Determine the design value N of the axial pressure on the top of the double-limb composite cross-section bending column and the design value q of the laterally uniformly distributed load on the mid-span for which the flexible support system needs to be designed. According to the axial pressure N, the laterally uniformly distributed load q, the linear stiffness K of the single-leg bending column, the column height l between the supports, the support stiffness γ of the flexible support system, and the number of middle supports n, the maximum supporting force F of the single-leg bending column is calculated; 最大支撑力F满足下述公式:The maximum supporting force F satisfies the following formula: F=γΔmaxF= γΔmax ; 式中,Δmax为最接近跨中的支撑处单肢压弯柱挠度,当支撑数目n≤2时取Δmax=ΔAB,当支撑数目n>2时取Δmax=ΔAC,上述公式在初步计算时取γ=γ0In the formula, Δmax is the deflection of the single-leg bending column at the support closest to the mid-span. When the number of supports n≤2, take Δmax = ΔAB , when the number of supports n>2, take Δmax = ΔAC , the above formula Take γ=γ 0 in the preliminary calculation; 步骤三:要求连杆的受弯整体稳定计算应力σcr2不超过连杆钢材强度设计值f2,根据连杆的受弯整体稳定计算应力σcr2计算得到连杆截面模量W2的下限值;令柔性支撑系统对单肢立柱提供的切线支撑刚度γT大于等于柔性支撑系统对单肢立柱提供的支撑刚度要求的下限值γcr,根据柔性支撑系统对单肢立柱提供的切线支撑刚度γT计算得到连杆的截面惯性矩I2的下限值;根据连杆绕其弯曲轴线的截面模量W2和连杆绕其弯曲轴线的截面惯性矩I2的下限值初步确定连杆的截面规格;Step 3: The calculated stress σ cr2 of the overall stability of the connecting rod is required not to exceed the design value f 2 of the steel strength of the connecting rod, and the lower limit of the section modulus W 2 of the connecting rod is calculated according to the calculated stress σ cr2 of the overall stability of the connecting rod under bending value; let the tangential support stiffness γ T provided by the flexible support system to the single-limb column be greater than or equal to the lower limit value γ cr of the support stiffness required by the flexible support system to the single-limb column, according to the tangential support provided by the flexible support system to the single-limb column The lower limit value of the section moment of inertia I 2 of the connecting rod is calculated by the stiffness γ T ; it is preliminarily determined according to the section modulus W 2 of the connecting rod around its bending axis and the lower limit value of the section inertia moment I 2 of the connecting rod around its bending axis Sectional specification of connecting rod; 连杆绕其弯曲轴线的截面模量W2满足下述公式:The section modulus W2 of the connecting rod about its bending axis satisfies the following formula :
Figure FDA0002327732240000012
Figure FDA0002327732240000012
式中,l2为连杆长度,
Figure FDA0002327732240000023
为连杆作为受弯构件时的整体稳定系数,上述公式在初步计算时取
Figure FDA0002327732240000024
f2根据连杆所用钢材的钢材牌号确定;
In the formula, l2 is the length of the connecting rod,
Figure FDA0002327732240000023
is the overall stability factor when the connecting rod is used as a flexural member, the above formula is taken as the initial calculation
Figure FDA0002327732240000024
f 2 is determined according to the steel grade of the steel used for the connecting rod;
柔性支撑系统对单肢立柱提供的切线支撑刚度γT满足下述公式:The tangential support stiffness γ T provided by the flexible support system to the single-limb column satisfies the following formula:
Figure FDA0002327732240000021
Figure FDA0002327732240000021
式中,η为连杆弯曲柔度与中部撑杆轴向压缩柔度的比值,FE为中部撑杆的欧拉临界力;In the formula, η is the ratio of the bending flexibility of the connecting rod to the axial compression flexibility of the middle strut, and F E is the Euler critical force of the middle strut; 中部撑杆的欧拉临界力FE满足下述公式:The Euler critical force F E of the middle strut satisfies the following formula: FE=π2EA11 2F E2 EA 11 2 ; 式中,λ1为中部撑杆的长细比;In the formula, λ 1 is the slenderness ratio of the middle strut; 中部撑杆的长细比λ1满足下述公式:The slenderness ratio λ 1 of the middle strut satisfies the following formula: λ1=l1/i1λ 1 =l 1 /i 1 ; 连杆绕其弯曲轴线的截面惯性矩I2和连杆弯曲柔度与中部撑杆轴向柔度的比值η满足下述公式:The section moment of inertia I 2 of the connecting rod about its bending axis and the ratio η of the bending flexibility of the connecting rod to the axial flexibility of the middle strut satisfy the following formula:
Figure FDA0002327732240000022
Figure FDA0002327732240000022
上述数值中,连杆长度l2的单位为mm,连杆绕其弯曲轴线的截面惯性矩I2的单位为mm4,连杆绕其弯曲轴线的截面模量W2的单位为mm3,柔性支撑系统对单肢立柱提供的切线支撑刚度γT的单位为N/mm,柔性支撑系统对单肢立柱提供的支撑刚度要求的下限值γcr的单位为N/mm,最大支撑力F的单位为N,中部撑杆的欧拉临界力FE的单位为N;Among the above values, the unit of the connecting rod length l 2 is mm, the unit of the cross-sectional moment of inertia I 2 of the connecting rod around its bending axis is mm 4 , and the unit of the section modulus W 2 of the connecting rod around its bending axis is mm 3 , The unit of tangent support stiffness γ T provided by the flexible support system to the single-limb column is N/mm, the lower limit of the support stiffness required by the flexible support system to the single-limb column, γ cr is in N/mm, and the maximum support force F The unit is N, and the unit of the Euler critical force FE of the middle strut is N; 步骤四:根据步骤三初步确定的连杆截面规格得到连杆绕其弯曲轴线的截面模量W2和截面惯性矩I2的实际值;根据步骤三初步确定的连杆绕其弯曲轴线的截面惯性矩I2的实际值计算得到连杆弯曲柔度与中部撑杆轴向柔度的比值η以及柔性支撑系统对单肢立柱提供的实际支撑刚度γ;将柔性支撑系统对单肢立柱提供的实际支撑刚度γ代入步骤二中重新计算得到最大支撑力F;将重新计算得到最大支撑力F代入步骤三中重新验算连杆的受弯整体稳定计算应力σcr2和柔性支撑系统对单肢立柱提供的切线支撑刚度γT是否满足要求,并且,根据重新计算得到最大支撑力F验算中部撑杆的轴压整体稳定承载力Fcr是否满足要求,其中,计算连杆的受弯整体稳定计算应力σcr2时,连杆作为受弯构件时的整体稳定系数
Figure FDA0002327732240000025
应根据连杆截面规格确定;若连杆的受弯整体稳定计算应力σcr2不满足要求,则需要更换更大截面的连杆,以更大截面连杆绕其弯曲轴线的截面模量W2’替换原设计连杆截面模量W2,若柔性支撑系统对单肢立柱提供的切线支撑刚度γT和中部撑杆的轴压整体稳定承载力Fcr中有一项不满足要求,则需要更换截面更大的中部撑杆,以增大后柔性支撑系统中中部撑杆的截面积确定值A1’替代柔性支撑系统中中部撑杆的截面积预设值A1,以增大后中部撑杆的截面最小回转半径i1’替代中部撑杆的截面回转半径预设值i1,并重复步骤一到步骤四,直至连杆的受弯整体稳定计算应力σcr2、柔性支撑系统对单肢立柱提供的切线支撑刚度γT和中部撑杆的轴压整体稳定承载力Fcr均满足要求;
Step 4: Obtain the actual value of the section modulus W 2 and the section moment of inertia I 2 of the connecting rod around its bending axis according to the specification of the connecting rod section preliminarily determined in the third step; The actual value of the moment of inertia I 2 is calculated to obtain the ratio η of the bending flexibility of the connecting rod to the axial flexibility of the middle strut and the actual support stiffness γ provided by the flexible support system to the single-limb column; Substitute the actual support stiffness γ into step 2 to recalculate the maximum support force F; substitute the recalculated maximum support force F into step 3 to re-check the bending overall stability calculation stress σ cr2 of the connecting rod and the flexible support system for the single-limb column. Whether the tangential support stiffness γ T meets the requirements, and, according to the recalculated maximum support force F, check whether the overall stable bearing capacity F cr of axial compression of the middle strut meets the requirements. When cr2 , the overall stability factor of the connecting rod as a flexural member
Figure FDA0002327732240000025
It should be determined according to the section specification of the connecting rod; if the overall stability calculation stress σ cr2 of the connecting rod does not meet the requirements, it is necessary to replace the connecting rod with a larger section, and use the section modulus W 2 of the larger section connecting rod around its bending axis 'Replace the original design link section modulus W 2 , if one of the tangential support stiffness γ T provided by the flexible support system to the single-limb column and the axial compression overall stable bearing capacity F cr of the middle strut does not meet the requirements, it needs to be replaced The middle strut with larger cross section is used to increase the sectional area of the middle strut in the rear flexible support system. Determine the value A 1 ' to replace the preset value A 1 of the sectional area of the middle strut in the flexible support system to increase the rear middle strut The minimum radius of gyration i 1 ' of the section of the rod replaces the preset value i 1 of the radius of gyration of the section of the middle strut, and steps 1 to 4 are repeated until the bending stress of the connecting rod is σ cr2 , and the flexible support system for a single limb The tangential support stiffness γT provided by the column and the overall stable bearing capacity F cr of the axial compression of the middle strut meet the requirements;
柔性支撑系统对单肢立柱提供的实际支撑刚度γ满足下述公式:The actual support stiffness γ provided by the flexible support system to the single-limb column satisfies the following formula:
Figure FDA0002327732240000031
Figure FDA0002327732240000031
连杆的受弯整体稳定计算应力σcr2需满足的要求如下:The requirements for the overall stability calculation stress σ cr2 of the connecting rod are as follows:
Figure FDA0002327732240000032
Figure FDA0002327732240000032
连杆弯曲柔度与中部撑杆轴向柔度的比值η满足下述公式:The ratio η of the bending flexibility of the connecting rod to the axial flexibility of the middle strut satisfies the following formula:
Figure FDA0002327732240000033
Figure FDA0002327732240000033
柔性支撑系统对单肢立柱提供的切线支撑刚度γT需满足的要求如下:The requirements for the tangential support stiffness γ T provided by the flexible support system to the single-limb column are as follows:
Figure FDA0002327732240000034
Figure FDA0002327732240000034
中部撑杆的轴压整体稳定承载力Fcr需满足的要求如下:The requirements for the overall stable bearing capacity F cr of axial compression of the middle strut are as follows: 2F≤Fcr 2F≤Fcr ; 中部撑杆的轴压整体稳定承载力Fcr满足下述公式:The axial compression overall stable bearing capacity F cr of the middle strut satisfies the following formula:
Figure FDA0002327732240000035
Figure FDA0002327732240000035
式中,
Figure FDA0002327732240000036
为中部撑杆的轴压整体稳定系数,根据中部撑杆长细比λ1和其截面分类确定,f1为中部撑杆钢材强度设计值,根据中部撑杆所用钢材的钢材牌号确定;
In the formula,
Figure FDA0002327732240000036
is the overall stability coefficient of the axial pressure of the middle strut, determined according to the slenderness ratio λ 1 of the middle strut and its section classification, f 1 is the design value of the steel strength of the middle strut, determined according to the steel grade of the steel used for the middle strut;
上述数值中,中部撑杆钢材强度设计值f1的单位为N/mm2,中部撑杆的轴压整体稳定承载力Fcr的单位为N。Among the above values, the unit of the steel strength design value f 1 of the middle strut is N/mm 2 , and the unit of the overall stable bearing capacity F cr of the axial pressure of the middle strut is N.
2.如权利要求1所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,所述柔性支撑系统的材料为Q235钢材或Q345钢材,所述中部撑杆为轴心受压钢构件的整体稳定的a类截面或b类截面。2 . The design method for a flexible support system for a double-limb combined cross-section compression-bending column according to claim 1 , wherein the material of the flexible support system is Q235 steel or Q345 steel, and the middle strut is a shaft. 3 . An integrally stable Class A or Class B cross-section of a steel member under central compression. 3.如权利要求2所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,当柔性支撑系统的材料为Q235钢材且中部撑杆为轴心受压构件的a类截面时,考虑了柔性支撑系统的刚度随着支撑力的增大而减小的非线性影响的系数ζ满足下述公式:3. The method for designing a flexible support system for a double-limb combined section compression-bending column according to claim 2, characterized in that, when the material of the flexible support system is Q235 steel and the middle strut is the a of the axial compression member When the cross-section is similar, the coefficient ζ, which takes into account the nonlinear effect of the stiffness of the flexible support system decreasing with the increase of the support force, satisfies the following formula:
Figure FDA0002327732240000041
Figure FDA0002327732240000041
当柔性支撑系统的材料为Q235钢材且中部撑杆为轴心受压构件的b类截面时,考虑了柔性支撑系统的刚度随着支撑力的增大而减小的非线性影响的系数ζ满足下述公式:When the material of the flexible support system is Q235 steel and the middle strut is the type b section of the axial compression member, the coefficient ζ that takes into account the nonlinear effect that the stiffness of the flexible support system decreases with the increase of the support force is satisfied The following formula:
Figure FDA0002327732240000042
Figure FDA0002327732240000042
当柔性支撑系统的材料为Q345钢材且中部撑杆为轴心受压构件的a类截面时,考虑了柔性支撑系统的刚度随着支撑力的增大而减小的非线性影响的系数ζ满足下述公式:When the material of the flexible support system is Q345 steel and the middle strut is the type a section of the axial compression member, the coefficient ζ that takes into account the nonlinear effect that the stiffness of the flexible support system decreases with the increase of the support force is satisfied The following formula:
Figure FDA0002327732240000043
Figure FDA0002327732240000043
当柔性支撑系统的材料为Q345钢材且中部撑杆为轴心受压构件的b类截面时,考虑了柔性支撑系统的刚度随着支撑力的增大而减小的非线性影响的系数ζ满足下述公式:When the material of the flexible support system is Q345 steel and the middle strut is the type b section of the axial compression member, the coefficient ζ that takes into account the nonlinear effect that the stiffness of the flexible support system decreases with the increase of the support force is satisfied The following formula:
Figure FDA0002327732240000044
Figure FDA0002327732240000044
4.如权利要求1-3任一所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,当n=1时,最大支撑力F满足下述公式:4. The design method for a flexible support system for a double-limb combined section compression-bending column according to any one of claims 1-3, wherein when n=1, the maximum support force F satisfies the following formula: F=γΔABF= γΔAB ; 式中,ΔAB为中部支撑处单肢压弯柱挠度,上述公式在初步计算时取γ=γ0,在确定中部撑杆的截面规格以及连杆的截面规格后取
Figure FDA0002327732240000045
In the formula, ΔAB is the deflection of the single-limb compression-bending column at the middle support, the above formula is taken as γ=γ 0 in the preliminary calculation, after the section specification of the middle brace and the connecting rod are determined, take
Figure FDA0002327732240000045
中部支撑处单肢压弯柱挠度ΔAB满足下述公式:The deflection ΔAB of the single-leg bending column at the central support satisfies the following formula:
Figure FDA0002327732240000046
Figure FDA0002327732240000046
式中,C和S为单肢压弯柱的抗弯刚度系数,MFBA为一端铰接、一端固接的单肢压弯柱节段的固端弯矩,K为单肢压弯柱线刚度,l=L/2;where C and S are the flexural stiffness coefficients of the single-limb bending column, M FBA is the fixed-end bending moment of the single-limb bending-column segment hinged at one end and fixed at the other end, and K is the linear stiffness of the single-limb bending-column segment. , l=L/2; 上述数值中,支撑间柱高l的单位为mm,轴向压力N的单位为N,横向均布荷载q的单位为N/mm,中部支撑处单肢压弯柱挠度ΔAB的单位为mm,单肢压弯柱线刚度K的单位为N·mm,支撑刚度γ的单位为N/mm;Among the above values, the unit of column height l between supports is mm, the unit of axial pressure N is N, the unit of lateral uniform load q is N/mm, and the unit of deflection ΔAB of the single-leg bending column at the central support is mm , the unit of single-limb bending column stiffness K is N mm, and the unit of support stiffness γ is N/mm; 当n=2时,最大支撑力F满足下述公式:When n=2, the maximum supporting force F satisfies the following formula: F=γΔABF= γΔAB ; 式中,ΔAB为L/3和2L/3柱高处单肢压弯柱挠度,上述公式在初步计算时取γ=γ0,在确定中部撑杆的截面规格以及连杆的截面规格后取
Figure FDA0002327732240000047
In the formula, ΔAB is the deflection of the single-leg bending column at L/3 and 2L/3 column heights. The above formula takes γ=γ 0 in the preliminary calculation. After determining the section specification of the middle strut and the section specification of the connecting rod Pick
Figure FDA0002327732240000047
L/3和2L/3柱高处单肢压弯柱挠度ΔAB满足下述公式:The deflection ΔAB of the single-leg bending column at the height of the L/3 and 2L/3 columns satisfies the following formula:
Figure FDA0002327732240000051
Figure FDA0002327732240000051
式中,C和S为单肢压弯柱的抗弯刚度系数,MFBA为一端铰接、一端固接的单肢压弯柱节段的固端弯矩,MFBC为两端固接压弯构件的固端弯矩,K为单肢压弯柱线刚度,l=L/3;where C and S are the flexural stiffness coefficients of the single-limb compression-bending column, M FBA is the fixed-end bending moment of the single-limb compression-bending column segment with one end hinged and one end fixed, and M FBC is the fixed-end bending moment Bending moment at the fixed end of the member, K is the linear stiffness of the single-leg bending column, l=L/3; 上述数值中,支撑间柱高l的单位为mm,轴向压力N的单位为N,横向均布荷载q的单位为N/mm,L/3和2L/3柱高处单肢压弯柱挠度ΔAB的单位为mm,单肢压弯柱线刚度K的单位为N·mm,支撑刚度γ的单位为N/mm;In the above values, the unit of column height l between supports is mm, the unit of axial pressure N is N, the unit of lateral uniform load q is N/mm, and the unit of single-limb bending column at L/3 and 2L/3 column heights is The unit of deflection ΔAB is mm, the unit of linear stiffness K of single limb bending column is N·mm, and the unit of support stiffness γ is N/mm; 当n=3时,最大支撑力F满足下述公式:When n=3, the maximum supporting force F satisfies the following formula: F=γΔACF=γΔ AC ; 式中,ΔAC为单肢压弯柱跨中挠度,上述公式在初步计算时取γ=γ0,在确定中部撑杆的截面规格以及连杆的截面规格后取
Figure FDA0002327732240000052
In the formula, Δ AC is the mid-span deflection of the single-limb compression-bending column. The above formula is taken as γ=γ 0 in the preliminary calculation, and is taken after determining the section specifications of the middle strut and the connecting rod.
Figure FDA0002327732240000052
单肢压弯柱跨中挠度ΔAC满足下述公式:The mid-span deflection Δ AC of a single-leg bending column satisfies the following formula: ΔAC=ΔABBCΔ ACABBC ;
Figure FDA0002327732240000053
Figure FDA0002327732240000053
式中,c11=K(C+S),c12=-γl/2,c13=N-γl/2-2K(C+S)/l,c21=KC,c22=3γl/2-N,c23=γl/2-K(C+S)/l,c31=K(2C2-S2)/C,c32=K(S2-C2)/(Cl),c33=-K(C+S)/l,d1=-ql2/2,d2=3ql2/2-MFBC,d3=-MFBC-MFBA;θA为单肢压弯柱柱顶处的柱转角,θB为单肢压弯柱四分之一柱高处的柱转角,ΔAB和ΔAC分别为单肢压弯柱四分之一和二分之一柱高处的挠度,ΔBC为二分之一柱高处的挠度相对于四分之一柱高处挠度的增量,C和S为单肢压弯柱的抗弯刚度系数,MFBA为一端铰接、一端固接的单肢压弯柱节段的固端弯矩,MFBC为两端固接压弯构件的固端弯矩,K为单肢压弯柱线刚度,l=L/4;In the formula, c 11 =K(C+S), c 12 =-γl/2, c 13 =N-γl/2-2K(C+S)/l, c 21 =KC, c 22 =3γl/2 -N, c 23 =γl/2-K(C+S)/l, c 31 =K(2C 2 -S 2 )/C, c 32 =K(S 2 -C 2 )/(Cl),c 33 = -K(C+S)/l, d 1 = -ql 2 /2, d 2 = 3ql 2 /2 - M FBC , d 3 = - M FBC - M FBA ; θ A is a single limb bending column Column rotation angle at the top of the column, θB is the column rotation angle at the quarter column height of the single-limb bending column, ΔAB and ΔAC are the single-limb bending column quarter and half the column height, respectively ΔBC is the increment of the deflection at one-half column height relative to the deflection at one-quarter column height, C and S are the flexural stiffness coefficients of single-limb compression-bending columns, M FBA is one end hinged, The fixed-end bending moment of the single-leg bending column segment fixed at one end, M FBC is the fixed-end bending moment of the two-end fixed bending member, K is the linear stiffness of the single-leg bending column, l=L/4; 上述数值中,支撑间柱高l的单位为mm,轴向压力N的单位为N,横向均布荷载q的单位为N/mm,立柱各项挠度值ΔAC、ΔAB和ΔBC的单位为mm,,单肢压弯柱线刚度K的单位为N·mm,支撑刚度γ的单位为N/mm;In the above values, the unit of column height l between supports is mm, the unit of axial pressure N is N, the unit of lateral uniform load q is N/mm, the unit of column deflection values Δ AC , Δ AB and Δ BC is mm, the unit of linear stiffness K of single limb bending column is N mm, and the unit of support stiffness γ is N/mm; 当n=4时,最大支撑力F满足下述公式:When n=4, the maximum support force F satisfies the following formula: F=γΔACF=γΔ AC ; 式中,ΔAC为单肢压弯柱2L/5和3L/5柱高处挠度,上述公式在初步计算时取γ=γ0,在确定中部撑杆的截面规格以及连杆的截面规格后取
Figure FDA0002327732240000061
In the formula, Δ AC is the deflection at the height of the single-limb bending column 2L/5 and 3L/5. The above formula is taken as γ=γ 0 in the preliminary calculation. After determining the section specifications of the middle strut and the connecting rod Pick
Figure FDA0002327732240000061
立柱中部2L/5和3L/5柱高处挠度ΔAC满足下述公式:The deflection Δ AC at the height of the 2L/5 and 3L/5 columns in the middle of the column satisfies the following formula: ΔAC=ΔABBCΔ ACABBC ;
Figure FDA0002327732240000062
Figure FDA0002327732240000062
ΔAB=(CθA+SθB)l/(C+S);ΔAB=( CθA + SθB )l/( C +S); ΔBC=l[(2C-S)θC+SθB]/(C+S);Δ BC =l[(2C-S)θ C +Sθ B ]/(C+S); 式中,a11=K(S-C),a12=2K(C-S),a13=2K(S-C),a21=K(S2-C2)+(Nl-2γl2)C,a22=K(C2-S2)+(Nl-3γl2)S,a23=γl2(S-2C),a31=-Cγl2,a32=K(C2-S2)+(Nl-2γl2)S,a33=3K(S2-C2)+(Nl-γl2)(2C-S),b1=-MFBA-MFBC,b2=-(C+S)(MFBA+2ql2),b3=-(C+S)ql2;θA为单肢压弯柱柱顶处的柱转角,θB为单肢压弯柱五分之一柱高处的柱转角,θC为单肢压弯柱五分之二柱高处的柱转角,ΔAB为单肢压弯柱五分之一柱高处的压弯柱挠度,ΔBC为单肢压弯柱五分之二柱高处的挠度相较于五分之一柱高处挠度的增量,C和S为单肢压弯柱的抗弯刚度系数,MFBA为一端铰接、一端固接的单肢压弯柱节段的固端弯矩,MFBC为两端固接单肢压弯柱节段的固端弯矩,K为单肢压弯柱线刚度,l=L/5;In the formula, a 11 =K(S-C), a 12 =2K(CS), a 13 =2K(S-C), a 21 =K(S 2 -C 2 )+(Nl-2γl 2 )C, a 22 =K(C 2 -S 2 )+(Nl-3γl 2 )S, a 23 =γl 2 (S-2C), a 31 =-Cγl 2 , a 32 =K(C 2 -S 2 )+(Nl−2γl 2 )S, a 33 =3K(S 2 −C 2 )+(Nl−γl 2 )(2C−S), b 1 =−M FBA −M FBC , b 2 =−( C+S)(M FBA +2ql 2 ), b 3 =-(C+S)ql 2 ; θ A is the column rotation angle at the top of the single-limb bending column, θ B is one-fifth of the single-limb bending column The column rotation angle at the height of one column, θ C is the column rotation angle at the height of two-fifths of the column height of the single-leg bending column, ΔAB is the bending column deflection at the one-fifth column height of the single-leg bending column, ΔBC is the increment of the deflection at the height of two-fifths of the single-leg bending column compared to the deflection at one-fifth of the height of the column, C and S are the flexural stiffness coefficients of the single-leg bending column, and M FBA is the hinge at one end , the fixed-end bending moment of the single-limb compression-bending column segment fixed at one end, M FBC is the fixed-end bending moment of the single-limb compression-bending column segment fixed at both ends, K is the single-limb compression-bending column line stiffness, l= L/5; 上述数值中,支撑间柱高l的单位为mm,轴向压力N的单位为N,横向均布荷载q的单位为N/mm,立柱各项挠度值ΔAC、ΔAB和ΔBC的单位为mm,单肢压弯柱线刚度K的单位为N·mm,支撑刚度γ的单位为N/mm;In the above values, the unit of column height l between supports is mm, the unit of axial pressure N is N, the unit of lateral uniform load q is N/mm, the unit of column deflection values Δ AC , Δ AB and Δ BC is mm, the unit of single-limb bending column line stiffness K is N mm, and the unit of support stiffness γ is N/mm; 当n>4时,最大支撑力F按照n=4时计算。When n>4, the maximum supporting force F is calculated as n=4.
5.如权利要求4所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,单肢压弯柱的抗弯刚度系数C满足下述公式:5. the design method of a kind of double-limb combined section compression-bending column flexible support system as claimed in claim 4, is characterized in that, the flexural rigidity coefficient C of single-limb compression-bending column satisfies the following formula:
Figure FDA0002327732240000063
Figure FDA0002327732240000063
单肢压弯柱的抗弯刚度系数S满足下述公式:The flexural stiffness coefficient S of a single-limb flexural column satisfies the following formula:
Figure FDA0002327732240000064
Figure FDA0002327732240000064
式中,k为计算系数;In the formula, k is the calculation coefficient; 计算系数k满足下述公式:The calculation coefficient k satisfies the following formula:
Figure FDA0002327732240000071
Figure FDA0002327732240000071
一端铰接、一端固接的单肢压弯柱节段的固端弯矩MFBA满足下述公式,以使得杆段顺时针方向旋转为正,逆时针方向旋转为负:The fixed-end bending moment M FBA of a single-limb compression-bending column segment hinged at one end and fixed at one end satisfies the following formula, so that the clockwise rotation of the rod segment is positive, and the counterclockwise rotation is negative:
Figure FDA0002327732240000072
Figure FDA0002327732240000072
两端固接单肢压弯柱节段的固端弯矩MFBC满足下述公式,以使得杆段顺时针方向旋转为正,逆时针方向旋转为负:The fixed-end bending moment M FBC of the single-limb compression-bending column segment fixed at both ends satisfies the following formula, so that the clockwise rotation of the rod segment is positive, and the counterclockwise rotation is negative:
Figure FDA0002327732240000073
Figure FDA0002327732240000073
单肢压弯柱线刚度K满足下述公式:The linear stiffness K of the single limb bending column satisfies the following formula: K=EIc/l;K=EI c /l; 式中,Ic为单肢压弯柱绕其弯曲轴线的截面惯性矩,E为结构钢材弹性模量;where I c is the moment of inertia of the single-limb compression-bending column around its bending axis, and E is the elastic modulus of the structural steel; 所述单肢压弯柱为双轴对称热轧型钢或焊接组合截面构件;The single-limb compression-bending column is a biaxially symmetrical hot-rolled section steel or a welded composite section member; 当单肢压弯柱为热轧型钢时,单肢压弯柱绕其弯曲轴线的截面惯性矩Ic可通过直接查询型钢表获得;When the single-leg bending column is a hot-rolled section steel, the section moment of inertia I c of the single-leg bending column around its bending axis can be obtained by directly querying the section steel table; 当单肢压弯柱为焊接组合截面构件时,若单肢压弯柱为焊接H形截面,单肢压弯柱绕其弯曲轴线的截面惯性矩Ic满足下述公式:When the single-leg bending column is a welded composite section member, if the single-leg bending column is a welded H-shaped section, the section moment of inertia I c of the single-leg bending column around its bending axis satisfies the following formula:
Figure FDA0002327732240000074
Figure FDA0002327732240000074
式中,H为焊接H形截面总高度,B为焊接H形截面宽度,t1为焊接H形截面腹板厚度,t2为H形截面翼缘厚度;where H is the total height of the welded H-shaped section, B is the width of the welded H-shaped section, t1 is the thickness of the web of the welded H-shaped section, and t2 is the thickness of the flange of the H-shaped section; 若单肢压弯柱为焊接矩形管截面,单肢压弯柱绕其弯曲轴线的截面惯性矩Ic满足下述公式:If the single-leg bending column is a welded rectangular tube section, the moment of inertia I c of the single-leg bending column around its bending axis satisfies the following formula:
Figure FDA0002327732240000075
Figure FDA0002327732240000075
式中,a1为焊接矩形管截面平行于弯曲轴线边的边长,a2为焊接矩形管截面垂直于弯曲轴线边的边长,t′为焊接矩形管截面壁厚;In the formula, a 1 is the side length of the welded rectangular tube section parallel to the bending axis, a 2 is the side length of the welded rectangular tube section perpendicular to the bending axis, and t' is the wall thickness of the welded rectangular tube section; 若单肢压弯柱为焊接圆管截面,单肢压弯柱绕其弯曲轴线的截面惯性矩Ic满足下述公式:If the single-leg bending column is a welded circular pipe section, the moment of inertia I c of the single-leg bending column around its bending axis satisfies the following formula: Ic=π[D4-(D-2t″)4]/64I c =π[D 4 -(D-2t″) 4 ]/64 式中,D为焊接圆管截面外径,t″为焊接圆管截面壁厚;In the formula, D is the outer diameter of the welded circular pipe section, and t″ is the wall thickness of the welded circular pipe section; 上述数值中,MFBA的单位为N·mm,MFBC的单位为N·mm,单肢压弯柱绕其弯曲轴线的截面惯性矩Ic的单位为mm4Among the above values, the unit of M FBA is N·mm, the unit of M FBC is N·mm, and the unit of section inertia moment I c of the single-limb bending column around its bending axis is mm 4 .
6.如权利要求1-5任一所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,所述双肢组合截面压弯柱包括两个单肢压弯柱,焊接于两个单肢压弯柱之间的连接墙板,焊接于连接墙板上、垂直于两个单肢压弯柱的加劲肋;所述双肢组合截面压弯柱的柔性支撑系统包括连杆以及中部撑杆;所述连杆焊接于两个单肢压弯柱之间且位于两个单肢压弯柱截面形心连线上;所述中部撑杆垂直于连接墙板且所述中部撑杆焊接于连杆沿长度方向的二分之一处。6. The design method for a flexible support system for a double-limb combined cross-section bending column according to any one of claims 1-5, wherein the double-limb combined cross-section bending column comprises two single-limb bending columns , welded on the connecting wall plate between two single-limb bending columns, welded on the connecting wall plate and the stiffening rib perpendicular to the two single-limb bending columns; the flexible support system of the double-limb combined section bending column It includes a connecting rod and a middle strut; the connecting rod is welded between two single-limb compression-bending columns and is located on the line connecting the cross-section centroids of the two single-limb compression-bending columns; the middle strut is perpendicular to the connecting wall plate and The middle strut is welded to half of the connecting rod along the length direction. 7.如权利要求1-6任一所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,所述中部撑杆的截面是指中部撑杆垂直于Y轴的截面。7. The design method for a flexible support system for a double-limb combined cross-section compression-bending column according to any one of claims 1-6, wherein the cross-section of the middle strut refers to the section of the middle strut perpendicular to the Y-axis. section. 8.如权利要求1-7任一所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,所述中部撑杆为双轴对称截面钢构件。8 . The design method for a flexible support system for a double-limb combined cross-section compression-bending column according to any one of claims 1 to 7 , wherein the middle brace is a biaxially symmetric cross-section steel member. 9 . 9.如权利要求1-7任一所述的一种双肢组合截面压弯柱柔性支撑系统的设计方法,其特征在于,所述连杆为对称截面钢构件。9 . The design method for a flexible support system for a double-limb combined cross-section compression-bending column according to claim 1 , wherein the connecting rod is a steel member with a symmetrical section. 10 . 10.权利要求1-9任一所述的设计方法在设计双肢组合截面压弯柱柔性支撑系统方面的应用。10. The application of the design method of any one of claims 1 to 9 in designing a flexible support system for a double-limb combined cross-section compression-bending column.
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