CN110288099B - Preventive maintenance spare part scheme optimization method and device - Google Patents
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Abstract
Description
技术领域technical field
本发明涉及故障预测与备件保障领域,具体而言,涉及一种预防性维修备件方案优化方法。The invention relates to the field of failure prediction and spare parts guarantee, in particular to a method for optimizing a preventive maintenance spare parts plan.
背景技术Background technique
开展对产品的预防性维修工作一般是通过检测明确的物理指标来量化产品的老化状态,从而能够及时开展预防性维修,在产品失效前将其更换,避免重大事故的发生。Carrying out preventive maintenance work on products generally quantifies the aging state of products by detecting clear physical indicators, so that preventive maintenance can be carried out in time, and products can be replaced before they fail to avoid major accidents.
对未明确有物理指标的产品,或有明确的物理指标,但是感知这些物理指标的探测器成本过高时,一般的预防性维修工作则难以开展及推广。For products that do not have clear physical indicators, or have clear physical indicators, but the cost of detectors that sense these physical indicators is too high, it is difficult to carry out and promote general preventive maintenance work.
发明内容Contents of the invention
本发明实施例至少公开一种预防性维修备件方案优化方法,能够在不明确描述产品老化状态的物理指标情况下,合理地实现对部件中需要更换的单元及单元的数量。The embodiment of the present invention discloses at least one method for optimizing the preventive maintenance spare parts plan, which can reasonably realize the units and the number of units that need to be replaced in the components without clearly describing the physical indicators of the aging state of the product.
所述方法包括:The methods include:
S100、归类具有相同初始状态的至少一个部件在同一部件类别;S100. Classifying at least one component with the same initial state in the same component category;
S200、获取每个所述部件类别中的至少一个备件方案;S200. Acquire at least one spare parts solution in each component category;
S300、组合每个所述部件类别中的任一所述备件方案为至少一个总体备件方案,以及评估所述总体备件方案的达标概率;S300. Combining any one of the spare parts schemes in each of the component categories into at least one overall spare parts scheme, and evaluating the compliance probability of the overall spare parts scheme;
S400、选择所述达标概率符合预置条件的所述总体备件方案为所述预防性维修备件方案。S400. Select the overall spare parts plan whose compliance probability meets a preset condition as the preventive maintenance spare part plan.
在本发明公开的一些实施例中,S100被配置有:In some embodiments disclosed in the present invention, S100 is configured with:
S110、获取所述部件的全部或部分单元的状态;S110. Obtain the state of all or part of the units of the component;
S120、根据所有所述单元的完好状态或失效状态确定所述初始状态,并且归类具有相同所述初始状态的所述部件在同一所述部件类别。S120. Determine the initial state according to the sound state or failure state of all the units, and classify the components with the same initial state into the same component category.
在本发明公开的一些实施例中,S110被配置为通过具有dyN项的数组dyFlag来描述所述部件全部或部分的单元,In some embodiments disclosed in the present invention, S110 is configured to describe all or part of the units of the component through an array dyFlag having dyN items,
dyFlag的第i项变量为dyFlagi,用于描述所述部件中第i项所述单元的所述完好状态或所述失效状态;The i-th variable of dyFlag is dyFlag i , which is used to describe the sound state or the failure state of the unit in the i-th item in the component;
S120被配置为通过矩阵bjState描述所述初始状态及所述部件类别,bjState的第j行向量bjState(j,:)为[dyFlag nFlagj],nFlagj用于描述第j类所述部件类别中部件的数量。S120 is configured to describe the initial state and the component category through the matrix bjState, the j-th row vector bjState(j,:) of bjState is [dyFlag nFlag j ], and nFlag j is used to describe the component category of the j-th category The number of parts.
在本发明公开的一些实施例中,S200被配置为:In some embodiments disclosed in the present invention, S200 is configured as:
S200被配置为:S200 is configured as:
S210、使类别序号j=1;S210, make the category number j=1;
S220、初始化方案序号j2=0,S220, initialization scheme serial number j2=0,
通过数组Ns描述第j类所述部件类别中部件的一备件方案,A spare part scheme for components in the component category described in category j is described by an array Ns,
Nsi是第i项所述单元的备件数量1≤i≤dyN;Ns i is the number of spare parts of the unit described in item i 1≤i≤dyN;
S230、调用一部件备件方案评估模块,评估所述备件方案Ns的维修效果为bjP;S230. Invoke a component spare part solution evaluation module, and evaluate the maintenance effect of the spare part solution Ns as bjP;
S240、S240,
取j2=j2+1,Take j2=j2+1,
获取费用 acquisition fee
更新矩阵plan,plan(j2,:)=[j2 bjP Mnow Ns];Update matrix plan, plan(j2,:)=[j2 bjP Mnow Ns];
S250、判断在时进入S260,在时生成下一备件方案;S250, judge exist When entering S260, in generate the next spare parts plan;
S260、取planAll(1:j2,iy1:iy2)=plan,iy1=(j-1)(3+dyN)+1,iy2=j(3+dyN),取planNj=j2;S260. Take planAll(1:j2, iy1:iy2)=plan, iy1=(j-1)(3+dyN)+1, iy2=j(3+dyN), take planN j =j2;
S270、取j=j+1,在j≤N1时返回S220,在j>N1则进入S300;S270. Take j=j+1, return to S220 when j≤N1, and enter S300 when j>N1;
S300被配置为利用planAll,组合每一类所述类别部件中所述部件的一备件方案为至少一个所述总体备件方案。S300 is configured to use planAll to combine a spare part plan for the parts in each category of the category parts into at least one overall spare part plan.
在本发明公开的一些实施例中,In some embodiments disclosed in the present invention,
S250被配置为判断在时进入S260,在时生成下一备件方案,进入S251;The S250 is configured to judge exist When entering S260, in When generating the next spare parts plan, enter S251;
S250被配置有:The S250 is configured with:
S251、取候选序号k=1,S251. Take the candidate sequence number k=1,
S252、生成候选方案Nt, S252. Generate a candidate solution Nt,
S253、根据候选方案Nt,调用所述部件备件方案评估模块,评估所述候选方案Nt的维修效果为bjPt,边际效费比 S253. According to the candidate solution Nt, call the parts and spare parts solution evaluation module, and evaluate the maintenance effect of the candidate solution Nt as bjPt, and the marginal benefit cost ratio
S254、取k=k+1,在k≤dyN时返回S252,在k>dyN时进入S255,S254, take k=k+1, return to S252 when k≤dyN, enter S255 when k>dyN,
S255、在所有p2mk,1≤k≤dyN中找到p2mk的最大值,并且记录p2mk最大值对应的候选序号Im,更新Ns中的NsIm=nFlagj后返回S230。S255. Find the maximum value of p2m k among all p2m k , 1≤k≤dyN, record the candidate serial number Im corresponding to the maximum value of p2m k , update Ns Im =nFlag j in Ns, and return to S230.
在本发明公开的一些实施例中,S300被配置有:In some embodiments disclosed in the present invention, S300 is configured with:
S310、初始化描述总体备件方案的数组planID,planIDj=1,1≤j≤N1;第j项的planIDj是第j类所述部件类别中所述备件方案的序号,S310. Initialize the array planID describing the overall spare parts plan, planID j = 1, 1≤j≤N1; the planID j of the jth item is the serial number of the spare parts plan in the component category of the jth class,
初始化每一类部件类别的优化标志bjFj=1,1≤j≤N1,Initialize the optimization flag bjF j =1, 1≤j≤N1 for each type of component category,
初始化总体方案序号i2=0;Initialize the overall scheme number i2=0;
S320、调用总体备件方案评估模块,获取所述总体备件方案的所述达标概率为Pm,所述备件费用为Mm,S320. Invoking the evaluation module of the overall spare parts scheme, obtaining the probability of reaching the standard of the overall spare parts scheme as Pm, and the cost of the spare parts as Mm,
取i2=i2+1,Take i2=i2+1,
矩阵result的第i2行向量result(i2,:)=[Mm Pm planID];Vector result(i2,:)=[Mm Pm planID] in row i2 of matrix result;
S330被配置有:The S330 is configured with:
S331、判断在时进入S332,在时进入S400,S331. Judgment exist Enter S332 when enter S400,
S332、取部件类别的序号j=1,S332. Take the serial number j=1 of the component category,
S333、取IDt=planID,IDtj=IDtj+1,S333. Get IDt = planID, IDt j = IDt j + 1,
S334、在IDtj>planNj时,取bjFj=0以及p2mj=0,S334. When IDt j > planN j , take bjF j =0 and p2m j =0,
在IDtj≤planNj时调用总体备件方案评估模块,获取所述总体备件方案的所述达标概率记为Ptj,所述备件费用记为Mtj,边际效费比 When IDt j ≤ planN j , the overall spare parts program evaluation module is called, and the attainment probability of the overall spare parts program is denoted as Pt j , the cost of spare parts is denoted as Mt j , and the marginal benefit-cost ratio
S335、取j=j+1,在j≤N1时进入S333,在j>N1时进入S336,S335, set j=j+1, enter S333 when j≤N1, enter S336 when j>N1,
S336、在所有p2mj,1≤j≤N1中找到最大值对应的序号为Im,S336. Find the serial number corresponding to the maximum value in all p2m j , 1≤j≤N1, which is Im,
在时,取planIDIm=planIDIm+1,Pm=PtIm,Mm=MtIm,保存结果到矩阵result:取i2=i2+1,取result的第i2行向量result(i2,:)=[Mm Pm planID]后返回S331;exist , take planID Im =planID Im + 1, Pm=Pt Im , Mm=Mt Im , save the result to the matrix result: take i2=i2+1, take the i2th row vector of result result(i2,:)=[Mm Pm planID] and return to S331;
在时,转S400;exist , turn to S400;
S400被配置为根据矩阵result获取所述达标概率Pm=P(n>M)的所述总体备件方案为所述预防性维修备件方案。S400 is configured to acquire the overall spare parts plan with the attainment probability Pm=P (n>M) as the preventive maintenance spare part plan according to the matrix result.
在本发明公开的一些实施例中,S400被配置为根据矩阵result绘制效费曲线;In some embodiments disclosed in the present invention, S400 is configured to draw an efficiency curve according to the matrix result;
所述效费曲线的X轴为所述总体备件方案的费用,Y轴为达标概率Pm=P(n>M);The X-axis of the cost curve is the cost of the overall spare parts plan, and the Y-axis is the probability of reaching the standard Pm=P (n>M);
查询所述曲线获取所述达标概率Pm=P(n>M)及所述备件费用最少的所述总体备件方案为所述预防性维修备件方案。The preventive maintenance spare parts plan is obtained by querying the curve to obtain the overall spare parts plan with the attainment probability Pm=P (n>M) and the least spare part cost.
在本发明公开的一些实施例中,调用所述部件备件方案评估模块评估所述备件方案的维修效果,被配置为:In some embodiments disclosed in the present invention, calling the component spare parts solution evaluation module to evaluate the maintenance effect of the spare parts solution is configured as:
取 Pick
dyPi是第i项单元为预置时间后的可靠度,p0及p1是第i项单元的寿命服从伽玛分布或对数正态分布或正态分布或威布尔分布的取值。dyP i is the reliability of the i-th unit after the preset time, p0 and p1 are the values that the life of the i-th unit obeys the gamma distribution, lognormal distribution, normal distribution or Weibull distribution.
在本发明公开的一些实施例中,调用所述部件备件方案评估模块评估所述总体备件方案,被配置为:In some embodiments disclosed in the present invention, calling the parts and spare parts plan evaluation module to evaluate the overall spare parts plan is configured as:
S321、初始化类别序号j=1,备件费用Mt=0。S321. Initialize the category number j=1, and spare part cost Mt=0.
S322、从planAll中获取第j类所述部件类别中所述备件方案序号为j2=planIDj的所述备件方案、可靠度bjP及所述备件费用Mnow;S322. Obtain the spare part plan, reliability bjP, and spare part cost Mnow of the spare part plan number j2=planID j in the component category of the jth category from planAll;
取Mt=Mt+Mnow;Take Mt=Mt+Mnow;
S323、取x1为从0~nFlagj的递增数列,步长为1,遍历计算x1k对应的概率1≤k≤1+nFlagj,得到向量p1;S323. Take x1 as an increasing sequence from 0 to nFlag j , with a step size of 1, and iteratively calculate the probability corresponding to x1 k 1≤k≤1+nFlag j , get the vector p1;
S324、在j>1时计算p1和p2的卷积,并把结果赋给p2;S324. Calculate the convolution of p1 and p2 when j>1, and assign the result to p2;
否则,取p2=p1。Otherwise, take p2=p1.
S325、取j=j+1,在j≤N1时返回S322,在j>N1时进入S326;S325. Take j=j+1, return to S322 when j≤N1, and enter S326 when j>N1;
S326、取总体备件方案planID的达标概率总体备件方案planID的备件费用Mm=Mt。S326. Obtain the probability of reaching the standard of the overall spare parts plan planID The spare parts cost Mm=Mt of the overall spare parts plan planID.
本发明实施例至少公开一种预防性维修备件方案构建装置。The embodiment of the present invention discloses at least one device for constructing a preventive maintenance spare parts plan.
所述装置包括:The devices include:
分类模块,用于归类具有相同初始状态的至少一个部件在同一部件类别;A classification module, configured to classify at least one component with the same initial state in the same component category;
备件模块,用于获取每个所述部件类别中的至少一个备件方案;a spare parts module for obtaining at least one spare parts solution in each of said component categories;
组合模块,组合每个所述部件类别中的任一所述备件方案为至少一个总体备件方案,以及评估所述总体备件方案的达标概率;A combination module, combining any one of the spare parts schemes in each of the component categories into at least one overall spare parts scheme, and evaluating the compliance probability of the overall spare parts scheme;
选择模块,选择所述达标概率符合预置条件的所述总体备件方案为所述预防性维修备件方案。A selection module, selecting the overall spare parts plan whose compliance probability meets a preset condition as the preventive maintenance spare parts plan.
针对上述方案,本发明通过以下参照附图对公开的示例性实施例作详细描述,亦使本发明实施例的其它特征及其优点清楚。In view of the above solutions, the present invention will describe the disclosed exemplary embodiments in detail below with reference to the accompanying drawings, and also make other features and advantages of the embodiments of the present invention clear.
附图说明Description of drawings
为了更清楚地说明本发明实施例的技术方案,下面将对实施例中所需要使用的附图作简单地介绍,应当理解,以下附图仅示出了本发明的某些实施例,因此不应被看作是对范围的限定,对于本领域普通技术人员来讲,在不付出创造性劳动的前提下,还可以根据这些附图获得其他相关的附图。In order to illustrate the technical solutions of the embodiments of the present invention more clearly, the accompanying drawings used in the embodiments will be briefly introduced below. It should be understood that the following drawings only show some embodiments of the present invention, and thus It should be regarded as a limitation on the scope, and those skilled in the art can also obtain other related drawings based on these drawings without creative work.
图1为本实施例提供的优化预防性维修备件方案的方法流程图;Fig. 1 is the flow chart of the method for optimizing the preventive maintenance spare parts scheme provided by the present embodiment;
图2为本实施例提供的优化预防性维修备件方案的功能模块图;Fig. 2 is the functional block diagram of the optimized preventive maintenance spare parts scheme provided by the present embodiment;
图3为本实施例提供示例中备件方案的效费曲线图。Fig. 3 is an efficiency-cost curve diagram of the spare parts solution in the example provided in this embodiment.
具体实施方式detailed description
为使本发明实施例的目的、技术方案和优点更加清楚,下面将结合本发明实施例中的附图,对本发明实施例中的技术方案进行清楚、完整地描述,显然,所描述的实施例是本发明一部分实施例,而不是全部的实施例。通常在此处附图中描述和示出的本发明实施例的组件可以以各种不同的配置来布置和设计。In order to make the purpose, technical solutions and advantages of the embodiments of the present invention clearer, the technical solutions in the embodiments of the present invention will be clearly and completely described below in conjunction with the drawings in the embodiments of the present invention. Obviously, the described embodiments It is a part of embodiments of the present invention, but not all embodiments. The components of the embodiments of the invention generally described and illustrated in the figures herein may be arranged and designed in a variety of different configurations.
如本文中所使用,根据上下文,术语“如果”任选地被解释为意思是“当……时”(“when”或“upon”)或“响应于确定”或“响应于检测到”。类似地,根据上下文,短语“如果确定……”或“如果检测到[所陈述的条件或事件]”任选地被解释为意思是“在确定……时”或“响应于确定……”或“在检测到[所陈述的条件或事件]时”或“响应于检测到[所陈述的条件或事件]”。As used herein, the term "if" is optionally interpreted to mean "when" or "upon" or "in response to determining" or "in response to detecting," depending on the context. Similarly, the phrases "if it is determined that ..." or "if [the stated condition or event] is detected" are optionally construed to mean "when determining ..." or "in response to determining ..." depending on the context Or "upon detection of [stated condition or event]" or "in response to detection of [stated condition or event]".
另外,在附图的流程图示出的步骤可以在诸如一组计算机可执行指取的计算机装置中执行,并且,虽然在流程图中示出了逻辑顺序,但是在某些情况下,可以以不同于此处的顺序执行所示出或描述的步骤。In addition, the steps shown in the flow diagrams of the figures may be performed in a computer device, such as a set of computer-executable instructions, and, although a logical order is shown in the flow diagrams, in some cases, may be implemented in The steps shown or described are performed in an order different than here.
本实施例提及的部件一般是指由至少一项单元构成的某中间层结构的产品;部件包括的各项单元之间一般能够用可靠性连接关系来描述。The components mentioned in this embodiment generally refer to a product of an intermediate layer structure composed of at least one unit; the units included in the component can generally be described by a reliable connection relationship.
常见的单间之间的可靠性连接关系为串联关系、并联关系及混联关系等。如果按照单元是否为关重件的标准对部件中的所有单元进行取舍,那么部件能够被简化成一个由至少一项关重件串联而成的产品。The common reliability connection relationships between single rooms are series relationship, parallel relationship and mixed connection relationship. If all the units in the component are selected according to whether the unit is a critical component, the component can be simplified into a product composed of at least one critical component in series.
由上述,本实施例在后所指部件是单元之间的可靠性关系均为串联关系的产品;单元均是符合标准的关重件。From the above, the components referred to in the following embodiments in this embodiment are products in which the reliability relationship between the units is a series relationship; the units are all critical parts that meet the standards.
具体的,所述部件由dyN项所述单元组成,已知每个单元的寿命分布规律和单价dyMi,1≤i≤dyN;当前维修时刻为T1;当前共有同一批次共N个部件;以备件替换故障单元或老化单元的方式,在T1时刻对这N个部件进行预防性维修工作;维修结束后,这N个部件工作到T2时刻完好数量n大于M的概率记为P(n>M),所述概率用于评估预防性维修备件方案的维修效果,在本实施例中称为达标概率;P(n>M)的下限记为P1,P1是对方案的达标概率指标要求;那么仅在满足P(n>M)≥P1时,预防性维修备件方案视为合格。Specifically, the components are composed of units described in the dyN item, and the life distribution law and unit price dyM i of each unit are known, 1≤i≤dyN; the current maintenance time is T1; there are currently a total of N components in the same batch; In the way of replacing the faulty unit or aging unit with spare parts, preventive maintenance work is carried out on these N components at time T1; after the maintenance, the probability that the N components work until the time T2 is intact and the number n is greater than M is recorded as P(n> M), the probability is used to evaluate the maintenance effect of the preventive maintenance spare parts plan, which is called the probability of reaching the standard in this embodiment; the lower limit of P (n>M) is recorded as P1, and P1 is the requirement of the probability of reaching the standard for the plan; Then only when P(n>M)≥P1 is satisfied, the preventive maintenance spare parts plan is considered qualified.
本实施例公开一种预防性维修备件方案优化方法,用于为具有dyN单元的上述部件构建合格并且具有高性价比的预防性维修备件方案。This embodiment discloses a method for optimizing a preventive maintenance spare parts plan, which is used to construct a qualified and cost-effective preventive maintenance spare parts plan for the above-mentioned components with dyN units.
请参照图1,本实施例的方法具有如下步骤。Please refer to FIG. 1 , the method of this embodiment has the following steps.
S100、预防性维修前根据所有单元对部件进行初始状态检测及归类。S100 , before the preventive maintenance, perform initial state detection and classification of components according to all units.
S110、通过具有dyN项的数组dyFlag来描述部件及其所有单元。S110. Describe the component and all its units through an array dyFlag with dyN items.
其中,dyFlagi描述部件中第i项单元;部件中第i项单元的状态是完好时,dyFlagi=1;当部件中第i项单元的状态是失效时,dyFlagi=0。Among them, dyFlag i describes the i-th unit in the component; when the status of the i-th unit in the component is intact, dyFlag i =1; when the status of the i-th unit in the component is failure, dyFlag i =0.
S120、将dyN项单元状态均相同的部件视为具有相同的初始状态并且归为同一部件类别,再用类别序号j标记不同的部件类别。S120. Deem the components with the same unit state of dyN items as having the same initial state and classify them into the same component category, and mark different component categories with the category number j.
通过矩阵bjState来根据单元的初始状态描述部件的归类结果;bjState中的第j行向量bjState(j,:)以数据结构描述为[dyFlag nFlagj],用于描述对部件进行初始状态检查和归类的结果,即:The matrix bjState is used to describe the classification results of the components according to the initial state of the unit; the j-th row vector bjState(j,:) in bjState is described as [dyFlag nFlag j ] in the data structure, which is used to describe the initial state check and The results of the classification, namely:
bjState(j,:)=[dyFlagj1 dyFlagj2 … dyFlagjdyN nFlagj],nFlagj描述第j类部件的数量。bjState(j,:)=[dyFlag j1 dyFlag j2 ... dyFlag jdyN nFlag j ], nFlag j describes the number of jth type components.
本实施例在面向一个以上的部件时,对相同类别的部件,采用相同的维修方案,即:如果需要更换部件中某一项单元,则相同类别中的所有部件一致性的更换所述单元。In this embodiment, when facing more than one component, the same maintenance scheme is adopted for components of the same category, that is, if a certain unit in the component needs to be replaced, all components in the same category will replace the unit consistently.
S200、根据每一类初始状态的部件,获取所述部件所在类别的一系列预防性维修部件的备件方案。S200. Acquire a series of spare parts solutions for preventive maintenance components of the category of the component according to the components in each category of initial state.
S210、获取类别序号j=1的备件方案。S210. Acquire a spare parts solution with category number j=1.
S220、通过数组Ns描述类别序号j=1的预防性维修部件的备件方案;S220. Describe the spare parts scheme of the preventive maintenance component with category number j=1 through the array Ns;
其中,Ns=[Ns1 Ns2 … NsdyN],Nsi是第i项单元的备件数量,1≤i≤dyN; Among them, Ns=[Ns 1 Ns 2 ... Ns dyN ], Ns i is the number of spare parts of unit i, 1≤i≤dyN;
初始化方案序号j2=0。The serial number of the initialization scheme j2=0.
S230、对上述类别序号j=1的备件方案Ns,调用部件备件方案评估模块,评估上述备件方案Ns的维修效果,并且记录评估结果为bjP。S230. For the spare part scheme Ns whose category number j=1, call the component spare part scheme evaluation module to evaluate the maintenance effect of the spare part scheme Ns, and record the evaluation result as bjP.
S240、更新矩阵plan。S240, updating the matrix plan.
j2=j2+1。j2=j2+1.
费用 cost
配置矩阵的第j2行向量,plan(j2,:)=[j2 bjP Mnow Ns]。The j2th row vector of the configuration matrix, plan(j2,:)=[j2 bjP Mnow Ns].
S250、判断即Nsi是否全为1;是则进入S260,否则生成下一备件方案,进入S251。S250, judge That is, whether Ns i are all 1s; if yes, go to S260; otherwise, generate the next spare parts plan and go to S251.
S251、Nsi不全为1,那么取候选序号k=1。S251, Ns i are not all 1, then take the candidate sequence number k=1.
S252、生成候选方案Nt;其中, S252. Generate a candidate solution Nt; wherein,
S253、根据候选方案Nt,调用部件备件方案评估模块,评估候选方案Nt的维修效果,评估结果记为bjPt,边际效费比 S253. According to the candidate plan Nt, call the parts and spare parts plan evaluation module to evaluate the maintenance effect of the candidate plan Nt, and record the evaluation result as bjPt, the marginal cost-benefit ratio
S254、k=k+1;如果k≤dyN,则返回S252,否则进入到S255。S254, k=k+1; if k≤dyN, then return to S252, otherwise go to S255.
S255、在历遍所有小于或等于dyN的k后,在所有p2mk,1≤k≤dyN中找到最大值,并且记录最大值对应的候选序号Im;再更新Ns,用于使NsIm=nFlagj,返回S230。S255. After traversing all k less than or equal to dyN, find the maximum value among all p2m k , 1≤k≤dyN, and record the candidate serial number Im corresponding to the maximum value; then update Ns to make Ns Im = nFlag j , return to S230.
S260、保存plan,更新planNj和矩阵planAll。S260. Save the plan, and update planN j and the matrix planAll.
取planNj=j2,planNj实际上是记录有状态序号为j的部件的预防性维修备件方案数量;Take planN j = j2, planN j actually records the number of preventive maintenance spare parts for the component with state number j;
把矩阵plan置于矩阵planAll以第一行及第(j-1)(3+dyN)+1列为起点的区域中,或者视为从矩阵plan是矩阵planAll中截取的区域,即:planAll(1:j2,iy1:iy2)=plan;Place the matrix planAll in the area starting from the first row and the (j-1)(3+dyN)+1 column of the matrix planAll, or as the area intercepted from the matrix planAll, that is: planAll( 1:j2, iy1:iy2) = plan;
其中,iy1=(j-1)(3+dyN)+1,iy2=j(3+dyN)。Wherein, iy1=(j-1)(3+dyN)+1, iy2=j(3+dyN).
S270、不同类别的初始状态视为有N1个,N1为正整数;j=j+1,如果j≤N1则转S220,否则转S300。S270. Assuming that there are N1 initial states of different categories, N1 is a positive integer; j=j+1, if j≤N1, go to S220, otherwise go to S300.
S300、利用planAll,组合所有类别的备件方案得到一系列的总体备件方案。S300, using planAll to combine all types of spare parts plans to obtain a series of overall spare parts plans.
S310、初始化描述总体备件方案的数组planID,planIDj=1,1≤j≤N1;其中第j项planIDj是第j类初始状态部件的部件备件方案序号,即:初始化总体备件方案 S310. Initialize the array planID describing the overall spare parts plan, planID j = 1, 1≤j≤N1; wherein the jth item planID j is the component spare part plan serial number of the jth type of initial state component, that is: initialize the overall spare part plan
初始化各类部件优化标志bjFj=1,1≤j≤N1。Initialize various component optimization flags bjF j =1, 1≤j≤N1.
初始化总体方案序号i2=0。Initialize the overall scheme number i2=0.
S320、针对总体备件方案planID,调用总体备件方案评估模块,得到的完好部件达标概率记为Pm,备件费用记为Mm,保存结果到矩阵result:S320. For the overall spare parts plan planID, call the overall spare parts plan evaluation module, mark the obtained intact parts compliance probability as Pm, mark the spare parts cost as Mm, and save the result to the matrix result:
i2=i2+1,result的第i2行向量result(i2,:)=[Mm Pm planID];i2=i2+1, the i2th row of result vector result(i2,:)=[Mm Pm planID];
S330、优化产生下一个总体备件方案S330. Optimizing and generating the next overall spare parts plan
S331、如果是则进入S332;否则进入S400。S331. If If yes, enter S332; otherwise, enter S400.
S332、取部件类别序号j=1。S332. Get the part category number j=1.
S333、取IDt=planID,IDtj=IDtj+1。S333. Get IDt=planID, IDt j =IDt j +1.
S334、如果IDtj>planNj,则有取bjFj=0,p2mj=0。S334. If IDt j >planN j , bjF j =0, p2m j =0.
如果IDtj≤planNj,那么针对总体备件方案IDt,调用总体备件方案评估模块,得到的完好部件达标概率记为Ptj,备件费用记为Mtj,取边际效费比 If IDt j ≤ planN j , then for the overall spare parts plan IDt, the overall spare parts plan evaluation module is called, and the obtained intact parts compliance probability is marked as Pt j , and the cost of spare parts is marked as Mt j , and the marginal benefit-cost ratio is taken
S335、j=j+1,如果j≤N1;则进入S333,否则进入S336。S335, j=j+1, if j≤N1; then go to S333, otherwise go to S336.
S336、在所有p2mj,1≤j≤N1中找到最大值,记其序号为Im;S336. Find the maximum value among all p2m j , 1≤j≤N1, and record its serial number as Im;
如果是则取planIDIm=planIDIm+1,Pm=PtIm,Mm=MtIm,保存结果到矩阵result:取i2=i2+1,取result的第i2行向量result(i2,:)=[Mm Pm planID]后转S331;if If yes, take planID Im = planID Im +1, Pm=Pt Im , Mm=Mt Im , save the result to the matrix result: take i2=i2+1, take the i2th row vector of result result(i2,:)=[Mm Pm planID] then transfer to S331;
如果则进入S400。if Then enter S400.
S400、利用result绘制效费曲线并且在显示屏显示,所述效费曲线的X轴为总体备件方案的费用,Y轴为达标概率Pm=P(n>M)。利用所述曲线可从中查询得到满足Pm≥P1要求的、备件费用最少的总体备件方案以及对应的部件备件方案。S400. Use the result to draw an efficiency curve and display it on the display screen. The X-axis of the efficiency curve is the cost of the overall spare parts solution, and the Y-axis is the compliance probability Pm=P (n>M). Using the curve, the overall spare parts scheme and the corresponding component spare parts scheme that meet the requirement of Pm≥P1 and have the least spare parts cost can be obtained from the query.
显示屏可用于显示由用户输入的信息或提供给用户的信息以及电子终端安装的各种应用。显示屏可包括显示面板,可选的,可以采用液晶显示器(Liquid、Crystal、Display,LCD)、有机发光二极管(Organic、Light-Emitting、Diode,OLED)等形式来配置显示面板。进一步的,触控面板可覆盖显示面板,当触控面板检测到在其上或附近的触摸操作后,传送给处理器以确定触摸事件的类型,随后处理器根据触摸事件的类型在显示面板上提供相应的视觉输出。The display screen may be used to display information input by or provided to the user and various applications installed in the electronic terminal. The display screen may include a display panel, and optionally, the display panel may be configured in the form of a liquid crystal display (Liquid, Crystal, Display, LCD), an organic light-emitting diode (Organic, Light-Emitting, Diode, OLED), or the like. Further, the touch panel can cover the display panel. When the touch panel detects a touch operation on or near it, it will be sent to the processor to determine the type of the touch event, and then the processor will display the touch event on the display panel according to the type of the touch event. Provide corresponding visual output.
优选的,在S230及S253中提及的部件备件方案评估模块,用于评估备件方案Ns及候选方案Nt的维修效果,具体以评估备件方案Ns的维修效果,示例如下。Preferably, the component spare part solution evaluation module mentioned in S230 and S253 is used to evaluate the maintenance effect of the spare part solution Ns and the candidate solution Nt, specifically to evaluate the maintenance effect of the spare part solution Ns, examples are as follows.
取式中; Pick in the formula;
dyPi是第i项单元在T2时刻的可靠度。dyP i is the reliability of the i-th unit at time T2.
常见寿命分布类型的单元可靠度计算式如下:The unit reliability calculation formula for common life distribution types is as follows:
如果第i项单元的寿命服从伽玛分布Ga(α,b),则有If the lifetime of the i-th unit obeys the Gamma distribution Ga(α,b), then there is
如果第i项单元的寿命服从对数正态分布LN(μ,σ2),则有If the lifetime of the i-th unit obeys the lognormal distribution LN(μ,σ 2 ), then
如果第i项单元的寿命服从正态分布N(μ,σ2),则有If the lifetime of the i-th unit obeys the normal distribution N(μ,σ 2 ), then
如果第i项单元的寿命服从威布尔分布W(α,b),则有If the life of the i-th unit obeys the Weibull distribution W(α,b), then there is
进一步的,在本实施例中如果第i项单元的寿命服从指数分布Exp(μ),则有且p1=p0。由于指数分布具有“剩余寿命等于寿命”的特性;那么本实施例的部件备件方案评估模块不对寿命服从指数分布Exp(μ)的第i项单元的预防性维修备件问题进行处理,而是本实施例在遭遇第i项单元的寿命服从指数分布Exp(μ)时,仅直接的更换失效单元或不更换未失效单元。Further, in this embodiment, if the lifetime of the i-th unit obeys the exponential distribution Exp(μ), then there is And p1=p0. Because the exponential distribution has the characteristic of "the remaining life is equal to the life"; then the parts and spare parts program evaluation module of this embodiment does not process the preventive maintenance spare parts of the i-th unit whose life obeys the exponential distribution Exp(μ), but this implementation For example, when the lifetime of the i-th unit obeys the exponential distribution Exp(μ), only the failed unit is directly replaced or the non-failed unit is not replaced.
优选的,本实施例在S320及S334中提及的总体备件方案评估模块,用于获取完好部件的达标概率及备件费用;具体以获取达标概率Pm及备件费用Mm的步骤示例如下。Preferably, the overall spare parts program evaluation module mentioned in S320 and S334 in this embodiment is used to obtain the compliance probability and spare parts cost of intact components; the specific steps for obtaining the compliance probability Pm and spare parts cost Mm are as follows.
S321、初始化类别序号j=1,备件费用Mt=0。S321. Initialize the category number j=1, and spare part cost Mt=0.
S322、从planAll中取出第j类初始状态部件的部件备件方案序号j2=planIDj的方案相关信息:部件可靠度bjP和备件费用Mnow;S322. Take out from planAll the spare parts plan serial number j2=planID j related information of the spare parts plan of the jth type of initial state parts: part reliability bjP and spare parts cost Mnow;
取Mt=Mt+Mnow;Take Mt=Mt+Mnow;
S323、取x1为从0~nFlagj的递增数列,步长为1,遍历计算x1k对应的概率1≤k≤1+nFlagj,得到向量p1;S323. Take x1 as an increasing sequence from 0 to nFlag j , with a step size of 1, and iteratively calculate the probability corresponding to x1 k 1≤k≤1+nFlag j , get the vector p1;
S324、如果j>1则计算p1和p2的卷积,并把结果赋给p2,即:p2=p1*p2,本实施例的“*”用于指出卷积计算;S324. If j>1, calculate the convolution of p1 and p2, and assign the result to p2, that is: p2=p1*p2, "*" in this embodiment is used to indicate convolution calculation;
否则,取p2=p1。Otherwise, take p2=p1.
S325、取j=j+1,如果j≤N1转S322,否则转S326。S325. Take j=j+1, if j≤N1 go to S322, otherwise go to S326.
S326、取总体备件方案planID的达标概率总体备件方案planID的备件费用Mm=Mt。S326. Obtain the probability of reaching the standard of the overall spare parts plan planID The spare parts cost Mm=Mt of the overall spare parts plan planID.
进一步的,本实施例的方法或装置在获取方案后,另提供以下仿真模型,用于模拟备件方案Ns对任意部件完成预防性维修后的保障效果。Further, the method or device of this embodiment further provides the following simulation model after obtaining the scheme, which is used to simulate the guarantee effect of the spare parts scheme Ns on any component after the preventive maintenance is completed.
S100、取单元序号i=1。S100. Get the unit serial number i=1.
S200、产生随机数sT,sT服从单元的寿命分布规律;S200. Generate a random number sT, and sT obeys the life distribution law of the unit;
取simTi用于模拟完成预防性维修后该单元的寿命。Pick simT i is used to simulate the life of the unit after preventive maintenance has been completed.
S300、i=i+1,如果i≤dyN则转S200,否则转S400。S300, i=i+1, if i≤dyN, go to S200, otherwise go to S400.
S400、从所有simTi,1≤i≤dyN中找到最小值,记为Tm。S400. Find the minimum value from all simT i , 1≤i≤dyN, and denote it as Tm.
S500、如果Tm>T2,则该部件在T2时刻状态为完好,记状态值djF=1;否则,记djF=0。S500. If Tm>T2, the component is in good condition at T2, and record the state value djF=1; otherwise, record djF=0.
在模拟所有部件的状态值后,所有状态值的累加结果即为预防性维修结束后在T2时刻完好部件的数量n。After simulating the status values of all components, the cumulative result of all status values is the number n of intact components at time T2 after the preventive maintenance ends.
在基于上述仿真模型进行大量仿真后,统计n>M的频率,即是达标概率P(n>M)的仿真结果。After a large number of simulations based on the above simulation model, the frequency of n>M is counted, which is the simulation result of the probability of reaching the standard P (n>M).
请参考图2,本实施例公开一种预防性维修备件方案构建装置。Please refer to FIG. 2 , this embodiment discloses a device for constructing a preventive maintenance spare parts plan.
所述装置包括分类模块、备件模块、组合模块及选择模块。The device includes a classification module, a spare parts module, a combination module and a selection module.
其中分类模块用于归类具有相同初始状态的至少一个部件在同一部件类别。备件模块用于获取每个所述部件类别中的至少一个备件方案;组合模块组合每个所述部件类别中的任一所述备件方案为至少一个总体备件方案,以及评估所述总体备件方案的达标概率;选择模块选择所述达标概率符合预置条件的所述总体备件方案为所述预防性维修备件方案。Wherein the classification module is used to classify at least one component with the same initial state in the same component category. The spare parts module is used to obtain at least one spare parts solution in each of the parts categories; the combination module combines any one of the spare parts solutions in each of the parts categories into at least one overall spare parts solution, and evaluates the overall spare parts solution Probability of reaching the standard; the selection module selects the overall spare parts plan whose probability of reaching the standard meets the preset condition as the preventive maintenance spare parts plan.
本实施例通过以下示例说明,预防性维修备件方案优化方法。This embodiment uses the following example to illustrate the method for optimizing the preventive maintenance spare parts plan.
某部件由4项单元组成,每项单元的寿命分布规律见表1。仓库中现有同批次的所述部件共18套,在第T1年对所有部件进行状态检查,检查结果见表2,完成对所有部件的预防性维修。预防性维修结束后,在第T2年时,完好部件数量n大于M的概率记为P(n>M)。现已知T1=4、T2=8及M=14。A component is composed of 4 units, and the life distribution of each unit is shown in Table 1. There are a total of 18 sets of the same batch of parts in the warehouse. In the first year of T1, the state inspection of all parts is carried out. The inspection results are shown in Table 2, and the preventive maintenance of all parts is completed. After the preventive maintenance is over, the probability that the number n of intact parts is greater than M at year T2 is recorded as P(n>M). It is now known that T1=4, T2=8 and M=14.
按照上述步骤制定备件方案,并绘制效费曲线。如果要求P(n>M)不小于0.85,从中找出满足要求、备件经费最少的备件方案。Follow the above steps to develop a spare parts plan and draw an efficiency curve. If it is required that P(n>M) is not less than 0.85, find out the spare parts plan that meets the requirements and has the least spare parts expenditure.
表1、各单元的寿命分布规律Table 1. Life distribution of each unit
表2、预防性维修前部件状态检查结果Table 2. Result of component status inspection before preventive maintenance
St100、部件预防性维修前,部件的初始状态检查和归类结果如表2;St100, before preventive maintenance of components, the results of initial state inspection and classification of components are shown in Table 2;
St200、针对每一类初始状态的部件,优化得到各类部件的一系列预防性维修部件备件方案。St200, for each type of initial state parts, optimize a series of spare parts plans for preventive maintenance of various parts.
对于部件类别1,经计算,其部件备件方案结果如表3。For component category 1, after calculation, the results of the component spare parts scheme are shown in Table 3.
表3、部件类别1Table 3. Component category 1
对于部件类别2,经计算,其部件备件方案结果如表4。For component category 2, after calculation, the results of the component spare parts scheme are shown in Table 4.
表4、部件类别2Table 4. Component category 2
对于部件类别3,经计算,其部件备件方案结果如表5。For component category 3, after calculation, the results of the component spare parts scheme are shown in Table 5.
表5、部件类别3Table 5. Component category 3
St300、利用上述结果优化组合各类部件的备件方案得到一系列的总体备件方案。St300, using the above results to optimize the combination of spare parts schemes of various components to obtain a series of overall spare parts schemes.
St310、初始化总体备件方案planID=[1 1 1],初始化各类部件优化标志bjF=[11 1],初始化总体方案序号i2=0。St310. Initialize the overall spare parts plan planID=[1 1 1], initialize various component optimization flags bjF=[11 1], initialize the overall plan number i2=0.
St320、针对总体备件方案planID,调用总体备件方案评估模块,得到的完好部件达标概率Pm=0.6177,备件费用Mm=607.6,保存结果到矩阵result:取result(1,:)=[MmPm planID]。St320. For the overall spare parts plan planID, call the overall spare parts plan evaluation module, obtain the qualified probability of intact parts Pm=0.6177, spare parts cost Mm=607.6, save the result to the matrix result: take result(1,:)=[MmPm planID].
St330、优化产生下一个总体备件方案,多次优化后,result最终结果如表6所示。St330, optimize to generate the next overall spare parts plan, after multiple optimizations, the final result is shown in Table 6.
表6、总体备件方案结果Table 6. Overall Spare Parts Program Results
St400、终止计算;请参考图3,图3中同时描述有通过本实施例提供的仿真模型进行仿真获取对总体备件方案的达标概率进行仿真获取的仿真结果,以及通过本实施例的方法或装置对总体备件方案的达标概率进行评估获取的评估结果。图3中明显示出达标概率的仿真结果及评估结果误差较小,满足工程要求。本实施例的方法或装置能够实现对备件方案的优化。St400, the calculation is terminated; please refer to Fig. 3, and Fig. 3 also describes the simulation results obtained by simulating the probability of reaching the standard of the overall spare parts scheme through the simulation model provided by this embodiment, and the method or device of this embodiment The evaluation result obtained by evaluating the compliance probability of the overall spare parts scheme. Figure 3 clearly shows that the error of the simulation results and evaluation results of the probability of reaching the standard is small, which meets the engineering requirements. The method or device of this embodiment can realize the optimization of the spare parts solution.
从以上结果可知:第6号总体备件方案的达标概率P(n>M)=0.885,满足P(n>M)不小于0.85的要求,其备件费用为1429,各类部件的备件方案序号为3、2、3,此时:对于第1类部件采取第3号部件备件方案,各单元的备件数量分别为7、0、7、0;对于第2类部件采取第2号部件备件方案,各单元的备件数量分别为6、0、6、0;对于第3类部件采取第3号部件备件方案,各单元的备件数量分别为5、5、5、5。可采用第6号总体备件方案作为最终的预防性维修备件方案。From the above results, it can be seen that the probability of reaching the standard of the No. 6 overall spare parts plan is P(n>M)=0.885, which meets the requirement that P(n>M) is not less than 0.85, and the cost of spare parts is 1429. 3, 2, 3, at this time: for the first category of components, the No. 3 component spare parts plan is adopted, and the number of spare parts of each unit is 7, 0, 7, 0 respectively; for the second category of components, the No. 2 component spare parts plan is adopted, The number of spare parts for each unit is 6, 0, 6, 0 respectively; for the third category of parts, the No. 3 spare parts plan is adopted, and the number of spare parts for each unit is 5, 5, 5, 5 respectively. General Spare Parts Program No. 6 may be used as the final preventive maintenance spare parts program.
以上所述仅为本发明的优选实施例而已,并不用于限制本发明,对于本领域的技术人员来说,本发明可以有各种更改和变化。凡在本发明的精神和原则之内,所作的任何修改、等同替换、改进等,均应包含在本发明的保护范围之内。The above descriptions are only preferred embodiments of the present invention, and are not intended to limit the present invention. For those skilled in the art, the present invention may have various modifications and changes. Any modifications, equivalent replacements, improvements, etc. made within the spirit and principles of the present invention shall be included within the protection scope of the present invention.
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