CN104301868A - High-precision indoor positioning method based on frame round-trip-time and time-of-arrival ranging technology - Google Patents
High-precision indoor positioning method based on frame round-trip-time and time-of-arrival ranging technology Download PDFInfo
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Abstract
本发明提供了一种基于帧往返和到达时间测距技术的高精度室内定位方法,通过采用TOA差分测量方法,提供了一种满足移动终端设备室内高精度定位要求的系统方案,基于帧往返的测量信息,通过嵌入帧传输的时间信息,对时间信息采用差分测量方法来减少帧处理时延误差,由于采用了基于帧往返和到达时间测距技术的高精度室内定位方法,除了达到传统室内定位的功能外,帧往返和到达时间测距技术有效解决了时间同步问题,而测距运用差分测量方法,消除了节点时钟与标准时钟的相位误差和频率误差。
The present invention provides a high-precision indoor positioning method based on frame round-trip and time-of-arrival ranging technology. By using the TOA differential measurement method, a system solution that meets the indoor high-precision positioning requirements of mobile terminal equipment is provided. Based on frame round-trip Measurement information, by embedding the time information of frame transmission, adopts differential measurement method for time information to reduce frame processing delay error, due to the use of high-precision indoor positioning method based on frame round-trip and arrival time ranging technology, in addition to achieving traditional indoor positioning In addition to the functions, the frame round-trip and arrival time ranging technology effectively solves the time synchronization problem, and the ranging uses the differential measurement method to eliminate the phase error and frequency error between the node clock and the standard clock.
Description
技术领域technical field
本发明涉及一种室内定位领域,尤其是一种高精度的室内定位方法。The invention relates to the field of indoor positioning, in particular to a high-precision indoor positioning method.
背景技术Background technique
随着信息技术的突飞猛进,人们对于获取信息的需求层出不穷,尤其对空间位置信息的感知需求日益增加。在户外方面,卫星技术的成熟促使全球定位系统(GlobalPositioning System,GPS)技术的全面发展。由于GPS具有全天候、高精度、自动测量等特点,在军事、交通、测绘及人们日常生活等各方面均得到广泛应用。GPS技术应用的首要条件即对空通视条件良好,对于室内定位导航就显得鞭长莫及。于是针对室内这个特殊环境必须寻求其他技术途径。With the rapid development of information technology, people's demand for information is emerging in an endless stream, especially the demand for the perception of spatial location information is increasing. In the field of outdoor, the maturity of satellite technology promotes the comprehensive development of Global Positioning System (Global Positioning System, GPS) technology. Since GPS has the characteristics of all-weather, high precision, and automatic measurement, it is widely used in military affairs, transportation, surveying and mapping, and people's daily life. The primary condition for the application of GPS technology is a good air-to-air communication condition, which is beyond reach for indoor positioning and navigation. Therefore, other technical approaches must be sought for the special indoor environment.
目前,超声波技术、射频识别技术、红外线技术、超宽带技术、蓝牙技术等室内定位虽然可以达到较高的定位精度,但是需要大量的传感器以及额外的硬件设备支持,实际应用中具有较大的局限性。随着IEEE802.11无线技术的成熟,WIFI在世界各地的普及,其覆盖面越来越广,更是成为智能手机、平板电脑等通讯设备的标配,并且很多区域如企业内部、机场、学校、仓库、医院等都提供WIFI支持,基于WIFI的室内定位技术应运而生。较之现行的定位技术,WIFI定位可依赖现有的网络,不需要额外的硬件设备,使用成本低。然而,由于多径信号和小尺度衰落等干扰因素的存在,往往导致基于室内传输模型的定位精度变得难以达到要求。At present, although indoor positioning such as ultrasonic technology, radio frequency identification technology, infrared technology, ultra-wideband technology, and Bluetooth technology can achieve high positioning accuracy, it requires a large number of sensors and additional hardware equipment support, which has great limitations in practical applications. sex. With the maturity of IEEE802.11 wireless technology and the popularization of WIFI all over the world, its coverage is getting wider and wider, and it has become the standard configuration of communication devices such as smartphones and tablet computers. Warehouses, hospitals, etc. all provide WIFI support, and WIFI-based indoor positioning technology emerges as the times require. Compared with the current positioning technology, WIFI positioning can rely on the existing network, does not require additional hardware devices, and has a low cost of use. However, due to the existence of interference factors such as multipath signals and small-scale fading, the positioning accuracy based on the indoor transmission model often becomes difficult to meet the requirements.
传统的室内定位方法中存在的位置特征信息指纹图数据库过于庞大,在线定位匹配过程中运算复杂度高,实时性差;并且随着室内空间坏境的变化,基于接收信号强度(RSS)技术的位置特征信息也在不断更改,一定程度上会影响匹配精确度;现有的基于到达时间(TOA,Time Of Arrival)技术的定位方法无法对时钟晶振误差以及节点上的传输时延进行较好处理,无法达到满足需求的室内高精度定位。The location feature information fingerprint database in the traditional indoor positioning method is too large, the calculation complexity is high in the online positioning matching process, and the real-time performance is poor; and with the change of the indoor space environment, the position based on received signal strength (RSS) technology The characteristic information is also constantly changing, which will affect the matching accuracy to a certain extent; the existing positioning method based on time of arrival (TOA, Time Of Arrival) technology cannot handle the clock crystal oscillator error and the transmission delay on the node well. Indoor high-precision positioning that meets the needs cannot be achieved.
发明内容Contents of the invention
为了克服现有技术的不足,本发明提出了一种基于帧往返(RTT,Round Trip Time)和到达时间(TOA,Time Of Arrival)测距技术的高精度室内定位方法,通过采用TOA差分测量方法,提供了一种满足移动终端设备室内高精度定位要求的系统方案。In order to overcome the deficiencies of the prior art, the present invention proposes a high-precision indoor positioning method based on frame round trip (RTT, Round Trip Time) and time of arrival (TOA, Time Of Arrival) ranging technology, by using the TOA differential measurement method , providing a system solution that meets the indoor high-precision positioning requirements of mobile terminal equipment.
本案基于帧往返的测量信息,通过嵌入帧传输的时间信息,对时间信息采用差分测量方法来减少帧处理时延误差。本发明解决其技术问题所采用的技术方案是:This case is based on the frame round-trip measurement information, by embedding the time information of the frame transmission, and adopting the differential measurement method for the time information to reduce the frame processing delay error. The technical solution adopted by the present invention to solve its technical problems is:
(1)RTT与TOA方法结合完成帧传输过程时间测量(1) The combination of RTT and TOA methods completes the time measurement of the frame transmission process
由移动终端,即MT(Mobile Terminal)向其无线信号有效范围内的AP(AccessPoint)发出无线信号,通过802.11无线协议中的握手机制来选定距离MT最近的至少3个AP来参与定位,AP选择完成后,MT向各选定AP发送问询帧,选定AP接收到MT的问询帧后,向MT返回应答帧,得到帧往返传输时间TRTT,MT与选定AP中任意一个AP的帧传输过程中,MT在t1时刻发出问询帧,选定AP在t2时刻收到问询帧,选定AP在t3时刻发出应答帧,MT在t4时刻收到应答帧,t1是MT发出的帧报文头出现在MT天线端口的时间;t3是选定AP发出的帧报文头出现在选定AP天线端口的时间;t2是传输帧报文头开始到达选定AP接收天线端口的时间;t4是传输帧报文头开始到达MT接收天线端口时间,其中t1和t4的记录由MT时钟来完成,t2和t3的记录由选定AP的时钟来完成;The mobile terminal, that is, MT (Mobile Terminal) sends a wireless signal to the AP (AccessPoint) within the effective range of its wireless signal, and selects at least three APs closest to the MT to participate in positioning through the handshake mechanism in the 802.11 wireless protocol. After the selection is completed, the MT sends an inquiry frame to each selected AP. After receiving the inquiry frame from the MT, the selected AP returns a response frame to the MT, and obtains the frame round-trip transmission time T RTT . The MT and any one of the selected APs In the process of frame transmission, the MT sends an inquiry frame at time t1 , the selected AP receives the inquiry frame at time t2 , the selected AP sends a response frame at time t3 , and the MT receives the response frame at time t4 , t 1 is the time when the frame header sent by the MT appears on the MT antenna port; t 3 is the time when the frame header sent by the selected AP appears on the selected AP antenna port; t 2 is the time when the transmission frame header begins to arrive The time of the selected AP receiving antenna port; t4 is the time when the header of the transmission frame arrives at the MT receiving antenna port, where the records of t1 and t4 are completed by the MT clock, and the records of t2 and t3 are completed by the selected AP’s clock to complete;
反之,如果由选定AP先发起测量,发送问询帧,整个传输过程MT与选定AP的角色可以互换;Conversely, if the selected AP first initiates the measurement and sends an inquiry frame, the roles of the MT and the selected AP can be interchanged during the entire transmission process;
(2)采用TOA差分测量方法消除或减小测量误差(2) Use TOA differential measurement method to eliminate or reduce measurement error
如步骤(1)所述,往返传输结束后,选定AP把其记录的时间点t2和t3传送给MT,由MT对时间数据进行计算得到帧往返传输时间TRTT如下:As described in step (1), after the round-trip transmission ends, the selected AP transmits its recorded time points t2 and t3 to the MT, and the MT calculates the time data to obtain the frame round-trip transmission time T RTT as follows:
TRTT=(t4-t1)-(t3-t2) (1)T RTT =(t 4 -t 1 )-(t 3 -t 2 ) (1)
TRTT为MT与选定AP上的时间差的差值,也就是差分测量,MT与选定AP间的距离D为传输速度乘以单向传输时间,即帧往返传输时间的一半,得到:T RTT is the difference between the time difference between the MT and the selected AP, that is, the differential measurement. The distance D between the MT and the selected AP is the transmission speed multiplied by the one-way transmission time, that is, half of the round-trip transmission time of the frame, to obtain:
其中C表示光速;where C is the speed of light;
(3)重复步骤(1)和(2)所述的方法,即可测量出MT与每个选定AP之间的距离,利用每个选定AP的坐标与MT间的距离为半径,建立至少3个以选定AP为圆心的圆方程,它们的公共交点就是MT的坐标,即可求解MT坐标,完成定位;(3) Repeat the method described in steps (1) and (2) to measure the distance between the MT and each selected AP, and use the distance between the coordinates of each selected AP and the MT as the radius to establish At least 3 circular equations with the selected AP as the center, their common intersection point is the coordinate of MT, then the MT coordinate can be solved to complete the positioning;
(4)在步骤(1)中,MT在t1=t’1+εMT时刻发出问询帧,选定AP在t2=t’2+εAP时刻收到问询帧,接着在t3=t’3+εAP’返回应答帧,MT在t4=t’4+εMT’收到应答帧,这里t1、t2、t3、t4为时间测量值,t’1、t’2、t’3、t’4为对应的标准时间,εMT、εAP、εAP’、εMT’为每个对应的测量值与标准时间之间的误差,误差又分为节点MT和AP的时钟与标准时钟的相位误差和频率误差,其中相位误差为节点MT和AP的时钟根据时间同步信号校准时间的时延,频率误差为两次时间同步之间节点时钟晶振频率漂移产生的累积误差,在步骤(1)的过程中,节点MT和AP完成时间同步的标准时间是t0,设Ti是从t0到测量时刻的时间间隔,经过时间Ti后节点MT和AP的标准时间为t’i=t0+Ti,(i=1,2…4),得到t’1=t0+T1为标准时钟所记时刻,节点MT所记时刻为:(4) In step (1), the MT sends out an inquiry frame at t 1 =t' 1 +ε MT , and the selected AP receives the inquiry frame at t 2 =t' 2 +ε AP , and then at t 3 =t' 3 +ε AP 'returns the response frame, MT receives the response frame at t 4 =t' 4 +ε MT ', where t 1 , t 2 , t 3 , t 4 are time measurement values, t' 1 , t' 2 , t' 3 , t' 4 are the corresponding standard time, ε MT , ε AP , ε AP ', ε MT ' are the errors between each corresponding measured value and the standard time, and the errors are further divided into The phase error and frequency error between the clocks of nodes MT and AP and the standard clock, where the phase error is the time delay of the clocks of nodes MT and AP according to the time synchronization signal calibration time, and the frequency error is the frequency drift of the node clock crystal oscillator between two time synchronizations In the process of step (1), the standard time for node MT and AP to complete time synchronization is t 0 , let T i be the time interval from t 0 to the measurement moment, after time T i passes between node MT and AP The standard time of the AP is t' i =t 0 +T i , (i=1,2...4), and t' 1 =t 0 +T 1 is the time recorded by the standard clock, and the time recorded by the node MT is:
t1=t'1+u+η(t1-u-t0) (3)t 1 =t' 1 +u+η(t 1 -ut 0 ) (3)
其中u为MT时钟与标准时钟的相位误差,η为时钟自身晶振频率漂移系数,则η(t1-u-t0)为节点从自己的测量时间(t0+u)时刻到t1时刻的晶振频率漂移的累计误差,化简后得:Where u is the phase error between the MT clock and the standard clock, η is the frequency drift coefficient of the clock’s own crystal oscillator, then η(t 1 -ut 0 ) is the crystal oscillator of the node from its own measurement time (t 0 +u) to t 1 The cumulative error of frequency drift, after simplification, is:
则MT时钟收到应答帧t4时刻可表达为:Then the time when the MT clock receives the response frame t4 can be expressed as:
公式(5)减去公式(4)可得到:Subtract formula (4) from formula (5) to get:
其中t’4-t’1=t0+T4-(t0+T1)=T4-T1;Where t' 4 -t' 1 =t 0 +T 4 -(t 0 +T 1 )=T 4 -T 1 ;
据此,公式(6)中t4-t1为测量时间的时间差,t'4-t'1为标准时间的时间差,η(t'4-t'1)为误差,误差等于标准时间的时间差乘以时钟自身晶振频率漂移系数η,η为10-5数量级,η(t'4-t'1)作为误差部分,可以忽略不计,得到同一时钟的测量时间的时间差t4-t1等于其对应的标准时间的时间差t'4-t'1,使得公式(1)中的帧往返时间TRTT可以用标准时间的时间差计算得到,从而消除了误差,测量结果的精度提高,从而使得定位精度得到提高。Accordingly, t 4 -t 1 in the formula (6) is the time difference of the measurement time, t' 4 -t' 1 is the time difference of the standard time, η(t' 4 -t' 1 ) is the error, and the error is equal to the standard time The time difference is multiplied by the clock's own crystal oscillator frequency drift coefficient η, η is on the order of 10 -5 , η(t' 4 -t' 1 ) is used as the error part, which can be ignored, and the time difference t 4 -t 1 of the measurement time of the same clock is equal to The corresponding time difference t' 4 -t' 1 of the standard time makes the frame round-trip time T RTT in the formula (1) can be calculated by using the time difference of the standard time, thereby eliminating the error and improving the accuracy of the measurement results, so that the positioning Accuracy is improved.
本发明的有益效果是由于采用了基于帧往返和到达时间测距技术的高精度室内定位方法,除了达到传统室内定位的功能外,帧往返(RTT)和到达时间(TOA)测距技术有效解决了时间同步问题,而测距运用差分测量方法,消除了节点时钟与标准时钟的相位误差和频率误差。The beneficial effects of the present invention are due to the adoption of a high-precision indoor positioning method based on frame round-trip and time-of-arrival ranging technology, in addition to the traditional indoor positioning function, the frame round-trip (RTT) and time-of-arrival (TOA) ranging technology effectively solves the problem. The time synchronization problem is solved, and the distance measurement uses the differential measurement method to eliminate the phase error and frequency error between the node clock and the standard clock.
附图说明Description of drawings
图1是本发明室内定位的帧往返时间测量框图,其中MT在t1时刻发出问询帧,AP在t2时刻收到问询帧,接着在t3返回应答帧,MT在t4收到应答帧,MLME为MAC层管理实体。Fig. 1 is a block diagram of frame round-trip time measurement for indoor positioning of the present invention, wherein the MT sends out an inquiry frame at t1 , the AP receives the inquiry frame at t2 , then returns a response frame at t3 , and the MT receives it at t4 Response frame, MLME is the MAC layer management entity.
图2是室内定位的基本系统模型框图,图中,AP1,AP2,AP3,AP4分别为接入点,MTi(i=1,…n)为移动终端。Fig. 2 is a block diagram of a basic system model of indoor positioning. In the figure, AP 1 , AP 2 , AP 3 , and AP 4 are respectively access points, and MT i (i=1,...n) are mobile terminals.
具体实施方式Detailed ways
下面结合附图和实施例对本发明进一步说明。The present invention will be further described below in conjunction with the accompanying drawings and embodiments.
(1)RTT与TOA方法结合完成帧传输过程时间测量(1) The combination of RTT and TOA methods completes the time measurement of the frame transmission process
由移动终端,即MT(Mobile Terminal)向其无线信号有效范围内的AP(AccessPoint)发出无线信号,通过802.11无线协议中的握手机制来选定距离MT最近的至少3个AP来参与定位,AP选择完成后,MT向各选定AP发送问询帧,选定AP接收到MT的问询帧后,向MT返回应答帧,得到帧往返传输时间TRTT,MT与选定AP中任意一个AP的帧传输过程中,MT在t1时刻发出问询帧,选定AP在t2时刻收到问询帧,选定AP在t3时刻发出应答帧,MT在t4时刻收到应答帧,t1是MT发出的帧报文头出现在MT天线端口的时间;t3是选定AP发出的帧报文头出现在选定AP天线端口的时间;t2是传输帧报文头开始到达选定AP接收天线端口的时间;t4是传输帧报文头开始到达MT接收天线端口时间,其中t1和t4的记录由MT时钟来完成,t2和t3的记录由选定AP的时钟来完成;The mobile terminal, that is, MT (Mobile Terminal) sends a wireless signal to the AP (AccessPoint) within the effective range of its wireless signal, and selects at least three APs closest to the MT to participate in positioning through the handshake mechanism in the 802.11 wireless protocol. After the selection is completed, the MT sends an inquiry frame to each selected AP. After receiving the inquiry frame from the MT, the selected AP returns a response frame to the MT, and obtains the frame round-trip transmission time T RTT . The MT and any one of the selected APs In the process of frame transmission, the MT sends an inquiry frame at time t1 , the selected AP receives the inquiry frame at time t2 , the selected AP sends a response frame at time t3 , and the MT receives the response frame at time t4 , t 1 is the time when the frame header sent by the MT appears on the MT antenna port; t 3 is the time when the frame header sent by the selected AP appears on the selected AP antenna port; t 2 is the time when the transmission frame header begins to arrive The time of the selected AP receiving antenna port; t4 is the time when the header of the transmission frame arrives at the MT receiving antenna port, where the records of t1 and t4 are completed by the MT clock, and the records of t2 and t3 are completed by the selected AP’s clock to complete;
反之,如果由选定AP先发起测量,发送问询帧,整个传输过程MT与选定AP的角色可以互换;Conversely, if the selected AP first initiates the measurement and sends an inquiry frame, the roles of the MT and the selected AP can be interchanged during the entire transmission process;
(2)采用TOA差分测量方法消除或减小测量误差(2) Use TOA differential measurement method to eliminate or reduce measurement error
如步骤(1)所述,往返传输结束后,选定AP把其记录的时间点t2和t3传送给MT,由MT对时间数据进行计算得到帧往返传输时间TRTT如下:As described in step (1), after the round-trip transmission ends, the selected AP transmits its recorded time points t2 and t3 to the MT, and the MT calculates the time data to obtain the frame round-trip transmission time T RTT as follows:
TRTT=(t4-t1)-(t3-t2) (1)T RTT =(t 4 -t 1 )-(t 3 -t 2 ) (1)
TRTT为MT与选定AP上的时间差的差值,也就是差分测量,MT与选定AP间的距离D为传输速度乘以单向传输时间,即帧往返传输时间的一半,得到:T RTT is the difference between the time difference between the MT and the selected AP, that is, the differential measurement. The distance D between the MT and the selected AP is the transmission speed multiplied by the one-way transmission time, that is, half of the round-trip transmission time of the frame, to obtain:
其中C表示光速;where C is the speed of light;
(3)重复步骤(1)和(2)所述的方法,即可测量出MT与每个选定AP之间的距离,利用每个选定AP的坐标与MT间的距离为半径,建立至少3个以选定AP为圆心的圆方程,它们的公共交点就是MT的坐标,即可求解MT坐标,完成定位;(3) Repeat the method described in steps (1) and (2) to measure the distance between the MT and each selected AP, and use the distance between the coordinates of each selected AP and the MT as the radius to establish At least 3 circular equations with the selected AP as the center, their common intersection point is the coordinate of MT, then the MT coordinate can be solved to complete the positioning;
(4)在步骤(1)中,MT在t1=t’1+εMT时刻发出问询帧,选定AP在t2=t’2+εAP时刻收到问询帧,接着在t3=t’3+εAP’返回应答帧,MT在t4=t’4+εMT’收到应答帧,这里t1、t2、t3、t4为时间测量值,t’1、t’2、t’3、t’4为对应的标准时间,εMT、εAP、εAP’、εMT’为每个对应的测量值与标准时间之间的误差,误差又分为节点MT和AP的时钟与标准时钟的相位误差和频率误差,其中相位误差为节点MT和AP的时钟根据时间同步信号校准时间的时延,频率误差为两次时间同步之间节点时钟晶振频率漂移产生的累积误差,在步骤(1)的过程中,节点MT和AP完成时间同步的标准时间是t0,设Ti是从t0到测量时刻的时间间隔,经过时间Ti后节点MT和AP的标准时间为t’i=t0+Ti,(i=1,2…4),得到t’1=t0+T1为标准时钟所记时刻,节点MT所记时刻为:(4) In step (1), the MT sends out an inquiry frame at t 1 =t' 1 +ε MT , and the selected AP receives the inquiry frame at t 2 =t' 2 +ε AP , and then at t 3 =t' 3 +ε AP 'returns the response frame, MT receives the response frame at t 4 =t' 4 +ε MT ', where t 1 , t 2 , t 3 , t 4 are time measurement values, t' 1 , t' 2 , t' 3 , t' 4 are the corresponding standard time, ε MT , ε AP , ε AP ', ε MT ' are the errors between each corresponding measured value and the standard time, and the errors are further divided into The phase error and frequency error between the clocks of nodes MT and AP and the standard clock, where the phase error is the time delay of the clocks of nodes MT and AP according to the time synchronization signal calibration time, and the frequency error is the frequency drift of the node clock crystal oscillator between two time synchronizations The cumulative error generated, in the process of step (1), the standard time for the node MT and AP to complete time synchronization is t 0 , let T i be the time interval from t 0 to the measurement moment, after the time Ti elapses, the node MT and AP The standard time is t' i =t 0 +T i , (i=1,2...4), and t' 1 =t 0 +T 1 is the time recorded by the standard clock, and the time recorded by the node MT is:
t1=t'1+u+η(t1-u-t0) (3)t 1 =t' 1 +u+η(t 1 -ut 0 ) (3)
其中u为MT时钟与标准时钟的相位误差,η为时钟自身晶振频率漂移系数,则η(t1-u-t0)为节点从自己的测量时间(t0+u)时刻到t1时刻的晶振频率漂移的累计误差,化简后得:Where u is the phase error between the MT clock and the standard clock, η is the frequency drift coefficient of the clock’s own crystal oscillator, then η(t 1 -ut 0 ) is the crystal oscillator of the node from its own measurement time (t 0 +u) to t 1 The cumulative error of frequency drift, after simplification, is:
则MT时钟收到应答帧t4时刻可表达为:Then the time when the MT clock receives the response frame t4 can be expressed as:
公式(5)减去公式(4)可得到:Subtract formula (4) from formula (5) to get:
其中t’4-t’1=t0+T4-(t0+T1)=T4-T1;Where t' 4 -t' 1 =t 0 +T 4 -(t 0 +T 1 )=T 4 -T 1 ;
据此,公式(6)中t4-t1为测量时间的时间差,t'4-t'1为标准时间的时间差,η(t'4-t'1)为误差,误差等于标准时间的时间差乘以时钟自身晶振频率漂移系数η,η为10-5数量级,η(t'4-t'1)作为误差部分,可以忽略不计,得到同一时钟的测量时间的时间差t4-t1等于其对应的标准时间的时间差t'4-t'1,使得公式(1)中的帧往返时间TRTT可以用标准时间的时间差计算得到,从而消除了误差,测量结果的精度提高,从而使得定位精度得到提高。Accordingly, t 4 -t 1 in the formula (6) is the time difference of the measurement time, t' 4 -t' 1 is the time difference of the standard time, η(t' 4 -t' 1 ) is the error, and the error is equal to the standard time The time difference is multiplied by the clock's own crystal oscillator frequency drift coefficient η, η is on the order of 10 -5 , η(t' 4 -t' 1 ) is used as the error part, which can be ignored, and the time difference t 4 -t 1 of the measurement time of the same clock is equal to The corresponding time difference t' 4 -t' 1 of the standard time makes the frame round-trip time T RTT in the formula (1) can be calculated by using the time difference of the standard time, thereby eliminating the error and improving the accuracy of the measurement results, so that the positioning Accuracy is improved.
为了使本发明的上述目的、特征和优点能够更加明显易懂,下面以WIFI室内定位为例对本案作进一步详细的描述。显然,本处所描述的实施例仅是本发明结合WIFI信号阐述的一部分实施例。基于本发明所述方案,本领域普通技术人员在没有做出创造性劳动的前提下获得的实施例,都在本发明的保护范围之内。In order to make the above-mentioned purpose, features and advantages of the present invention more obvious and easy to understand, the following takes WIFI indoor positioning as an example to further describe this case in detail. Apparently, the embodiments described here are only part of the embodiments described in the present invention in conjunction with WIFI signals. Based on the solutions described in the present invention, the embodiments obtained by persons of ordinary skill in the art without making creative efforts are all within the protection scope of the present invention.
首先,移动终端(如手机、平板电脑、笔记本等)即MT选择定位时,应先接入到室内区域(如企业内部、机场、学校、仓库、医院等)的WIFI系统中。由MT向其WIFI信号有效范围的AP(路由器等无线设备)发出WIFI问询帧信号,通过802.11无线协议中的握手机制来选定距离MT最近的至少3个AP来参与定位过程,AP的选取原则是:根据AP对MT的应答先后顺序进行选取。AP选择完成后,MT向各AP发送问询帧,AP接收到MT的问询帧后,向MT返回应答帧,得到帧往返传输时间TRTT。以MT与任意的AP的帧传输过程为例,MT在t1时刻发出问询帧,AP在t2时刻收到问询帧,AP在t3时刻发出应答帧,MT在t4时刻收到应答帧(所有时刻均为帧报文头开始出现或开始到达MT和AP的天线端口的时间)。其中特别关注的是,各个时间点的记录都是由相应节点自身时钟完成的,帧往返时间测量框图如图1所示。First of all, when mobile terminals (such as mobile phones, tablet computers, notebooks, etc.) or MTs choose to locate, they should first be connected to the WIFI system in indoor areas (such as inside enterprises, airports, schools, warehouses, hospitals, etc.). The MT sends a WIFI inquiry frame signal to the AP (router and other wireless devices) within the effective range of its WIFI signal, and selects at least 3 APs closest to the MT to participate in the positioning process through the handshake mechanism in the 802.11 wireless protocol. The principle is: select according to the order in which the AP responds to the MT. After AP selection is completed, the MT sends an inquiry frame to each AP, and the AP returns a response frame to the MT after receiving the inquiry frame from the MT, and obtains the frame round-trip transmission time T RTT . Take the frame transmission process between MT and any AP as an example, MT sends an inquiry frame at time t1 , AP receives the inquiry frame at time t2 , AP sends a response frame at time t3 , and MT receives the response at time t4 Frame (all times are the time when the header of the frame begins to appear or arrives at the antenna ports of the MT and AP). Of special concern is that the recording of each time point is completed by the corresponding node's own clock, and the frame round-trip time measurement block diagram is shown in Figure 1.
帧往返传输结束后,AP把其记录的时间点t2和t3传送给MT,由MT对时间数据进行计算得到TRTT After the frame round-trip transmission is completed, the AP sends the recorded time points t2 and t3 to the MT, and the MT calculates the time data to obtain T RTT
TRTT=(t4-t1)-(t3-t2)T RTT =(t 4 -t 1 )-(t 3 -t 2 )
=[(t'4+εMT')-(t'1+εMT)]-[(t'3+εAP')-(t'2+εAP)] (7)=[(t' 4 +ε MT ')-(t' 1 +ε MT )]-[(t' 3 +ε AP ')-(t' 2 +ε AP )] (7)
=[(t'4-t'1)-(t'1-t'2)]+[(εMT'-εMT)-(εAP'-εAP)]=[(t' 4 -t' 1 )-(t' 1 -t' 2 )]+[(ε MT '-ε MT )-(ε AP '-ε AP )]
公式(7)中,[(t'4-t'1)-(t'3-t'2)]为帧的真实传输时间,[(εMT'-εMT)-(εAP'-εAP)]为帧的传输误差,εMT和εMT’为MT时钟测量的两个误差,它们的差值为η(t'4-t'1),因为(t'4-t'1)最大为10-6数量级,η为10-5数量级,所以此项的结果为10-11数量级,数量级过小,可以忽略不计;同样εAP和εAP’为AP时钟测量的两个误差,它们的差值为η(t'3-t'2),而t'3-t'2AP时钟从收到问询帧到发出应答帧的处理时间,是小于t'4-t'1的,η(t'3-t'2)也因为数量级过小忽略不计,因此,通过差分测量使得第二个中括号部分对结果的影响非常小,可忽略不计。则得到的TRTT结果就等于信号在两个AP之间传输所消耗的时间。In formula (7), [(t' 4 -t' 1 )-(t' 3 -t' 2 )] is the real transmission time of the frame, [(ε MT '-ε MT )-(ε AP '-ε AP )] is the transmission error of the frame, ε MT and ε MT ' are two errors measured by the MT clock, and their difference is η(t' 4 -t' 1 ), because (t' 4 -t' 1 ) The maximum is on the order of 10 -6 , and η is on the order of 10 -5 , so the result of this item is on the order of 10 -11 , which is too small to be ignored; similarly, ε AP and ε AP ' are two errors measured by the AP clock, and they The difference is η(t' 3 -t' 2 ), and the processing time of t' 3 -t' 2 AP clock from receiving the inquiry frame to sending out the response frame is less than t' 4 -t' 1 , η(t' 3 -t' 2 ) is also negligible because the order of magnitude is too small. Therefore, the influence of the second bracket part on the result is very small and negligible through differential measurement. Then the obtained T RTT result is equal to the time consumed by the signal transmission between the two APs.
由于WIFI的覆盖范围为100m,在MT与AP相距100m的情况下,最大的标准时间差为10-6数量级,则10-11数量级的时间对应于毫米级的距离,相对于室内定位1m的精度,完全可以忽略不计。Since the coverage of WIFI is 100m, when the distance between MT and AP is 100m, the maximum standard time difference is on the order of 10 -6 , and the time on the order of 10 -11 corresponds to the distance of millimeter level, relative to the accuracy of indoor positioning of 1m, completely negligible.
实际测量中,首先需要根据802.11协议使MT与参与定位的至少3个AP进行时间同步(现有的定位方法的时钟分辨率为1μs,根据802.11v协议的时钟分辨率为10ns,本发明设置MT与各AP的时钟分辨率皆为1ns),AP收到时间同步信号后需要时间u调整自己的时钟时间至标准时间,因此在仿真实验中,设定MT与各AP的时钟都与标准时钟有相位误差u,取u为[-5,-1]上的离散均匀分布且只能为整数,MT与AP自身晶振频率漂移系数η为[-5×10-5,5×10-5]上的均匀分布,其中负值表示晶振频率慢于标准时钟频率,正值表示晶振频率快于标准时钟频率。选取一个AP,MT每个测量点的位置均来自AP附近x∈[34,65],y∈[34,65]的区域,测量实验得到了传统TOA方法的测量时间与真实帧传输时间的绝对误差D1,误差均值为E[D1],均方误差MSE1=E[D1 2];对于差分测量方法,TRTT与真实帧传输时间的绝对误差为D2,误差均值为E[D2],均方误差MSE2=E[D2 2]。其中E[·]表示求取变量的期望。并定义P=MSE1/MSE2作为增益参考值。In the actual measurement, at first it is necessary to make the MT and at least 3 APs involved in positioning carry out time synchronization according to the 802.11 protocol (the clock resolution of the existing positioning method is 1 μs, and the clock resolution according to the 802.11v protocol is 10 ns, the present invention sets the MT The clock resolution of each AP is 1 ns), and it takes time for the AP to adjust its clock time to the standard time after receiving the time synchronization signal. Therefore, in the simulation experiment, the clocks of the MT and each AP are set to be consistent with the standard clock Phase error u, take u as a discrete uniform distribution on [-5, -1] and can only be an integer, MT and AP’s own crystal oscillator frequency drift coefficient η is [-5×10 -5 ,5×10 -5 ] A uniform distribution of , where a negative value indicates that the crystal oscillator frequency is slower than the standard clock frequency, and a positive value indicates that the crystal oscillator frequency is faster than the standard clock frequency. Select an AP, and the position of each measurement point of the MT comes from the area of x∈[34,65], y∈[34,65] near the AP. The measurement experiment obtained the absolute difference between the measurement time of the traditional TOA method and the real frame transmission time. Error D 1 , the mean value of the error is E[D 1 ], the mean square error MSE 1 =E[D 1 2 ]; for the differential measurement method, the absolute error between T RTT and the real frame transmission time is D 2 , and the mean value of the error is E[ D 2 ], mean square error MSE 2 =E[D 2 2 ]. Among them, E[·] represents the expectation of obtaining variables. And define P=MSE 1 /MSE 2 as the gain reference value.
实验一主要对面两种测量方式在T1=0(T1为从上次时间同步完成到MT开始发送问询帧的时间)的情况下,AP附近区域内的全部MT测量点对于时间同步误差的结果。表1显示了本次的全部测量结果:Experiment 1 mainly faces two measurement methods. In the case of T 1 = 0 (T 1 is the time from the completion of the last time synchronization to the time when the MT starts to send the inquiry frame), all MT measurement points in the vicinity of the AP have a relatively large impact on the time synchronization error the result of. Table 1 shows all the measurement results of this time:
表1 传统测量与差分测量误差结果对比Table 1 Comparison of error results between traditional measurement and differential measurement
实验结果说明了本发明的TOA差分测量方法大幅度减小了测量误差,提高了测量精度。Experimental results show that the TOA differential measurement method of the present invention greatly reduces measurement errors and improves measurement accuracy.
实验二中,MT与AP的时钟的参数u和η保持不变。主要对比两种测量方式在不同T1情况下,x∈[34,65],y∈[34,65]区域内的全部测量点的结果差异。对于传统TOA,其测量值:In Experiment 2, the parameters u and η of the MT and AP clocks remain unchanged. The difference between the results of all the measurement points in the x∈[34,65], y∈[34,65] area is mainly compared between the two measurement methods under different T 1 conditions. For traditional TOA, its measured value:
D1=t2-t1-Δ (11)D 1 =t 2 -t 1 -Δ (11)
其中Δ为MT到AP的帧传输时间,根据公式(10)和(11)可以看出绝对误差D1的值与T1的值有线性关系。Where Δ is the frame transmission time from the MT to the AP. According to formulas (10) and (11), it can be seen that the value of the absolute error D 1 has a linear relationship with the value of T 1 .
表2 T对于传统测量和差分测量误差结果对比Table 2 Comparison of T for traditional measurement and differential measurement error results
根据表2可以发现,传统TOA方法的误差和均方误差随着T1增加而线性变化,而TOA差分测量的误差和均方误差与T1的变化无关。因此差分测量有效的抑制了由晶振频率漂移造成的累积误差。According to Table 2, it can be found that the error and mean square error of the traditional TOA method change linearly with the increase of T1 , while the error and mean square error of TOA differential measurement have nothing to do with the change of T1 . Therefore, the differential measurement effectively suppresses the cumulative error caused by the frequency drift of the crystal oscillator.
MT与AP间的距离为传输速度乘以单向传输的时间(帧往返传输时间的一半),即其中C表示光速,可采用上述同样的方法测量出MT与其它几个选定的AP之间的距离。在该模型中,通过选定的至少3个AP的坐标及其与MT的距离为半径,建立至少3个以AP为圆心的圆方程,它们的公共交点就是MT的坐标,即可求解MT坐标,完成定位,基本系统模型结构如图2所示。The distance between MT and AP is the transmission speed multiplied by the one-way transmission time (half of the frame round-trip transmission time), that is Where C represents the speed of light, and the distance between the MT and several other selected APs can be measured using the same method as above. In this model, by selecting the coordinates of at least 3 APs and their distance from MT as the radius, at least 3 circle equations with AP as the center are established, and their common intersection points are the coordinates of MT, and the MT coordinates can be solved , complete the positioning, and the basic system model structure is shown in Figure 2.
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