\[\int\frac{\operatorname{Ai}\left(z\right)\operatorname{Bi}\left(z\right)}{%
\left({\operatorname{Ai}}^{2}\left(z\right)+{\operatorname{Bi}}^{2}\left(z%
\right)\right)^{2}}\,\mathrm{d}z=\frac{\pi}{2}\frac{{\operatorname{Bi}}^{2}%
\left(z\right)}{{\operatorname{Ai}}^{2}\left(z\right)+{\operatorname{Bi}}^{2}%
\left(z\right)}.\]