\[{\frac{{\mathrm{d}}^{2}w}{{\mathrm{d}\zeta}^{2}}+\frac{1}{2}\left(\frac{1}{%
\zeta-e_{1}}+\frac{1}{\zeta-e_{2}}+\frac{1}{\zeta-e_{3}}\right)\frac{\mathrm{d%
}w}{\mathrm{d}\zeta}}+\frac{g-\nu(\nu+1)\zeta}{4(\zeta-e_{1})(\zeta-e_{2})(%
\zeta-e_{3})}w=0,\]