\[{\operatorname{Ms}^{(j)}_{2m+1}}\left(z,h\right)=(-1)^{m}\left(\operatorname{%
se}_{2m+1}\left(\tfrac{1}{2}\pi,h^{2}\right)\right)^{-1}\sum_{\ell=0}^{\infty}%
B_{2\ell+1}^{2m+1}(h^{2}){\cal C}_{2\ell+1}^{(j)}(2h\sinh z),\]