\[C^{(\mu)}_{n}\left(x\right)=\sum_{\ell=0}^{\left\lfloor n/2\right\rfloor}\frac%
{\lambda+n-2\ell}{\lambda}\frac{{\left(\mu\right)_{n-\ell}}}{{\left(\lambda+1%
\right)_{n-\ell}}}\frac{{\left(\mu-\lambda\right)_{\ell}}}{\ell!}C^{(\lambda)}%
_{n-2\ell}\left(x\right),\]