\[w_{2}(z)={\mathrm{e}}^{(1-a)\pi\mathrm{i}}\frac{\Gamma\left(2-c\right)\Gamma%
\left(c-b\right)}{\Gamma\left(a-c+1\right)\Gamma\left(c-a-b+1\right)}w_{4}(z)+%
\exp{\mathrm{e}}^{-a\pi\mathrm{i}}\frac{\Gamma\left(2-c\right)\Gamma\left(c-b%
\right)}{\Gamma\left(a-b+1\right)\Gamma\left(1-a\right)}w_{5}(z),\]