\[Q^{-m}_{\nu}\left(x\right)=(-1)^{m}\left(x^{2}-1\right)^{-m/2}\*\int_{x}^{%
\infty}\!\dots\!\int_{x}^{\infty}Q_{\nu}\left(x\right)\left(\!\,\mathrm{d}x%
\right)^{m}.\]