\[\boldsymbol{Q}^{\mu}_{\nu,s}\left(z\right)=e^{-s\mu\pi i}\boldsymbol{Q}^{\mu}_%
{\nu}\left(z\right)-\frac{\pi i\sin\left(s\mu\pi\right)}{\sin\left(\mu\pi%
\right)\Gamma\left(\nu-\mu+1\right)}P^{-\mu}_{\nu}\left(z\right),\]