take_mut
This crate provides (at this time) a single function, take().
take() allows for taking T out of a &mut T, doing anything with it including consuming it, and producing another T to put back in the &mut T.
During take(), if a panic occurs, the entire process will be exited, as there's no valid T to put back into the &mut T.
Contrast with std::mem::replace(), which allows for putting a different T into a &mut T, but requiring the new T to be available before being able to consume the old T.
Example
;
let mut foo = Foo;
take;